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def no_consecutive_ones(n: int) -> bool:       bin_n = bin(n)[2:]         for i in range(len(bin_n)-1):         if bin_n[i] == '1' and bin_n[i+1] == '1':             return False     return True m, n = map(int, input().split()) for i in range(m+1, n):     if no_consecutive_ones(i):         print(bin(i)[2:]) Python✅ Telegram - @Coding_000✅

import java.util.Scanner; public class Main { public static void main(String[] args) { Scanner sc = new Scanner(System.in); int start = sc.nextInt(); int end = sc.nextInt(); for (int i = start; i <= end; i++) { System.out.println(Integer.toBinaryString(i)); } } } Java ✅

import java.util.Scanner; public class Main { public static void main(String[] args) { Scanner sc = new Scanner(System.in); int start = sc.nextInt(); int end = sc.nextInt(); for (int i = start; i <= end; i++) { System.out.println(Integer.toBinaryString(i)); } } }

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