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LeetCode, GeeksForGeeks Problem of the day solution

LeetCode, GeeksForGeeks Problem of the day solution

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Complete daily challenges from LeetCode, GeeksForGeeks and redeem their rewards Channel link : https://t.me/leetcode_gfg_potd

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Архів дописів
class Solution { public: bool isIsomorphic(string s, string t) { char mapS[128] = {0}; char mapT[128] = {0}; for(int i=0;i

LeetCode | Daily challenge :

class Solution { public: void inorder(Node* root,int &ans,int &k) { if(root==NULL)return; inorder(root->left,ans,k); ans=min(ans,abs(k-root->data)); k=root->data; inorder(root->right,ans,k); } int absolute_diff(Node *root) { //Your code here int ans=1e9,k=-1e9; inorder(root,ans,k); return ans; } };

GFG | Problem of the day :

class Solution { public: int lengthOfLastWord(string s) { string word= ""; int j; for(int i=s.length()-1;i>=0;i--){ if(s[i] != ' '){ j = i; break; } } for(int i=j;i>=0;i--){ if(s[i]==' '){ break; } else{ word = word + s[i]; } } return word.length(); } };

LeetCode | Daily challenge :

class Solution { public: vector<int> arr; int ans=0; void inorder(Node* root) { if(!root) return; inorder(root->left); arr.push_back(root->data); inorder(root->right); } void mergeSort(int i,int j) { if(i>=j)return; int m=i+(j-i)/2; mergeSort(i,m); mergeSort(m+1,j); int k=m+1, start=i; while(i<k and k<=j) { if(arr[i]<=arr[k])i++; else { ans+=m-i+1; k++; } } sort(arr.begin() + start, arr.begin() + j + 1); } int pairsViolatingBST(int n, Node *root) { inorder(root); mergeSort(0,n-1); return ans; } };

GFG | Problem of the day :

class Solution { public: long long countSubarrays(vector& nums, int minK, int maxK) { long long ans=0; int start=0, minStart, maxStart; bool minf=false, maxf=false; for(int i=0; imaxK){ minf=false; maxf=false; start= i+1; } if(num==minK){ minf=true; minStart=i; } if(num==maxK){ maxf=true; maxStart= i; } if(maxf && minf){ ans += (min(minStart,maxStart)-start+1); } } return ans; } };

LeetCode | Daily challenge :

class Solution { public: int findMaxForN(Node* root, int n) { int num=-1; while(root!=NULL){ if(root->key<=n){ num=root->key; root=root->right; } else{ root=root->left; } } return num; } };

GFG | Problem of the day :

class Solution { public: int subarraysWithKDistinct(vector& nums, int k) { return countK(nums, k) - countK(nums, k - 1); } private: int countK(vector& nums, int k) { unordered_map counter; int left = 0; int distinct_count = 0; int result = 0; for (int right = 0; right < nums.size(); ++right) { if (counter[nums[right]] == 0) { distinct_count++; } counter[nums[right]]++; while (distinct_count > k) { counter[nums[left]]--; if (counter[nums[left]] == 0) { distinct_count--; } left++; } result += right - left + 1; } return result; } };

LeetCode | Daily challenge :

class Solution { public: int minValue(Node* root) { if(root==NULL) return -1; while(root->left!=NULL) root=root->left; return root->data; } };

GFG | Problem of the day :

class Solution { public: long long countSubarrays(vector& nums, int k) { int maxi=0; for(int i=0;i

LeetCode | Daily challenge :

class Solution { public: bool isEularCircuitExist(int v, vectoradj[]){ for(int src=0; src

GFG | Problem of the day :