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allcoding1_official

allcoding1_official

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allcoding1_official (@allcoding1_official) Ingliz til segmentidagi kanali faol ishtirokchi. Hozirda hamjamiyat 78 863 obunachidan iborat bo'lib, Texnologiyalar & Aralashmalar toifasida 1 625-o'rinni va Hindiston mintaqasida 3 815-o'rinni egallagan.

📊 Auditoriya ko‘rsatkichlari va dinamika

невідомо sanasidan buyon loyiha tez o‘sib, 78 863 obunachiga ega bo‘ldi.

28 Oktabr, 2026 dagi oxirgi ma’lumotlarga ko‘ra kanal barqaror faollikka ega. Oxirgi 30 kunda obunachilar soni -1 626 ga, so‘nggi 24 soatda esa -63 ga o‘zgardi va umumiy qamrov yuqori darajada qolmoqda.

  • Tasdiqlash holati: Tasdiqlanmagan
  • Jalb etish (ER): Auditoriya o‘rtacha 2.72% darajada jalb etiladi. Nashrdan keyingi dastlabki 24 soatda kontent odatda umumiy obunachilar sonining 0.61% ini tashkil etuvchi reaksiyalarni to‘playdi.
  • Post qamrovi: Har bir post o‘rtacha 2 148 marta ko‘riladi; birinchi sutkada odatda 478 ta ko‘rish yig‘iladi.
  • Reaksiyalar va o‘zaro ta’sir: Auditoriya faol: har bir postga o‘rtacha 0 ta reaksiya keladi.
  • Tematik yo‘nalishlar: Kontent dsa, stack, namaste, javascript, dev kabi asosiy mavzularga jamlangan.

📝 Tavsif va kontent siyosati

Kanal uchun tavsif kiritilmagan.

Yuqori yangilanish chastotasi (oxirgi ma’lumot 29 Oktabr, 2026 da olingan) sababli kanal doimo dolzarb va katta qamrovli bo‘lib qoladi. Analitika auditoriya kontent bilan faol hamkorlik qilishini, uni Texnologiyalar & Aralashmalar toifasidagi muhim ta’sir nuqtasiga aylantirishini ko‘rsatadi.

78 863
Obunachilar
-6324 soatlar
-3517 kun
-1 62630 kun
Postlar arxiv
Part time jobs hyderabad https://t.me/+_LwFiGmv2N45NDM9

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def find_different_evenness_index(n, numbers): odd_count = even_count = 0 odd_index = even_index = 0 for i, num in enumerate(
def find_different_evenness_index(n, numbers):     odd_count = even_count = 0     odd_index = even_index = 0     for i, num in enumerate(numbers):         if num % 2 == 0:             even_count += 1             even_index = i + 1         else:             odd_count += 1             odd_index = i + 1     return odd_index if even_count > odd_count else even_index n = int(input()) numbers = list(map(int, input().split())) result = find_different_evenness_index(n, numbers) print(result) Accenture

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n=int(input()) temp=list(map(int,list(bin(n)[2:]))) print(sum(temp)) Python3
n=int(input()) temp=list(map(int,list(bin(n)[2:]))) print(sum(temp)) Python3

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