allcoding1_official

def solve(N: int, t: list) -> list: if all(t[k] <= t[k+1] for k in range(N - 1)): return [0, sum(t)] p = next(k for k in range(N - 1) if t[k] > t[k+1]) M = [0] * N M[N-1] = t[N-1] for i in range(N - 2, -1, -1): M[i] = min(t[i], M[i+1]) prefix_sum = [0] * (N + 1) for i in range(N): prefix_sum[i+1] = prefix_sum[i] + t[i] best = -1 for i in range(0, p + 2): if i > 0 and t[i-1] > M[i]: continue total = prefix_sum[i] + M[i] * (N - i) best = max(best, total) return [1, best]

#include <bits/stdc++.h> using namespace std; long long solve(int N, vector<int>& target) { long long total = 0; for (int i = 0; i < N; i++) total += target[i]; long long sumX = 0; long long carry = 0; for (int i = 0; i + 1 < N; i++) { long long cap = min((long long)target[i] - carry, (long long)target[i + 1]); if (cap < 0) cap = 0; sumX += cap; carry = cap; } return total - sumX; } int main() { ios_base::sync_with_stdio(false); cin.tie(NULL); int N; cin >> N; vector<int> target(N); for (int i = 0; i < N; i++) cin >> target[i]; auto result = solve(N, target); cout << result << endl; return 0; }

#include <bits/stdc++.h> using namespace std; long long solve(int N, vector<int>& target) { long long total = 0; for (int i = 0; i < N; i++) total += target[i]; long long sumX = 0; long long carry = 0; for (int i = 0; i + 1 < N; i++) { long long cap = min((long long)target[i] - carry, (long long)target[i + 1]); if (cap < 0) cap = 0; sumX += cap; carry = cap; } return total - sumX; } int main() { ios_base::sync_with_stdio(false); cin.tie(NULL); int N; cin >> N; vector<int> target(N); for (int i = 0; i < N; i++) cin >> target[i]; auto result = solve(N, target); cout << result << endl; return 0; }

#include <bits/stdc++.h> using namespace std; int solve(int N, int K, vector<vector<int>>& cost, vector<int>& fatigue) { const long long INF = 4e18; vector<vector<long long>> prev(K, vector<long long>(2, INF)); vector<vector<long long>> cur(K, vector<long long>(2, INF)); for (int c = 0; c < K; c++) prev[c][1] = cost[0][c]; for (int i = 1; i < N; i++) { for (int c = 0; c < K; c++) { cur[c][0] = cur[c][1] = INF; } for (int last = 0; last < K; last++) { for (int streak = 1; streak <= 2; streak++) { if (prev[last][streak - 1] == INF) continue; for (int now = 0; now < K; now++) { if (now == last) { if (streak == 2) continue; cur[now][1] = min( cur[now][1], prev[last][streak - 1] + cost[i][now] + fatigue[now] );

#include <bits/stdc++.h> using namespace std; const int MOD = 1000000007; int solve(int N) { vector<array<long long, 3>> dp(N + 1); // last = 0 -> 1 // last = 1 -> 3 // last = 2 -> 4 for (int s = 1; s <= N; s++) { if (s == 1) { dp[s][0] = 1; } else { long long ways = 0; if (s >= 1) { ways = (dp[s - 1][1] + dp[s - 1][2]) % MOD; } dp[s][0] = ways; } if (s == 3) { dp[s][1] = (dp[s][1] + 1) % MOD; } if (s > 3) { dp[s][1] = (dp[s - 3][0] + dp[s - 3][2]) % MOD; } if (s == 4) { dp[s][2] = (dp[s][2] + 1) % MOD; } if (s > 4) { dp[s][2] = (dp[s - 4][0] + dp[s - 4][1]) % MOD; } } return (dp[N][0] + dp[N][1] + dp[N][2]) % MOD; } int main() { ios::sync_with_stdio(false); cin.tie(nullptr); int N; cin >> N; cout << solve(N) << '\n'; return 0; }

from collections import defaultdict n = int(raw_input()) L = int(raw_input()) K = int(raw_input()) pts = list(map(int, raw_input().split())) groups = defaultdict(list) for x in pts: groups[x % K].append(x) ans = 0 for arr in groups.values(): arr.sort() left = 0 for right in range(len(arr)): while arr[right] - arr[left] > L: left += 1 ans = max(ans, right - left + 1) print code All test cases pass

from collections import defaultdict n = int(raw_input()) L = int(raw_input()) K = int(raw_input()) pts = list(map(int, raw_input().split())) groups = defaultdict(list) for x in pts: groups[x % K].append(x) ans = 0 for arr in groups.values(): arr.sort() left = 0 for right in range(len(arr)): while arr[right] - arr[left] > L: left += 1 ans = max(ans, right - left + 1) print ans

#include <bits/stdc++.h> using namespace std; long long solve(int N, int S, vector<int>& M) { unordered_map<long long, long long> freq; for (int x : M) : long long ans = 0; for (auto &[x, cnt] : freq) { long long y = (long long)S - 2LL * x; if (y < x) continue; auto it = freq.find(y); if (it == freq.end()) continue; if (x == y) ans += cnt * (cnt - 1) / 2; else ans += cnt * it->second; } return ans; } Barycentric Tether calibration ✅ C++

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