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Aptiwings | Problem solving skills | Aptitude

Aptiwings | Problem solving skills | Aptitude

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Choice (3) From the above diagram, we can see that if the player seeded 43 reached finals, then the player seeded 46 cannot r
Choice (3) From the above diagram, we can see that if the player seeded 43 reached finals, then the player seeded 46 cannot reach the final, as they are in the same half of the draw and exactly one person from each half of the draw reaches the finals.

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Let the repayments be Rs "a – d", Rs "a" and Rs. "a + d" a – d + a + a + d = 54000 3a = 54000 a = 18000 The payment at the en
Let the repayments be Rs "a – d", Rs "a" and Rs. "a + d" a – d + a + a + d = 54000 3a = 54000 a = 18000 The payment at the end of year 2 is Rs. 18,000. Borrowed amount = Rs. 45,000 Amount outstanding at the end of Year 1 = (45000 × 1.1) – (18000 – d) = 31500 + d Amount outstanding at the end of Year 2 = ((31500 + d) * 1.1) – 18000 = 34650 + 1.1d – 18000 = 16650 + 1.1d Amount outstanding at the end of Year 3 = ((16650 + 1.1d) * 1.1) = 18000 + d 18315 + 1.21d = 18000 + d 0.21d = – 315 d = –1500 The payments are Rs. 19500, Rs. 18000 and Rs. 16500 The question is " How much did he pay in year 1?" He paid Rs. 19500 in year 1

Lets say that the students are named a, b, c, d and e, in increasing order of weights. The average of a, b, c and d is 40 kg, whereas the average of b, c, d and e is 45 kg. The sum of a, b, c and d is 160 kg, and the sum of b, c, d and e is 180 kg. There are two ways of looking at this. a) 160 + e b) 180 + a Or, e is 20 more than a. The total weight is 160 + e. So, the highest value of e will correspond to the highest possible average. The highest possible value of e occurs when it is 20 higher than the highest possible value for a, which is 40 (all the first 4 scores are equal to 40). So, the highest possible average is (160+60)/5 = 44 This will be the case when the weights are 40 kgs, 40kgs, 40 kgs, 40 kgs and 60 kgs. Conversely, the least possible value for the average occurs when a is the least. This happens when e is the least too (since a is 20 less than e). The least possible value for e is 45 = 180/4 So, the least possible value for a would be 25. The least possible average = (180+25)/5 = 41 This will be the case when the weights are 25 kgs, 45kgs, 45 kgs, 45 kgs and 45 kgs. So, the difference between maximum possible and minimum possible average = 44 -41 = 3 kgs.

Aptiwings Formula Hand Book.pdf1.65 MB