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allcoding1_official (@allcoding1_official) Ingliz til segmentidagi kanali faol ishtirokchi. Hozirda hamjamiyat 84 584 obunachidan iborat bo'lib, Texnologiyalar & Aralashmalar toifasida 1 497-o'rinni va Hindiston mintaqasida 3 527-o'rinni egallagan.
📊 Auditoriya ko‘rsatkichlari va dinamika
невідомо sanasidan buyon loyiha tez o‘sib, 84 584 obunachiga ega bo‘ldi.
10 Iyul, 2026 dagi oxirgi ma’lumotlarga ko‘ra kanal barqaror faollikka ega. Oxirgi 30 kunda obunachilar soni -1 556 ga, so‘nggi 24 soatda esa -30 ga o‘zgardi va umumiy qamrov yuqori darajada qolmoqda.
- Tasdiqlash holati: Tasdiqlanmagan
- Jalb etish (ER): Auditoriya o‘rtacha 2.01% darajada jalb etiladi. Nashrdan keyingi dastlabki 24 soatda kontent odatda umumiy obunachilar sonining 0.85% ini tashkil etuvchi reaksiyalarni to‘playdi.
- Post qamrovi: Har bir post o‘rtacha 1 701 marta ko‘riladi; birinchi sutkada odatda 723 ta ko‘rish yig‘iladi.
- Reaksiyalar va o‘zaro ta’sir: Auditoriya faol: har bir postga o‘rtacha 1 ta reaksiya keladi.
- Tematik yo‘nalishlar: Kontent dsa, stack, namaste, javascript, dev kabi asosiy mavzularga jamlangan.
📝 Tavsif va kontent siyosati
Kanal uchun tavsif kiritilmagan.
Yuqori yangilanish chastotasi (oxirgi ma’lumot 11 Iyul, 2026 da olingan) sababli kanal doimo dolzarb va katta qamrovli bo‘lib qoladi. Analitika auditoriya kontent bilan faol hamkorlik qilishini, uni Texnologiyalar & Aralashmalar toifasidagi muhim ta’sir nuqtasiga aylantirishini ko‘rsatadi.
84 584
Obunachilar
-3024 soatlar
-4257 kunlar
-1 55630 kunlar
Postlar arxiv
84 569
Accenture Velotio & Johnson Off Campus Drive | 4LPA+
Batch - 2019 2020 2021 2022
https://www.joboffersadda.com/2022/04/accenture-off-campus-drive-4lpa-batch.html?m=1
https://www.joboffersadda.com/2022/04/accenture-off-campus-drive-4lpa-batch.html?m=1
Telegram - @allcoding1
84 569
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84 569
JOBS NOTIFICATIONS 🔔 (2022)
allcoding1:
3.5LPA
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4LPA
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8LPA
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7.5LPA
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10LPA
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Telegram:- @allcoding1
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4.5 LPA
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4.3 LPA
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7.3LPA
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12LPA
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6LPA
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4 LPA
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4LPA
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8LPA
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6 LPA
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🎯 virtusa
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🎯IBM
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🎯TCS 4.4 LPA
Apply:- https://www.joboffersadda.com/2022/04/tcs-is-hiring-any-graduate.html
🎯 Tech Mahindra. 3.25 LPA
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🎯Data- patterns 6 LPS
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84 569
🔔Jobs notifications
Accenture
Capgemini
Cognizant
Infosys
IBM
TCS
Tech Mahindra
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Apply Now
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84 569
🎯RDA Labs Off Campus Drive | CTC: INR 5.5 LPA
* Job Role : Associate Engineer
* Qualification : B.E/B.Tech
* Experience : Freshers
* Package : 5.5 LPA
https://www.joboffersadda.com/2022/04/rda-labs-off-campus-drive-ctc-inr-55-lpa.html
https://www.joboffersadda.com/2022/04/rda-labs-off-campus-drive-ctc-inr-55-lpa.html
TELEGRAM :-@allcoding1
84 569
#include <bits/stdc++.h>
using namespace std;
int vowel(string s){
int n = s.length();
vector<int> arr;
for (int i = 0; i < n; i++) {
if (i == 0){
arr.push_back(n);
}
else{
arr.push_back((n - i) + arr[i - 1] - i);
}
}
int sum = 0;
for (int i = 0; i < n; i++)
if (s[i] == 'a' s[i] == 'e' s[i] == 'i' s[i] == 'o' s[i] == 'u'){
sum += arr[i];
}
return sum;
}
int main(){
string s = "abc";
cout << vowel(s) << endl;
}
EPAM
VOWEL Code
C++
TELEGRAM :-@allcoding1
84 569
Repost from allcoding1_official
#include <bits/stdc++.h>
using namespace std;
int vowel(string s){
int n = s.length();
vector<int> arr;
for (int i = 0; i < n; i++) {
if (i == 0){
arr.push_back(n);
}
else{
arr.push_back((n - i) + arr[i - 1] - i);
}
}
int sum = 0;
for (int i = 0; i < n; i++)
if (s[i] == 'a' s[i] == 'e' s[i] == 'i' s[i] == 'o' s[i] == 'u'){
sum += arr[i];
}
return sum;
}
int main(){
string s = "abc";
cout << vowel(s) << endl;
}
EPAM CODE
Telegram👇
@allcoding1 @allcoding1
@allcoding1 @allcoding1
@allcoding1 @allcoding1
⚠️ Share post in ur college and telegram Group's
84 569
Repost from allcoding1_official
from bisect import bisect_left, insort_left
n, d = map(int, input().split())
t = list(map(int, input().split()))
noti = 0
lastd = sorted(t[:d])
def med():
return lastd[d//2] if d % 2 == 1 else ((lastd[d//2] + lastd[d//2-1])/2)
for i in range(d, n):
if t[i] >= 2*med():
noti += 1
del lastd[bisect_left(lastd,t[i-d])]
insort_left(lastd, t[i])
print(noti)
EPAM Bank Notification Code
Telegram👇
@allcoding1 @allcoding1
@allcoding1 @allcoding1
@allcoding1 @allcoding1
⚠️ Share post in ur college and telegram Group's
84 569
Repost from allcoding1_official
#include <bits/stdc++.h>
using namespace std;
int vowel(string s){
int n = s.length();
vector<int> arr;
for (int i = 0; i < n; i++) {
if (i == 0){
arr.push_back(n);
}
else{
arr.push_back((n - i) + arr[i - 1] - i);
}
}
int sum = 0;
for (int i = 0; i < n; i++)
if (s[i] == 'a' || s[i] == 'e' || s[i] == 'i'|| s[i] == 'o' || s[i] == 'u'){
sum += arr[i];
}
return sum;
}
int main(){
string s = "abc";
cout << vowel(s) << endl;
}
EPAM
Telegram - https://t.me/allcoding1
