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allcoding1_official
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allcoding1_official (@allcoding1_official) Ingliz til segmentidagi kanali faol ishtirokchi. Hozirda hamjamiyat 85 483 obunachidan iborat bo'lib, Texnologiyalar & Aralashmalar toifasida 1 507-o'rinni va Hindiston mintaqasida 3 480-o'rinni egallagan.
📊 Auditoriya ko‘rsatkichlari va dinamika
невідомо sanasidan buyon loyiha tez o‘sib, 85 483 obunachiga ega bo‘ldi.
24 Iyun, 2026 dagi oxirgi ma’lumotlarga ko‘ra kanal barqaror faollikka ega. Oxirgi 30 kunda obunachilar soni -1 369 ga, so‘nggi 24 soatda esa -35 ga o‘zgardi va umumiy qamrov yuqori darajada qolmoqda.
- Tasdiqlash holati: Tasdiqlanmagan
- Jalb etish (ER): Auditoriya o‘rtacha 2.60% darajada jalb etiladi. Nashrdan keyingi dastlabki 24 soatda kontent odatda umumiy obunachilar sonining 0.55% ini tashkil etuvchi reaksiyalarni to‘playdi.
- Post qamrovi: Har bir post o‘rtacha 2 222 marta ko‘riladi; birinchi sutkada odatda 474 ta ko‘rish yig‘iladi.
- Reaksiyalar va o‘zaro ta’sir: Auditoriya faol: har bir postga o‘rtacha 3 ta reaksiya keladi.
- Tematik yo‘nalishlar: Kontent dsa, stack, namaste, javascript, dev kabi asosiy mavzularga jamlangan.
📝 Tavsif va kontent siyosati
Kanal uchun tavsif kiritilmagan.
Yuqori yangilanish chastotasi (oxirgi ma’lumot 25 Iyun, 2026 da olingan) sababli kanal doimo dolzarb va katta qamrovli bo‘lib qoladi. Analitika auditoriya kontent bilan faol hamkorlik qilishini, uni Texnologiyalar & Aralashmalar toifasidagi muhim ta’sir nuqtasiga aylantirishini ko‘rsatadi.
85 483
Obunachilar
-3524 soatlar
-2687 kunlar
-1 36930 kunlar
Postlar arxiv
85 483
🎯Atos Is Hiring
Degree:- Any Graduate
Batch:- 2019, 2020, 2021, 2022, 2023 & 2024
Apply Now:- https://www.allcoding1.com/2024/02/atos-off-campus-drive-for-any-graduate.html
Telegram:- @allcoding1_official
85 483
public class Solution {
public static int longestArraySegment(int array_length, List<Integer> arr) {
int maxLength = 1;
int currentLength = 1;
for (int i = 1; i < array_length; i++) {
if (arr.get(i) > arr.get(i - 1)) {
currentLength++;
} else {
currentLength = 1;
}
maxLength = Math.max(maxLength, currentLength);
}
currentLength = 1;
for (int i = 1; i < array_length; i++) {
if (arr.get(i) < arr.get(i - 1)) {
currentLength++;
} else {
currentLength = 1;
}
maxLength = Math.max(maxLength, currentLength);
}
return maxLength;
}
Ever increasing and ever decreasing - L&T
Java
Telegram:- @allcoding1_official
85 483
int solve(vector<int>& A) { int s = 0; for (const auto&n: A) { string sn = to_string(n); char md = *max_element(sn.begin().
sn.end());
s += md-'0';
}
return s;
}
C++
Telegram:- @allcoding1_official
L&t
Encryption by digits
85 483
int solve(vector<int>& arr) { int narr.size(); if (n == 0) return 0;
int maxLen = 1;
int currLen = 1;
bool f = true;
for (int i = 1; i < n; ++i) { if ((arr[i] > arr[i-1] && f) || (arr[i] < arr[i-1] && !f)) { ++currLen; } else { maxLen = max(maxLen, currLen); currLen = 2;
f = arr[i] > arr[i-1]
}
}
maxLen = max(maxLen, currLen); return maxLen;
}
C++
Telegram:- @allcoding1_official
L&t
Q) Ever - increasing & ever decreasing array segments
85 483
+2int solve(vector& arr) { int n = arr.size(); if (n == 0) return 0;
int maxLen = 1; int currLen = 1; bool f = true;
for (int i = 1; i < n; ++i) { if ((arr[i] > arr[i-1] && f) II (arr[i] < arr[i-1] && !f)) { ++currLen; } else {
maxLen = max(maxLen, currLen); currLen = 2; f = arr[i] > arr[i-1]; }
maxLen = max(maxLen, currLen); return maxLen; }
C++
85 483
Repost from allcoding1_official
Cognizant is hiring❤️
Apply link:
https://t.me/itjoblinks
Join our group for daily job posts
#paid promotion
85 483
Repost from allcoding1_official
Guys❤
👉 I am doing promotions (real Or fake) I don't know
👉I'm not forcing you. Your decision
👉I am not a responsible to you and money
👉 I need money that why I'm doing promotions try understand
85 483
🎯Position: Accountant Trainee
Location: Coimbatore
Experience: Fresher
Qualification: B.Com. 2023 passed out
https://careers.banfico.com/jobs/Careers/31483000015926001/Accountant-Trainee?source=CareerSite&t=807
85 483
Cognizant is hiring❤️
Apply link:
https://t.me/itjoblinks
Join our group for daily job posts
#paid promotion
85 483
Guys❤
👉 I am doing promotions (real Or fake) I don't know
👉I'm not forcing you. Your decision
👉I am not a responsible to you and money
👉 I need money that why I'm doing promotions try understand
85 483
Cognizant is hiring❤️
Apply link:
https://t.me/itjoblinks
Join our group for daily job posts
#paid promotion
85 483
Cognizant is hiring❤️
Apply link:
https://t.me/itjoblinks
Join our group for daily job posts
#paid promotion
85 483
🎯Qualcomm Off Campus Recruitment
Job Position:- IT Software Developer (UX/UI/Fullstack)
Job ID: 3058496
Qualification:- B.Tech
Batch:- 2019/2020/2021
Job Location:- Hyderabad, India
Department: Software Engineering
Salary Package:- As per Company Standards
Job Type:- Full-time
Last Date:- ASAP
Apply Now:- https://www.allcoding1.com/2024/02/qualcomm-off-campus-recruitment-2024.html?m=1
Telegram:- @allcoding1_official
85 483
def check_digit_position(s):
if s[0].isdigit() and not s[-1].isdigit():
return "Yes"
elif not s[0].isdigit() and s[-1].isdigit():
return "No"
else:
return "Invalid input"
input_str = input().strip()
print(check_digit_position(input_str))
