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LeetCode, GeeksForGeeks Problem of the day solution

LeetCode, GeeksForGeeks Problem of the day solution

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Complete daily challenges from LeetCode, GeeksForGeeks and redeem their rewards Channel link : https://t.me/leetcode_gfg_potd

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+224 години
+147 днів
+2930 день
Архів дописів
class Solution { public: void matchPairs(int n, char nuts[], char bolts[]) { unordered_map<char,int> mp; mp['^']=1; mp['@']=2; mp['?']=3; mp['*']=4; mp['&']=5; mp['%']=6; mp['$']=7; mp['#']=8; mp['!']=9; priority_queue<pair<int,char>> pq; for(int i=0; i<n; i++){ pq.push({mp[nuts[i]],nuts[i]}); } for(int i=0; i<n; i++){ nuts[i]=bolts[i]=pq.top().second; pq.pop(); } } };

GFG | Problem of the day :

class Solution { public: #define ll long long int subarraysDivByK(vector<int>& nums, int k) { vector<ll> mp(k); ll tot = 0; int ans = 0; mp[0] = 1; for(int num: nums){ tot += num; int mod = (tot % k + k) % k; mp[mod]++; } for (int n: mp) ans += (n * (n-1) * 0.5); return ans; } };

LeetCode | Daily challenge :

class Solution { public: void zigZag(int n, vector &arr) { for (int i = 0; i < n - 1; i++) { if (i % 2 == 0) { if (arr[i] > arr[i + 1]) { swap(arr[i], arr[i + 1]); } } else { if (arr[i] < arr[i + 1]) { swap(arr[i], arr[i + 1]); } } } } };

GFG | Problem of the day :

class Solution { public: bool checkSubarraySum(vector& nums, int k) { unordered_mapm; int sum=0; for(int i=0;i0) { return true; } if(m.find(rem)==m.end()) { m[rem]=i; } else if(i-m[rem]>=2) { return true; } } return false; } };

LeetCode | Daily challenge :

class Solution { public: int findExtra(int n, int arr1[], int arr2[]) { int i=0; int ans=0; while(ans==0){ ans=arr1[i]-arr2[i]; i++; } ans=i-1; return ans; } };

GFG | Problem of the day :

class Solution { public: string replaceWords(vector& dictionary, string sentence) { int count=0; string s,t; vectorv; for(int i=0;i

LeetCode | Daily challenge :

class Solution { public: // l and r are input array // maxx : maximum in r[] // n: size of array // arr[] : declared globally with size equal to maximum in l[] and r[] // Function to find the maximum occurred integer in all ranges. int maxOccured(int n, int l[], int r[], int maxx) { // Your code here unordered_mapx; unordered_mapy; vectorans(maxx+1,0); int answer = 0; int occ = 0; for(int i=0 ;iocc) { occ = ans[i]; answer = i; } } return answer; } };

GFG | Problem of the day :

class Solution { public: bool isNStraightHand(vector& hand, int groupSize) { int totalSize = hand.size(); if(totalSize % groupSize != 0) return false; map mp; for(auto it : hand) { mp[it]++; } while(mp.size()) { int num = mp.begin()->first; for(int i = 0; i < groupSize; i++) { if(mp[num+i]) { mp[num+i]--; if(mp[num+i] == 0) { mp.erase(num+i); } } else { return false; } } } return true; } };

LeetCode | Daily challenge :

class Solution { public: long long max_sum(int a[], int n) { long long s1 = 0; long long ts = 0; for (int i = 0; i < n; i++) { s1 += (long long)i * a[i]; ts += (long long)a[i]; } long long maxi = s1; for (int i = n - 1; i >= 1; i--) { s1 = s1 + ts - (long long)n * a[i]; if (maxi < s1) { maxi = s1; } } return maxi; } };

GFG | Problem of the day :

class Solution { public: vector commonChars(vector& words) { vector ans; map m2; for(char ch : words[0]){ m2[ch]++; } for(int i = 1; i < words.size(); i++){ map m1; for(char ch : words[i]){ m1[ch]++; } for(auto it = m2.begin(); it != m2.end();){ if(m1.find(it->first) != m1.end()){ it->second = min(it->second, m1[it->first]); ++it; } else { it = m2.erase(it); } } } for(auto it : m2){ string ch(1, it.first); int x = it.second; while(x--){ ans.push_back(ch); } } return ans; } };

LeetCode | Daily challenge :

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