Data Careers Resources & Job Updates | iamrupnath
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بحسب آخر البيانات بتاريخ 31 يوليو, 2026، تحافظ القناة على نشاط مستقر. خلال آخر 30 يوماً تغيّر عدد الأعضاء بمقدار -416، وفي آخر 24 ساعة بمقدار -9، مع بقاء الوصول العام مرتفعاً.
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📝 الوصف وسياسة المحتوى
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“👉 Connect LinkedIn :
https://www.linkedin.com/in/rupnath-shaw
Google Search => Techcompreviews
IG: @iamrupnath
Perfect channel for Data Careers, Job Updates
Learn Excel, SQL, Python, Tableau, Power BI, AI tools, AI tips & tricks and many more”
بفضل وتيرة التحديث المرتفعة (أحدث البيانات بتاريخ 01 أغسطس, 2026) تحافظ القناة على حداثتها ومستوى وصول مرتفع. وتُظهر التحليلات تفاعلاً نشطاً من الجمهور، ما يجعلها نقطة تأثير مهمة ضمن فئة التكنولوجيات والتطبيقات.
GROUP BY clause in SQL is used to arrange identical data into groups. This is particularly useful when combined with aggregate functions like COUNT(), SUM(), AVG(), MIN(), and MAX(). The GROUP BY clause groups rows that have the same values in specified columns into summary rows.
▎Basic Syntax
SELECT column1, aggregate_function(column2)
FROM table_name
WHERE condition
GROUP BY column1;
▎Example 1: Counting Rows
Suppose you have a table called employees with the following structure:
| id | department | salary |
|----|------------|--------|
| 1 | HR | 50000 |
| 2 | IT | 60000 |
| 3 | HR | 55000 |
| 4 | IT | 70000 |
| 5 | Sales | 65000 |
To find out how many employees are in each department, you can use:
SELECT department, COUNT(*) AS employee_count
FROM employees
GROUP BY department;
Result:
| department | employee_count |
|------------|----------------|
| HR | 2 |
| IT | 2 |
| Sales | 1 |
▎Example 2: Summing Salaries
To calculate the total salary paid to employees in each department, you can use:
SELECT department, SUM(salary) AS total_salary
FROM employees
GROUP BY department;
Result:
| department | total_salary |
|------------|--------------|
| HR | 105000 |
| IT | 130000 |
| Sales | 65000 |
▎Example 3: Average Salary
To find the average salary of employees in each department:
SELECT department, AVG(salary) AS average_salary
FROM employees
GROUP BY department;
Result:
| department | average_salary |
|------------|----------------|
| HR | 52500 |
| IT | 65000 |
| Sales | 65000 |
▎Example 4: Grouping by Multiple Columns
You can also group by multiple columns. For instance, if you had another column for job_title:
| id | department | job_title | salary |
|----|------------|-----------|--------|
| 1 | HR | Manager | 50000 |
| 2 | IT | Developer | 60000 |
| 3 | HR | Assistant | 55000 |
| 4 | IT | Manager | 70000 |
| 5 | Sales | Executive | 65000 |
To count employees by both department and job_title:
SELECT department, job_title, COUNT(*) AS employee_count
FROM employees
GROUP BY department, job_title;
Result:
| department | job_title | employee_count |
|------------|-----------|----------------|
| HR | Manager | 1 |
| HR | Assistant | 1 |
| IT | Developer | 1 |
| IT | Manager | 1 |
| Sales | Executive | 1 |
▎Important Notes
1. Aggregate Functions: Any column in the SELECT statement that is not an aggregate function must be included in the GROUP BY clause.
2. HAVING Clause: You can filter groups using the HAVING clause, which is similar to the WHERE clause but is used for aggregated data. For example:
SELECT department, COUNT(*) AS employee_count
FROM employees
GROUP BY department
HAVING COUNT(*) > 1;
This would return only departments with more than one employee.
▎Conclusion
The GROUP BY clause is a powerful tool in SQL for summarizing data. It allows you to analyze and report on your datasets effectively by grouping similar data points and applying aggregate functions.