Coding Interview Resources
This channel contains the free resources and solution of coding problems which are usually asked in the interviews. Managed by: @love_data
Ko'proq ko'rsatish📈 Telegram kanali Coding Interview Resources analitikasi
Coding Interview Resources (@crackingthecodinginterview) Ingliz til segmentidagi kanali faol ishtirokchi. Hozirda hamjamiyat 52 034 obunachidan iborat bo'lib, Texnologiyalar & Aralashmalar toifasida 2 563-o'rinni va Hindiston mintaqasida 6 802-o'rinni egallagan.
📊 Auditoriya ko‘rsatkichlari va dinamika
невідомо sanasidan buyon loyiha tez o‘sib, 52 034 obunachiga ega bo‘ldi.
26 Oktabr, 2026 dagi oxirgi ma’lumotlarga ko‘ra kanal barqaror faollikka ega. Oxirgi 30 kunda obunachilar soni -185 ga, so‘nggi 24 soatda esa -3 ga o‘zgardi va umumiy qamrov yuqori darajada qolmoqda.
- Tasdiqlash holati: Tasdiqlanmagan
- Jalb etish (ER): Auditoriya o‘rtacha 2.13% darajada jalb etiladi. Nashrdan keyingi dastlabki 24 soatda kontent odatda umumiy obunachilar sonining 0.64% ini tashkil etuvchi reaksiyalarni to‘playdi.
- Post qamrovi: Har bir post o‘rtacha 1 110 marta ko‘riladi; birinchi sutkada odatda 331 ta ko‘rish yig‘iladi.
- Reaksiyalar va o‘zaro ta’sir: Auditoriya faol: har bir postga o‘rtacha 2 ta reaksiya keladi.
- Tematik yo‘nalishlar: Kontent array, stack, algorithm, programming, sort kabi asosiy mavzularga jamlangan.
📝 Tavsif va kontent siyosati
Muallif resursni shaxsiy fikrni ifoda etish maydoni sifatida ta’riflaydi:
“This channel contains the free resources and solution of coding problems which are usually asked in the interviews.
Managed by: @love_data”
Yuqori yangilanish chastotasi (oxirgi ma’lumot 27 Oktabr, 2026 da olingan) sababli kanal doimo dolzarb va katta qamrovli bo‘lib qoladi. Analitika auditoriya kontent bilan faol hamkorlik qilishini, uni Texnologiyalar & Aralashmalar toifasidagi muhim ta’sir nuqtasiga aylantirishini ko‘rsatadi.
s = "hello"
print(s[::-1]) # Output: 'olleh'
2. Check for a palindrome:
def is_palindrome(s):
return s == s[::-1]
3. Count word frequency in a list:
from collections import Counter
words = ['apple', 'banana', 'apple']
print(Counter(words))
4. Swap two variables:
a, b = 5, 10
a, b = b, a
5. Fibonacci using recursion:
def fib(n):
return n if n <= 1 else fib(n-1) + fib(n-2)
6. Find duplicate elements:
lst = [1,2,3,2,4]
duplicates = set([x for x in lst if lst.count(x) > 1])
7. Check if list is sorted:
def is_sorted(lst):
return lst == sorted(lst)
8. Flatten a 2D list:
matrix = [[1, 2], [3, 4]]
flat = [num for row in matrix for num in row]
9. Read a file line by line:
with open('file.txt') as f:
for line in f:
print(line.strip())
10. Lambda & Map usage:
nums = [1, 2, 3]
squares = list(map(lambda x: x**2, nums))
💡 Practice these with variations, especially for lists, strings, and dictionaries.
💬 Tap ❤️ for more!
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