Codehub
前往频道在 Telegram
📈 Telegram 频道 Codehub 的分析概览
频道 Codehub (@pythonadvisorai) 英语 语言赛道中的 是活跃参与者。目前社区聚集了 32 521 名订阅者，在 技术与应用 类别中位列第 3 985，并在 马来西亚 地区排名第 1 015 位。
📊 受众指标与增长动态
自 невідомо 创建以来，项目保持高速增长，吸引了 32 521 名订阅者。
根据 26 八月, 2026 的最新数据，频道保持稳定运转。过去 30 天订阅人数变化为 -431，过去 24 小时变化为 -5，整体触达仍然可观。
- 认证状态： 未认证
- 互动率 (ER)： 平均受众互动率为 3.42%。内容发布后 24 小时内通常能获得 N/A% 的反应，占订阅者总量。
- 帖子覆盖： 每篇帖子平均可获得 0 次浏览，首日通常累积 0 次浏览。
- 互动与反馈： 受众积极参与，单帖平均反应数为 0。
📝 描述与内容策略
作者将该频道定位为表达主观观点的平台：
“Free Programming resources.”
凭借高频更新（最新数据采集于 27 八月, 2026），频道始终保持新鲜度与高覆盖。分析显示受众积极互动，使其成为 技术与应用 类别中的关键影响点。
32 521
订阅者
-524 小时
-837 天
-43130 天
帖子存档
32 521
import turtle
turtle.bgcolor("black")
squary = turtle.Turtle()
squary.speed(20)
squary.pencolor("red")
for i in range(400):
squary.forward(i)
squary.left(91)
32 521
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32 521
Source Code of Getting WiFi Passwords 👇👇-
# importing subprocess
import subprocess
# getting meta data
meta_data = subprocess.check_output(['netsh', 'wlan', 'show', 'profiles'])
# decoding meta data
data = meta_data.decode('utf-8', errors ="backslashreplace")
# splitting data by line by line
data = data.split('\n')
# creating a list of profiles
profiles = []
# traverse the data
for i in data:
# find "All User Profile" in each item
if "All User Profile" in i :
# if found
# split the item
i = i.split(":")
# item at index 1 will be the wifi name
i = i[1]
# formatting the name
# first and last character is use less
i = i[1:-1]
# appending the wifi name in the list
profiles.append(i)
# printing heading
print("{:<30}| {:<}".format("Wi-Fi Name", "Password"))
print("----------------------------------------------")
# traversing the profiles
for i in profiles:
# try catch block begins
# try block
try:
# getting meta data with password using wifi name
results = subprocess.check_output(['netsh', 'wlan', 'show', 'profile', i, 'key = clear'])
# decoding and splitting data line by line
results = results.decode('utf-8', errors ="backslashreplace")
results = results.split('\n')
# finding password from the result list
results = [b.split(":")[1][1:-1] for b in results if "Key Content" in b]
# if there is password it will print the pass word
try:
print("{:<30}| {:<}".format(i, results[0]))
# else it will print blank in front of pass word
except IndexError:
print("{:<30}| {:<}".format(i, ""))
# called when this process get failed
except subprocess.CalledProcessError:
print("Encoding Error Occurred")
32 521
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32 521
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