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📈 Análisis del canal de Telegram allcoding1_official
El canal allcoding1_official (@allcoding1_official) en el segmento lingüístico de Inglés es un actor destacado. Actualmente la comunidad reúne a 79 557 suscriptores, ocupando la posición 1 588 en la categoría Tecnologías y Aplicaciones y el puesto 3 855 en la región India.
📊 Métricas de audiencia y dinámica
Desde su creación el невідомо, el proyecto ha mostrado un crecimiento acelerado, reuniendo a 79 557 suscriptores.
Según los últimos datos del 14 octubre, 2026, el canal mantiene una actividad estable. En los últimos 30 días la variación de miembros fue de -1 647, y en las últimas 24 horas de 0, conservando un alto alcance.
- Estado de verificación: No verificado
- Tasa de interacción (ER): El promedio de interacción de la audiencia es 0.88%. Durante las primeras 24 horas tras publicar, el contenido suele obtener 0.65% de reacciones respecto al total de suscriptores.
- Alcance de las publicaciones: Cada publicación recibe en promedio 699 visualizaciones. En el primer día suele acumular 517 visualizaciones.
- Reacciones e interacción: La audiencia responde de forma activa: el promedio de reacciones por publicación es 2.
- Intereses temáticos: El contenido se centra en temas clave como dsa, stack, namaste, javascript, dev.
📝 Descripción y política de contenido
No se ha proporcionado la descripción del canal.
Gracias a la alta frecuencia de actualizaciones (últimos datos recibidos el 15 octubre, 2026), el canal mantiene la vigencia y un amplio alcance. La analítica demuestra que la audiencia interactúa activamente con el contenido, lo que lo convierte en un punto de referencia dentro de la categoría Tecnologías y Aplicaciones.
79 557
Suscriptores
Sin datos24 horas
-3057 días
-1 64730 días
Archivo de publicaciones
79 539
![def solve(N: int, t: list) -> list: if all(t[k] <= t[k+1] for k in range(N - 1)): return [0, sum(t)] p = next(k for k i](data:image/jpeg;base64,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)
def solve(N: int, t: list) -> list:
if all(t[k] <= t[k+1] for k in range(N - 1)):
return [0, sum(t)]
p = next(k for k in range(N - 1) if t[k] > t[k+1])
M = [0] * N
M[N-1] = t[N-1]
for i in range(N - 2, -1, -1):
M[i] = min(t[i], M[i+1])
prefix_sum = [0] * (N + 1)
for i in range(N):
prefix_sum[i+1] = prefix_sum[i] + t[i]
best = -1
for i in range(0, p + 2):
if i > 0 and t[i-1] > M[i]:
continue
total = prefix_sum[i] + M[i] * (N - i)
best = max(best, total)
return [1, best]
79 539
+1
#include <bits/stdc++.h>
using namespace std;
long long solve(int N, vector<int>& target) {
long long total = 0;
for (int i = 0; i < N; i++) total += target[i];
long long sumX = 0;
long long carry = 0;
for (int i = 0; i + 1 < N; i++) {
long long cap = min((long long)target[i] - carry, (long long)target[i + 1]);
if (cap < 0) cap = 0;
sumX += cap;
carry = cap;
}
return total - sumX;
}
int main() {
ios_base::sync_with_stdio(false);
cin.tie(NULL);
int N; cin >> N;
vector<int> target(N);
for (int i = 0; i < N; i++) cin >> target[i];
auto result = solve(N, target);
cout << result << endl;
return 0;
}
79 539
#include <bits/stdc++.h>
using namespace std;
long long solve(int N, vector<int>& target) {
long long total = 0;
for (int i = 0; i < N; i++) total += target[i];
long long sumX = 0;
long long carry = 0;
for (int i = 0; i + 1 < N; i++) {
long long cap = min((long long)target[i] - carry, (long long)target[i + 1]);
if (cap < 0) cap = 0;
sumX += cap;
carry = cap;
}
return total - sumX;
}
int main() {
ios_base::sync_with_stdio(false);
cin.tie(NULL);
int N; cin >> N;
vector<int> target(N);
for (int i = 0; i < N; i++) cin >> target[i];
auto result = solve(N, target);
cout << result << endl;
return 0;
}
79 539
#include <bits/stdc++.h>
using namespace std;
int solve(int N, int K, vector<vector<int>>& cost, vector<int>& fatigue) {
const long long INF = 4e18;
vector<vector<long long>> prev(K, vector<long long>(2, INF));
vector<vector<long long>> cur(K, vector<long long>(2, INF));
for (int c = 0; c < K; c++)
prev[c][1] = cost[0][c];
for (int i = 1; i < N; i++) {
for (int c = 0; c < K; c++) {
cur[c][0] = cur[c][1] = INF;
}
for (int last = 0; last < K; last++) {
for (int streak = 1; streak <= 2; streak++) {
if (prev[last][streak - 1] == INF) continue;
for (int now = 0; now < K; now++) {
if (now == last) {
if (streak == 2) continue;
cur[now][1] = min(
cur[now][1],
prev[last][streak - 1] +
cost[i][now] + fatigue[now]
);
79 539
#include <bits/stdc++.h>
using namespace std;
const int MOD = 1000000007;
int solve(int N) {
vector<array<long long, 3>> dp(N + 1);
// last = 0 -> 1
// last = 1 -> 3
// last = 2 -> 4
for (int s = 1; s <= N; s++) {
if (s == 1) {
dp[s][0] = 1;
} else {
long long ways = 0;
if (s >= 1) {
ways = (dp[s - 1][1] + dp[s - 1][2]) % MOD;
}
dp[s][0] = ways;
}
if (s == 3) {
dp[s][1] = (dp[s][1] + 1) % MOD;
}
if (s > 3) {
dp[s][1] = (dp[s - 3][0] + dp[s - 3][2]) % MOD;
}
if (s == 4) {
dp[s][2] = (dp[s][2] + 1) % MOD;
}
if (s > 4) {
dp[s][2] = (dp[s - 4][0] + dp[s - 4][1]) % MOD;
}
}
return (dp[N][0] + dp[N][1] + dp[N][2]) % MOD;
}
int main() {
ios::sync_with_stdio(false);
cin.tie(nullptr);
int N;
cin >> N;
cout << solve(N) << '\n';
return 0;
}
79 539
from collections import defaultdict
n = int(raw_input())
L = int(raw_input())
K = int(raw_input())
pts = list(map(int, raw_input().split()))
groups = defaultdict(list)
for x in pts:
groups[x % K].append(x)
ans = 0
for arr in groups.values():
arr.sort()
left = 0
for right in range(len(arr)):
while arr[right] - arr[left] > L:
left += 1
ans = max(ans, right - left + 1)
print code
All test cases pass
79 539
from collections import defaultdict
n = int(raw_input())
L = int(raw_input())
K = int(raw_input())
pts = list(map(int, raw_input().split()))
groups = defaultdict(list)
for x in pts:
groups[x % K].append(x)
ans = 0
for arr in groups.values():
arr.sort()
left = 0
for right in range(len(arr)):
while arr[right] - arr[left] > L:
left += 1
ans = max(ans, right - left + 1)
print ans
79 539
#include <bits/stdc++.h>
using namespace std;
long long solve(int N, int S, vector<int>& M) {
unordered_map<long long, long long> freq;
for (int x : M) :
long long ans = 0;
for (auto &[x, cnt] : freq) {
long long y = (long long)S - 2LL * x;
if (y < x) continue;
auto it = freq.find(y);
if (it == freq.end()) continue;
if (x == y)
ans += cnt * (cnt - 1) / 2;
else
ans += cnt * it->second;
}
return ans;
}
Barycentric Tether calibration ✅
C++
79 539
HCLTech Freshers Hiring
Eligible Batches: 2020–2026
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79 539
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79 539
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𝗖𝗼𝗴𝗻𝗶𝘇𝗮𝗻𝘁 𝗙𝗿𝗲𝘀𝗵𝗲𝗿 𝗛𝗶𝗿𝗶𝗻𝗴 – Digital Workplace Practice (Service Desk)
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𝗟𝗼𝗰𝗮𝘁𝗶𝗼𝗻: PAN India
𝗦𝗮𝗹𝗮𝗿𝘆: As Per Company Standards
𝗟𝗮𝘀𝘁 𝗗𝗮𝘁𝗲: 31st July 2026
𝗢𝗙𝗙𝗜𝗖𝗜𝗔𝗟 𝗔𝗣𝗣𝗟𝗜𝗖𝗔𝗧𝗜𝗢𝗡 𝗟𝗜𝗡𝗞: https://app.joinsuperset.com/join/#/signup/student/jobprofiles/a8af19f3-444e-43bd-8828-e8656f637a17
79 539
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AWS
Devops
Azure Devops
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All courses
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79 539
Google is hiring
Position: Data Analytics Apprenticeship
Qualifications: Bachelor’s degree
Experience: 0-1 (Years)
Location: Hyderabad; Bengaluru; Gurgaon; Mumbai, India
Apply Now: https://www.google.com/about/careers/applications/jobs/results/114421121054319302-data-analytics-apprenticeship-march-2027-start
79 539
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AWS
Devops
Azure Devops
👉Naresh IT
All courses
50 rupees
Lifetime access
Contact:- @meterials_available
79 539
Deloitte is Hiring for Services Support Associate
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