Data Careers Resources & Job Updates | iamrupnath
👉 Connect LinkedIn : https://www.linkedin.com/in/rupnath-shaw Google Search => Techcompreviews IG: @iamrupnath Perfect channel for Data Careers, Job Updates Learn Excel, SQL, Python, Tableau, Power BI, AI tools, AI tips & tricks and many more
Ko'proq ko'rsatish📈 Telegram kanali Data Careers Resources & Job Updates | iamrupnath analitikasi
Data Careers Resources & Job Updates | iamrupnath (@codewithrup) Ingliz til segmentidagi kanali faol ishtirokchi. Hozirda hamjamiyat 21 400 obunachidan iborat bo'lib, Texnologiyalar & Aralashmalar toifasida 6 134-o'rinni va Hindiston mintaqasida 19 532-o'rinni egallagan.
📊 Auditoriya ko‘rsatkichlari va dinamika
невідомо sanasidan buyon loyiha tez o‘sib, 21 400 obunachiga ega bo‘ldi.
28 Iyul, 2026 dagi oxirgi ma’lumotlarga ko‘ra kanal barqaror faollikka ega. Oxirgi 30 kunda obunachilar soni -413 ga, so‘nggi 24 soatda esa -15 ga o‘zgardi va umumiy qamrov yuqori darajada qolmoqda.
- Tasdiqlash holati: Tasdiqlanmagan
- Jalb etish (ER): Auditoriya o‘rtacha 4.36% darajada jalb etiladi. Nashrdan keyingi dastlabki 24 soatda kontent odatda umumiy obunachilar sonining 1.29% ini tashkil etuvchi reaksiyalarni to‘playdi.
- Post qamrovi: Har bir post o‘rtacha 933 marta ko‘riladi; birinchi sutkada odatda 277 ta ko‘rish yig‘iladi.
- Reaksiyalar va o‘zaro ta’sir: Auditoriya faol: har bir postga o‘rtacha 1 ta reaksiya keladi.
- Tematik yo‘nalishlar: Kontent apply, qualification, bachelor, degree, engineer kabi asosiy mavzularga jamlangan.
📝 Tavsif va kontent siyosati
Muallif resursni shaxsiy fikrni ifoda etish maydoni sifatida ta’riflaydi:
“👉 Connect LinkedIn :
https://www.linkedin.com/in/rupnath-shaw
Google Search => Techcompreviews
IG: @iamrupnath
Perfect channel for Data Careers, Job Updates
Learn Excel, SQL, Python, Tableau, Power BI, AI tools, AI tips & tricks and many more”
Yuqori yangilanish chastotasi (oxirgi ma’lumot 29 Iyul, 2026 da olingan) sababli kanal doimo dolzarb va katta qamrovli bo‘lib qoladi. Analitika auditoriya kontent bilan faol hamkorlik qilishini, uni Texnologiyalar & Aralashmalar toifasidagi muhim ta’sir nuqtasiga aylantirishini ko‘rsatadi.
SELECT *, missing indexes, functions in WHERE, unnecessary JOINs, subqueries.
https://www.linkedin.com/feed/update/urn:li:share:7488197667341385728/SELECT
employee_id,
total_projects
FROM (
SELECT
employee_id,
COUNT(DISTINCT project_id) AS total_projects,
DENSE_RANK() OVER (
ORDER BY COUNT(DISTINCT project_id) DESC
) AS rnk
FROM employee_projects
GROUP BY employee_id
) ranked
WHERE rnk = 1;
💡 Explanation:
This query counts the number of unique projects each employee has worked on and identifies those with the highest count.
• COUNT(DISTINCT project_id) counts unique projects for each employee
• GROUP BY employee_id creates one record per employee
• DENSE_RANK() ranks employees based on the number of projects
• The outer query returns all employees tied for the highest number of projects
This question tests your understanding of:
✅ COUNT(DISTINCT)
✅ GROUP BY
✅ Window Functions DENSE_RANK
✅ Ranking Aggregated Results
🎯 Expected Output Example
Employee ID | Total Projects
101 | 12
205 | 12
Both employees have worked on the highest number of distinct projects.
🚀 Alternative Without Window Functions
SELECT
employee_id,
COUNT(DISTINCT project_id) AS total_projects
FROM employee_projects
GROUP BY employee_id
HAVING COUNT(DISTINCT project_id) = (
SELECT MAX(project_count)
FROM (
SELECT
COUNT(DISTINCT project_id) AS project_count
FROM employee_projects
GROUP BY employee_id
) t
);
This solution uses nested subqueries and MAX() instead of window functions.
🚀 Tip for SQL Job Seekers:
Many interview questions involve ranking aggregated results, such as:
Highest number of projects, Most orders, Maximum sales, Highest attendance, Most logins
Practice combining GROUP BY with window functions like DENSE_RANK() to solve these efficiently.
❤️ React with ❤️ for more interview challenges!