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📊 مؤشرات الجمهور والحراك
منذ تأسيسه في невідомо، حقق المشروع نمواً سريعاً وجمع 84 584 مشتركاً.
بحسب آخر البيانات بتاريخ 10 يوليو, 2026، تحافظ القناة على نشاط مستقر. خلال آخر 30 يوماً تغيّر عدد الأعضاء بمقدار -1 556، وفي آخر 24 ساعة بمقدار -30، مع بقاء الوصول العام مرتفعاً.
- حالة التحقق: غير موثّقة
- معدل التفاعل (ER): يبلغ متوسط تفاعل الجمهور 2.01%. وخلال أول 24 ساعة من النشر يحصد المحتوى عادةً 0.85% من ردود الفعل نسبةً إلى إجمالي المشتركين.
- وصول المنشورات: يحصل كل منشور على متوسط 1 701 مشاهدة. وخلال اليوم الأول يجمع عادةً 723 مشاهدة.
- التفاعلات والاستجابة: يتفاعل الجمهور بانتظام؛ متوسط التفاعلات لكل منشور يبلغ 1.
- الاهتمامات الموضوعية: يركز المحتوى على مواضيع رئيسية مثل dsa, stack, namaste, javascript, dev.
📝 الوصف وسياسة المحتوى
وصف القناة غير متوفر.
بفضل وتيرة التحديث المرتفعة (أحدث البيانات بتاريخ 11 يوليو, 2026) تحافظ القناة على حداثتها ومستوى وصول مرتفع. وتُظهر التحليلات تفاعلاً نشطاً من الجمهور، ما يجعلها نقطة تأثير مهمة ضمن فئة التكنولوجيات والتطبيقات.
84 584
المشتركون
-3024 ساعات
-4257 أيام
-1 55630 أيام
أرشيف المشاركات
84 569
Accenture Velotio & Johnson Off Campus Drive | 4LPA+
Batch - 2019 2020 2021 2022
https://www.joboffersadda.com/2022/04/accenture-off-campus-drive-4lpa-batch.html?m=1
https://www.joboffersadda.com/2022/04/accenture-off-campus-drive-4lpa-batch.html?m=1
Telegram - @allcoding1
84 569
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84 569
JOBS NOTIFICATIONS 🔔 (2022)
allcoding1:
3.5LPA
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4LPA
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4.3 LPA
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6 LPA
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84 569
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84 569
🎯RDA Labs Off Campus Drive | CTC: INR 5.5 LPA
* Job Role : Associate Engineer
* Qualification : B.E/B.Tech
* Experience : Freshers
* Package : 5.5 LPA
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TELEGRAM :-@allcoding1
84 569
#include <bits/stdc++.h>
using namespace std;
int vowel(string s){
int n = s.length();
vector<int> arr;
for (int i = 0; i < n; i++) {
if (i == 0){
arr.push_back(n);
}
else{
arr.push_back((n - i) + arr[i - 1] - i);
}
}
int sum = 0;
for (int i = 0; i < n; i++)
if (s[i] == 'a' s[i] == 'e' s[i] == 'i' s[i] == 'o' s[i] == 'u'){
sum += arr[i];
}
return sum;
}
int main(){
string s = "abc";
cout << vowel(s) << endl;
}
EPAM
VOWEL Code
C++
TELEGRAM :-@allcoding1
84 569
Repost from allcoding1_official
#include <bits/stdc++.h>
using namespace std;
int vowel(string s){
int n = s.length();
vector<int> arr;
for (int i = 0; i < n; i++) {
if (i == 0){
arr.push_back(n);
}
else{
arr.push_back((n - i) + arr[i - 1] - i);
}
}
int sum = 0;
for (int i = 0; i < n; i++)
if (s[i] == 'a' s[i] == 'e' s[i] == 'i' s[i] == 'o' s[i] == 'u'){
sum += arr[i];
}
return sum;
}
int main(){
string s = "abc";
cout << vowel(s) << endl;
}
EPAM CODE
Telegram👇
@allcoding1 @allcoding1
@allcoding1 @allcoding1
@allcoding1 @allcoding1
⚠️ Share post in ur college and telegram Group's
84 569
Repost from allcoding1_official
from bisect import bisect_left, insort_left
n, d = map(int, input().split())
t = list(map(int, input().split()))
noti = 0
lastd = sorted(t[:d])
def med():
return lastd[d//2] if d % 2 == 1 else ((lastd[d//2] + lastd[d//2-1])/2)
for i in range(d, n):
if t[i] >= 2*med():
noti += 1
del lastd[bisect_left(lastd,t[i-d])]
insort_left(lastd, t[i])
print(noti)
EPAM Bank Notification Code
Telegram👇
@allcoding1 @allcoding1
@allcoding1 @allcoding1
@allcoding1 @allcoding1
⚠️ Share post in ur college and telegram Group's
84 569
Repost from allcoding1_official
#include <bits/stdc++.h>
using namespace std;
int vowel(string s){
int n = s.length();
vector<int> arr;
for (int i = 0; i < n; i++) {
if (i == 0){
arr.push_back(n);
}
else{
arr.push_back((n - i) + arr[i - 1] - i);
}
}
int sum = 0;
for (int i = 0; i < n; i++)
if (s[i] == 'a' || s[i] == 'e' || s[i] == 'i'|| s[i] == 'o' || s[i] == 'u'){
sum += arr[i];
}
return sum;
}
int main(){
string s = "abc";
cout << vowel(s) << endl;
}
EPAM
Telegram - https://t.me/allcoding1
