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def solution(a,b):     res=a.count(b)     if res>0:         return res     else:         return 0     a=input()  b=input() print(solution(a,b))

n=int(input()) arr=list(map(int,input().split())) ev=[] od=[] for i in arr:     if i%2==0:         ev.append(i)     else:         od.append(i)         res=ev+od print(*res)

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#include <stdio.h> int main() { int e,r,n,t; scanf("%d %d %d", &e,&r,&n); int i; for(i=1;i<=n;i++) { if(i==1) t=e; else t=t*r; printf("%d ",t); } } @Coding_000 energy produced at n seconds code -c language

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