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OSSSC / OSSC MATH AND REASONING

OSSSC / OSSC MATH AND REASONING

Kanalga Telegram’da o‘tish

𝐀𝐧𝐲 PROMOTION RELATED CONTACT OWNER @BUNNYTAPAS Join our YouTube Channel: https://shorturl.at/Ulwjw 🔴 𝐂𝐮𝐫𝐫𝐞𝐧𝐭 𝐚𝐟𝐟𝐚𝐢𝐫𝐬 @CURRENT_AFFAIRS_REGULARLY 🔴𝐄𝐧𝐠𝐥𝐢𝐬𝐡- @BLACKBOOK_ENGLISH

Ko'proq ko'rsatish

📈 Telegram kanali OSSSC / OSSC MATH AND REASONING analitikasi

OSSSC / OSSC MATH AND REASONING (@pinnacle_math_reasoning) Ingliz til segmentidagi kanali faol ishtirokchi. Hozirda hamjamiyat 11 530 obunachidan iborat bo'lib, Taʼlim toifasida 17 105-o'rinni va Hindiston mintaqasida 33 456-o'rinni egallagan.

📊 Auditoriya ko‘rsatkichlari va dinamika

невідомо sanasidan buyon loyiha tez o‘sib, 11 530 obunachiga ega bo‘ldi.

03 Oktabr, 2026 dagi oxirgi ma’lumotlarga ko‘ra kanal barqaror faollikka ega. Oxirgi 30 kunda obunachilar soni 130 ga, so‘nggi 24 soatda esa -3 ga o‘zgardi va umumiy qamrov yuqori darajada qolmoqda.

  • Tasdiqlash holati: Tasdiqlanmagan
  • Jalb etish (ER): Auditoriya o‘rtacha 12.47% darajada jalb etiladi. Nashrdan keyingi dastlabki 24 soatda kontent odatda umumiy obunachilar sonining 4.11% ini tashkil etuvchi reaksiyalarni to‘playdi.
  • Post qamrovi: Har bir post o‘rtacha 1 438 marta ko‘riladi; birinchi sutkada odatda 474 ta ko‘rish yig‘iladi.
  • Reaksiyalar va o‘zaro ta’sir: Auditoriya faol: har bir postga o‘rtacha 2 ta reaksiya keladi.
  • Tematik yo‘nalishlar: Kontent ʜᴇʀᴇ, cgle, cgl, mcqs, mcq kabi asosiy mavzularga jamlangan.

📝 Tavsif va kontent siyosati

Muallif resursni shaxsiy fikrni ifoda etish maydoni sifatida ta’riflaydi:
“𝐀𝐧𝐲 PROMOTION RELATED CONTACT OWNER @BUNNYTAPAS Join our YouTube Channel: https://shorturl.at/Ulwjw 🔴 𝐂𝐮𝐫𝐫𝐞𝐧𝐭 𝐚𝐟𝐟𝐚𝐢𝐫𝐬 @CURRENT_AFFAIRS_REGULARLY 🔴𝐄𝐧𝐠𝐥𝐢𝐬𝐡- @BLACKBOOK_ENGLISH”

Yuqori yangilanish chastotasi (oxirgi ma’lumot 04 Oktabr, 2026 da olingan) sababli kanal doimo dolzarb va katta qamrovli bo‘lib qoladi. Analitika auditoriya kontent bilan faol hamkorlik qilishini, uni Taʼlim toifasidagi muhim ta’sir nuqtasiga aylantirishini ko‘rsatadi.

11 530
Obunachilar
-324 soatlar
+117 kun
+13030 kun
Postlar arxiv
If a positive integer n is divided by 7, the remainder is 2. Which of the numbers in the options yields a remainder of 0 when it is divided by 7?
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Ans. (a) : 653 × 308 × 402 × 413 Unit's digit = 3 × 8 × 2 × 3 = 144 Unit digit = 4

What is the digit at units place in the product (653 × 308 × 402 × 413)?
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What percentage of the numbers from 101 to 1000 have 9 in the unit's digit?
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If the unit digit of 433 × 456 × 43N is (N + 2), then what is the value of N?
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How many positive factors of 444 are there?
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How many factors of 420 are prime numbers?
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The number of factors of 3600 is :
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How many natural numbers less than 1000 are divisible by 5 or 7 but NOT by 35?
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How many multiples of 7 are there from 1 to 100 which are not multiples of 4?
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x, y and z are prime numbers and x+y+z = 38. What is maximum value of x?
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