Codehub
Kanalga Telegram’da o‘tish
📈 Telegram kanali Codehub analitikasi
Codehub (@pythonadvisorai) Ingliz til segmentidagi kanali faol ishtirokchi. Hozirda hamjamiyat 31 547 obunachidan iborat bo'lib, Texnologiyalar & Aralashmalar toifasida 4 204-o'rinni va Malayziya mintaqasida 1 033-o'rinni egallagan.
📊 Auditoriya ko‘rsatkichlari va dinamika
невідомо sanasidan buyon loyiha tez o‘sib, 31 547 obunachiga ega bo‘ldi.
25 Oktabr, 2026 dagi oxirgi ma’lumotlarga ko‘ra kanal barqaror faollikka ega. Oxirgi 30 kunda obunachilar soni -447 ga, so‘nggi 24 soatda esa -18 ga o‘zgardi va umumiy qamrov yuqori darajada qolmoqda.
- Tasdiqlash holati: Tasdiqlanmagan
- Jalb etish (ER): Auditoriya o‘rtacha 7.53% darajada jalb etiladi. Nashrdan keyingi dastlabki 24 soatda kontent odatda umumiy obunachilar sonining N/A% ini tashkil etuvchi reaksiyalarni to‘playdi.
- Post qamrovi: Har bir post o‘rtacha 0 marta ko‘riladi; birinchi sutkada odatda 0 ta ko‘rish yig‘iladi.
- Reaksiyalar va o‘zaro ta’sir: Auditoriya faol: har bir postga o‘rtacha 0 ta reaksiya keladi.
📝 Tavsif va kontent siyosati
Muallif resursni shaxsiy fikrni ifoda etish maydoni sifatida ta’riflaydi:
“Free Programming resources.”
Yuqori yangilanish chastotasi (oxirgi ma’lumot 26 Oktabr, 2026 da olingan) sababli kanal doimo dolzarb va katta qamrovli bo‘lib qoladi. Analitika auditoriya kontent bilan faol hamkorlik qilishini, uni Texnologiyalar & Aralashmalar toifasidagi muhim ta’sir nuqtasiga aylantirishini ko‘rsatadi.
31 547
Obunachilar
-1824 soatlar
-1067 kun
-44730 kun
Postlar arxiv
31 542
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31 542
import turtle
turtle.bgcolor("black")
squary = turtle.Turtle()
squary.speed(20)
squary.pencolor("red")
for i in range(400):
squary.forward(i)
squary.left(91)
31 542
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31 542
Source Code of Getting WiFi Passwords 👇👇-
# importing subprocess
import subprocess
# getting meta data
meta_data = subprocess.check_output(['netsh', 'wlan', 'show', 'profiles'])
# decoding meta data
data = meta_data.decode('utf-8', errors ="backslashreplace")
# splitting data by line by line
data = data.split('\n')
# creating a list of profiles
profiles = []
# traverse the data
for i in data:
# find "All User Profile" in each item
if "All User Profile" in i :
# if found
# split the item
i = i.split(":")
# item at index 1 will be the wifi name
i = i[1]
# formatting the name
# first and last character is use less
i = i[1:-1]
# appending the wifi name in the list
profiles.append(i)
# printing heading
print("{:<30}| {:<}".format("Wi-Fi Name", "Password"))
print("----------------------------------------------")
# traversing the profiles
for i in profiles:
# try catch block begins
# try block
try:
# getting meta data with password using wifi name
results = subprocess.check_output(['netsh', 'wlan', 'show', 'profile', i, 'key = clear'])
# decoding and splitting data line by line
results = results.decode('utf-8', errors ="backslashreplace")
results = results.split('\n')
# finding password from the result list
results = [b.split(":")[1][1:-1] for b in results if "Key Content" in b]
# if there is password it will print the pass word
try:
print("{:<30}| {:<}".format(i, results[0]))
# else it will print blank in front of pass word
except IndexError:
print("{:<30}| {:<}".format(i, ""))
# called when this process get failed
except subprocess.CalledProcessError:
print("Encoding Error Occurred")
31 542
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31 542
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