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allcoding1 (@allcoding1) Ingliz til segmentidagi kanali faol ishtirokchi. Hozirda hamjamiyat 22 504 obunachidan iborat bo'lib, Taʼlim toifasida 8 840-o'rinni va Hindiston mintaqasida 19 317-o'rinni egallagan.
📊 Auditoriya ko‘rsatkichlari va dinamika
невідомо sanasidan buyon loyiha tez o‘sib, 22 504 obunachiga ega bo‘ldi.
19 Iyun, 2026 dagi oxirgi ma’lumotlarga ko‘ra kanal barqaror faollikka ega. Oxirgi 30 kunda obunachilar soni -395 ga, so‘nggi 24 soatda esa -4 ga o‘zgardi va umumiy qamrov yuqori darajada qolmoqda.
- Tasdiqlash holati: Tasdiqlanmagan
- Jalb etish (ER): Auditoriya o‘rtacha 6.50% darajada jalb etiladi. Nashrdan keyingi dastlabki 24 soatda kontent odatda umumiy obunachilar sonining 1.28% ini tashkil etuvchi reaksiyalarni to‘playdi.
- Post qamrovi: Har bir post o‘rtacha 1 462 marta ko‘riladi; birinchi sutkada odatda 288 ta ko‘rish yig‘iladi.
- Reaksiyalar va o‘zaro ta’sir: Auditoriya faol: har bir postga o‘rtacha 2 ta reaksiya keladi.
- Tematik yo‘nalishlar: Kontent dsa, stack, namaste, javascript, learning kabi asosiy mavzularga jamlangan.
📝 Tavsif va kontent siyosati
Kanal uchun tavsif kiritilmagan.
Yuqori yangilanish chastotasi (oxirgi ma’lumot 20 Iyun, 2026 da olingan) sababli kanal doimo dolzarb va katta qamrovli bo‘lib qoladi. Analitika auditoriya kontent bilan faol hamkorlik qilishini, uni Taʼlim toifasidagi muhim ta’sir nuqtasiga aylantirishini ko‘rsatadi.
22 504
Obunachilar
-424 soatlar
-867 kunlar
-39530 kunlar
Postlar arxiv
22 504
import java.lang.Math;
class Gfg {
// driver code
public static void main(String args[])
{
// float numbers
float x = 4567.9874f;
// find the closest int for these floats
System.out.println(Math.round(x));
float y = -3421.134f;
// find the closest int for these floats
System.out.println(Math.round(y));
double positiveInfinity = Double.POSITIVE_INFINITY;
// returns the Integer.MAX_VALUE value when
System.out.println(Math.round(positiveInfinity));
}
}
Java
IBM EXAM ANS 6PM
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22 504
x = float(input())
n = int(input())
print(round(x,n)
Python Q) abridged Ans
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22 504
🎯HCL Technologies Off Campus Freshers Recruitment Hiring For Analyst Role | 4.2 LPA
Job Role Senior analyst
Education B.Tech
Experience 0-2.5 Years
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22 504
string changeCase(string s, int n)
{
int n = s.size();
string ans = "";
if (n == 1)
{
for (int i = 0; i < n; i++)
{
int a = 0;
if (s[i] == ' ')
a = 1;
else if (a == 1)
ans += toupper(s[i]);
else
ans += s[i];
}
}
else if (n == 2)
{
for (int i = 0; i < n; i++)
{
int a = 0;
if (s[i] == ' ')
ans += '-';
else
ans += s[i];
}
}
else if (n == 3)
{
for (int i = 0; i < n; i++)
{
int a = 0;
if (s[i] == ' ')
ans += '_';
else
ans += s[i];
}
}
else if (n == 4)
{
ans += toupper(s[0]);
for (int i = 1; i < n; i++)
{
int a = 0;
if (s[i] == ' ')
a = 1;
else if (a == 1)
ans += toupper(s[i]);
else
ans += s[i];
}
}
return ans;
}
C++
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22 504
![def getMaximumGreyness(pixels): l=[] for i in range(len(pixels)): l.append(list(map(int,pixels[i]))) row_1=[] for i in range(](https://cdn.tlmtr.io/_next/static/media/empty-channel.35ed232f.svg)
def getMaximumGreyness(pixels):
l=[]
for i in range(len(pixels)):
l.append(list(map(int,pixels[i])))
row_1=[]
for i in range(len(l)):
k=sum(l[i])
row_1.append(k)
col_1=[]
for i in range(len(l[0])):
c=0
for j in range(len(l)):
c+=l[j][i]
col_1.append(c)
m=len(l)
n=len(l[0])
ans=[[0]*n]*m
res=-float("inf")
for i in range(len(l)):
for j in range(len(l[0])):
x=row_1[i]
y=col_1[j]
ans[i][j]=2*(x+y)-(m+n)
res=max(res,ans[i][j])
return res
Python 3
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22 504
🎯HCL Technologies Off Campus Freshers Recruitment Hiring For Analyst Role | 4.2 LPA
Job Role Senior analyst
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22 504
🎯Kreeti Technologies Off Campus Drive 2023 | B.E/B.Tech/MCA | 2021 & 2022 Batch
Job Role QA Engineer
Qualification B.E/B.Tech/MCA
Batch 2021 & 2022
Experience Freshers
Salary Rs. 4.5 LPA CTC
Job Location Kolkata
Interview Date Informed Later
Registration Last Date ASAP
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22 504
Amazon exam Coding Ans
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