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allcoding1

前往频道在 Telegram

📈 Telegram 频道 allcoding1 的分析概览

频道 allcoding1 (@allcoding1) 英语 语言赛道中的 是活跃参与者。目前社区聚集了 22 504 名订阅者,在 教育 类别中位列第 8 840,并在 印度 地区排名第 19 317

📊 受众指标与增长动态

невідомо 创建以来,项目保持高速增长,吸引了 22 504 名订阅者。

根据 19 六月, 2026 的最新数据,频道保持稳定运转。过去 30 天订阅人数变化为 -395,过去 24 小时变化为 -4,整体触达仍然可观。

  • 认证状态: 未认证
  • 互动率 (ER): 平均受众互动率为 6.50%。内容发布后 24 小时内通常能获得 1.28% 的反应,占订阅者总量。
  • 帖子覆盖: 每篇帖子平均可获得 1 462 次浏览,首日通常累积 288 次浏览。
  • 互动与反馈: 受众积极参与,单帖平均反应数为 2
  • 主题关注点: 内容集中在 dsa, stack, namaste, javascript, learning 等核心主题上。

📝 描述与内容策略

尚未提供频道描述。

凭借高频更新(最新数据采集于 20 六月, 2026),频道始终保持新鲜度与高覆盖。分析显示受众积极互动,使其成为 教育 类别中的关键影响点。

22 504
订阅者
-424 小时
-867
-39530
帖子存档
import java.lang.Math; class Gfg { // driver code public static void main(String args[]) { // float numbers float x = 4567.9874f; // find the closest int for these floats System.out.println(Math.round(x)); float y = -3421.134f; // find the closest int for these floats System.out.println(Math.round(y)); double positiveInfinity = Double.POSITIVE_INFINITY; // returns the Integer.MAX_VALUE value when System.out.println(Math.round(positiveInfinity)); } } Java IBM EXAM ANS 6PM Telegram:- @allcoding1

Python IBM EXAM ANS 6PM Telegram:- @allcoding1
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Python IBM EXAM ANS 6PM Telegram:- @allcoding1

Python IBM EXAM ANS 6PM Telegram:- @allcoding1
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Python IBM EXAM ANS 6PM Telegram:- @allcoding1

IBM EXAM ANS 6PM Telegram:- @allcoding1 Discussion group:- @IBM_exam_Ans

x = float(input()) n = int(input()) print(round(x,n) Python Q) abridged Ans Telegram:- @allcoding1

Python Telegram - @allcoding1
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Python Telegram - @allcoding1

IBM EXAM ANS 6PM Telegram:- @allcoding1

🎯HCL Technologies Off Campus Freshers Recruitment Hiring For Analyst Role | 4.2 LPA Job Role Senior analyst Education B.Tech Experience 0-2.5 Years CTC/Salary 4.2 LPA Apply Now:- http://www.allcoding1.com Telegram:- @allcoding1

C Telegram:- @allcoding1_official
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Code for changeCase question in python 3 Telegram:-@allcoding1
Code for changeCase question in python 3 Telegram:-@allcoding1

string changeCase(string s, int n) {     int n = s.size();     string ans = "";     if (n == 1)     {         for (int i = 0; i < n; i++)         {             int a = 0;             if (s[i] == ' ')                 a = 1;             else if (a == 1)                 ans += toupper(s[i]);             else                 ans += s[i];         }     }     else if (n == 2)     {         for (int i = 0; i < n; i++)         {             int a = 0;             if (s[i] == ' ')                 ans += '-';             else                 ans += s[i];         }     }     else if (n == 3)     {         for (int i = 0; i < n; i++)         {             int a = 0;             if (s[i] == ' ')                 ans += '_';             else                 ans += s[i];         }     }     else if (n == 4)     {         ans += toupper(s[0]);         for (int i = 1; i < n; i++)         {             int a = 0;             if (s[i] == ' ')                 a = 1;             else if (a == 1)                 ans += toupper(s[i]);             else                 ans += s[i];         }     }     return ans; } C++ Telegram:- @allcoding1

Python Telegram - @allcoding1
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Python Telegram - @allcoding1

photo content
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C++ Telegram - @allcoding1
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C++ Telegram - @allcoding1

Python Telegram:- @allcoding1
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Python Telegram:- @allcoding1

def getMaximumGreyness(pixels): l=[] for i in range(len(pixels)): l.append(list(map(int,pixels[i]))) row_1=[] for i in range(
def getMaximumGreyness(pixels):     l=[]     for i in range(len(pixels)):         l.append(list(map(int,pixels[i])))     row_1=[]     for i in range(len(l)):         k=sum(l[i])         row_1.append(k)     col_1=[]     for i in range(len(l[0])):         c=0         for j in range(len(l)):             c+=l[j][i]         col_1.append(c)     m=len(l)     n=len(l[0])     ans=[[0]*n]*m     res=-float("inf")     for i in range(len(l)):         for j in range(len(l[0])):             x=row_1[i]             y=col_1[j]             ans[i][j]=2*(x+y)-(m+n)             res=max(res,ans[i][j])     return res Python 3 Telegram:- @allcoding1

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