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allcoding1_official (@allcoding1_official) Ingliz til segmentidagi kanali faol ishtirokchi. Hozirda hamjamiyat 85 319 obunachidan iborat bo'lib, Texnologiyalar & Aralashmalar toifasida 1 499-o'rinni va Hindiston mintaqasida 3 457-o'rinni egallagan.

📊 Auditoriya ko‘rsatkichlari va dinamika

невідомо sanasidan buyon loyiha tez o‘sib, 85 319 obunachiga ega bo‘ldi.

27 Iyun, 2026 dagi oxirgi ma’lumotlarga ko‘ra kanal barqaror faollikka ega. Oxirgi 30 kunda obunachilar soni -1 441 ga, so‘nggi 24 soatda esa -91 ga o‘zgardi va umumiy qamrov yuqori darajada qolmoqda.

  • Tasdiqlash holati: Tasdiqlanmagan
  • Jalb etish (ER): Auditoriya o‘rtacha 2.61% darajada jalb etiladi. Nashrdan keyingi dastlabki 24 soatda kontent odatda umumiy obunachilar sonining 0.84% ini tashkil etuvchi reaksiyalarni to‘playdi.
  • Post qamrovi: Har bir post o‘rtacha 2 230 marta ko‘riladi; birinchi sutkada odatda 713 ta ko‘rish yig‘iladi.
  • Reaksiyalar va o‘zaro ta’sir: Auditoriya faol: har bir postga o‘rtacha 3 ta reaksiya keladi.
  • Tematik yo‘nalishlar: Kontent dsa, stack, namaste, javascript, dev kabi asosiy mavzularga jamlangan.

📝 Tavsif va kontent siyosati

Kanal uchun tavsif kiritilmagan.

Yuqori yangilanish chastotasi (oxirgi ma’lumot 28 Iyun, 2026 da olingan) sababli kanal doimo dolzarb va katta qamrovli bo‘lib qoladi. Analitika auditoriya kontent bilan faol hamkorlik qilishini, uni Texnologiyalar & Aralashmalar toifasidagi muhim ta’sir nuqtasiga aylantirishini ko‘rsatadi.

85 319
Obunachilar
-9124 soatlar
-3487 kunlar
-1 44130 kunlar
Postlar arxiv
Python
+1
Python

Python
+1
Python

Java
+1
Java

def construct_graph(n):     graph = [[] for _ in range(n+1)]     for i in range(2, n+1):         for j in range(2*i, n+1, i):             graph[i].append(j)             graph[j].append(i)     return graph def dfs(node, graph, visited):     visited.add(node)     for neighbor in graph[node]:         if neighbor not in visited:             dfs(neighbor, graph, visited) def count_groups(n):     graph = construct_graph(n)     visited = set()     groups = 0     for i in range(2, n+1):         if i not in visited:             groups += 1             dfs(i, graph, visited)     return groups Social Network Python Telegram:- @allcoding1

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Python Simply Equal Qsn Telegram :-

Java Code Tata Steel
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Java Code Tata Steel

photo content
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None of these
None of these

$800
$800

6
6

66 kg
66 kg

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Qpvy Telegram:- @allcoding1_official

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