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OSSSC / OSSC MATH AND REASONING

OSSSC / OSSC MATH AND REASONING

Kanalga Telegram’da o‘tish

𝐀𝐧𝐲 PROMOTION RELATED CONTACT OWNER @BUNNYTAPAS Join our YouTube Channel: https://shorturl.at/Ulwjw 🔴 𝐂𝐮𝐫𝐫𝐞𝐧𝐭 𝐚𝐟𝐟𝐚𝐢𝐫𝐬 @CURRENT_AFFAIRS_REGULARLY 🔴𝐄𝐧𝐠𝐥𝐢𝐬𝐡- @BLACKBOOK_ENGLISH

Ko'proq ko'rsatish

📈 Telegram kanali OSSSC / OSSC MATH AND REASONING analitikasi

OSSSC / OSSC MATH AND REASONING (@pinnacle_math_reasoning) Ingliz til segmentidagi kanali faol ishtirokchi. Hozirda hamjamiyat 11 531 obunachidan iborat bo'lib, Taʼlim toifasida 17 102-o'rinni va Hindiston mintaqasida 33 457-o'rinni egallagan.

📊 Auditoriya ko‘rsatkichlari va dinamika

невідомо sanasidan buyon loyiha tez o‘sib, 11 531 obunachiga ega bo‘ldi.

02 Oktabr, 2026 dagi oxirgi ma’lumotlarga ko‘ra kanal barqaror faollikka ega. Oxirgi 30 kunda obunachilar soni 147 ga, so‘nggi 24 soatda esa 0 ga o‘zgardi va umumiy qamrov yuqori darajada qolmoqda.

  • Tasdiqlash holati: Tasdiqlanmagan
  • Jalb etish (ER): Auditoriya o‘rtacha 20.61% darajada jalb etiladi. Nashrdan keyingi dastlabki 24 soatda kontent odatda umumiy obunachilar sonining 4.23% ini tashkil etuvchi reaksiyalarni to‘playdi.
  • Post qamrovi: Har bir post o‘rtacha 2 377 marta ko‘riladi; birinchi sutkada odatda 488 ta ko‘rish yig‘iladi.
  • Reaksiyalar va o‘zaro ta’sir: Auditoriya faol: har bir postga o‘rtacha 4 ta reaksiya keladi.
  • Tematik yo‘nalishlar: Kontent ʜᴇʀᴇ, cgle, cgl, mcqs, mcq kabi asosiy mavzularga jamlangan.

📝 Tavsif va kontent siyosati

Muallif resursni shaxsiy fikrni ifoda etish maydoni sifatida ta’riflaydi:
“𝐀𝐧𝐲 PROMOTION RELATED CONTACT OWNER @BUNNYTAPAS Join our YouTube Channel: https://shorturl.at/Ulwjw 🔴 𝐂𝐮𝐫𝐫𝐞𝐧𝐭 𝐚𝐟𝐟𝐚𝐢𝐫𝐬 @CURRENT_AFFAIRS_REGULARLY 🔴𝐄𝐧𝐠𝐥𝐢𝐬𝐡- @BLACKBOOK_ENGLISH”

Yuqori yangilanish chastotasi (oxirgi ma’lumot 03 Oktabr, 2026 da olingan) sababli kanal doimo dolzarb va katta qamrovli bo‘lib qoladi. Analitika auditoriya kontent bilan faol hamkorlik qilishini, uni Taʼlim toifasidagi muhim ta’sir nuqtasiga aylantirishini ko‘rsatadi.

11 531
Obunachilar
Ma'lumot yo'q24 soatlar
+227 kun
+14730 kun
Postlar arxiv
If a number is divisible by 624, the remainder will be 53. If the same number is divisible by 16, then the remainder will be:
Anonymous voting

Let x be the least number which when divided by 8, 9, 12, 14 and 36 leaves a remainder of 4 in each case, but x is divisible by 11. The sum of the digits of x is____.
Anonymous voting

When a number M is divided by 7, the remainder is 6. What is the remainder if the square of M is divided by 7?
Anonymous voting

When 3738, 5659 and 9501 are divided by the greatest possible number x, the remainder in each case is y. What is the sum of x and y?
Anonymous voting

(a) Let the number be 23. On dividing 23 by 14 the remainder is 9. Again, on dividing (23)2 = 529 by 14 the remainder is 11.

When a number is divided by 14, the remainder is 9. If the square of the same number is divided by 14, then the remainder will be:
Anonymous voting

𝐎𝐃𝐈𝐒𝐇𝐀   𝐕𝐈𝐑𝐓𝐔𝐀𝐋   𝐋𝐈𝐁𝐑𝐀𝐑𝐘 The six-digit number 7x1yyx is a multiple of 33 for non-zero digits x and y. Which of the following could be a possible value of (x + y) ?
Anonymous voting

𝐎𝐃𝐈𝐒𝐇𝐀   𝐕𝐈𝐑𝐓𝐔𝐀𝐋   𝐋𝐈𝐁𝐑𝐀𝐑𝐘 What is the least value of x + y, if 10 digit number 780x533y24 is divisible by 88 ?
Anonymous voting

𝐎𝐃𝐈𝐒𝐇𝐀   𝐕𝐈𝐑𝐓𝐔𝐀𝐋   𝐋𝐈𝐁𝐑𝐀𝐑𝐘 In a division sum, the divisor is 11 times the quotient and 5 times the remainder. If the remainder is 44, then the dividend is:
Anonymous voting

𝐎𝐃𝐈𝐒𝐇𝐀   𝐕𝐈𝐑𝐓𝐔𝐀𝐋   𝐋𝐈𝐁𝐑𝐀𝐑𝐘 Two numbers, when divided by a certain divisor, leave the remainder 57. When sum of the two numbers is divided by the same divisor, the remainder is 49. The divisor is:
Anonymous voting

𝐎𝐃𝐈𝐒𝐇𝐀   𝐕𝐈𝐑𝐓𝐔𝐀𝐋   𝐋𝐈𝐁𝐑𝐀𝐑𝐘 A six-digit number 11p9q4 is divisible by 24. Then the greatest possible value for pq is:
Anonymous voting