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Guys pls wait i will try to send...asap maximum answers....❤️

SELECT     DATE_FORMAT(dt, '%Y-%m') AS month_year,     'Jobs' AS source,     COUNT(*) AS total_number FROM jobs WHERE YEAR(dt) = 2022 GROUP BY month_year UNION ALL -- For freelancer registrations SELECT     DATE_FORMAT(dt, '%Y-%m') AS month_year,     'Freelancers' AS source,     COUNT(*) AS total_number FROM freelancers WHERE YEAR(dt) = 2022 GROUP BY month_year ORDER BY month_year, source; leading freelancer code ✅

Check above 👆👆 If ur unable to find the questions answer Share @coding_000❤️✅ send in comment 👇👇

Freelancer  code SELECT     DATE_FORMAT(DATE, '%Y-%m') AS month_year,     source,     SUM(total_number) AS total_number FROM (     SELECT         DATE(created_at) AS DATE,         'jobs' AS source,         COUNT(*) AS total_number     FROM JobPosts     WHERE YEAR(created_at) = 2022     GROUP BY DATE(created_at)         UNION ALL         SELECT         DATE(created_at) AS DATE,         'Freelancers' AS source,         COUNT(*) AS total_number     FROM Freelancers     WHERE YEAR(created_at) = 2022     GROUP BY DATE(created_at) ) AS t GROUP BY     DATE_FORMAT(DATE, '%Y-%m'),     source ORDER BY     DATE_FORMAT(DATE, '%Y-%m'),     source; Freelancer code 👆👆👆👆 Share @coding_000❤️

Check above 👆👆 If ur unable to find the questions answer Share @coding_000❤️✅ send in comment 👇👇

SELECT DATE_FORMAT(date_field, '%Y-%m') AS month_year, 'Jobs' AS source, COUNT(*) AS total_number FROM jobs GROUP BY month_ye
SELECT    DATE_FORMAT(date_field, '%Y-%m') AS month_year,    'Jobs' AS source,    COUNT(*) AS total_number FROM    jobs GROUP BY    month_year UNION ALL SELECT    DATE_FORMAT(date_field, '%Y-%m') AS month_year,    'Freelancers' AS source,    COUNT(*) AS total_number FROM    freelancers GROUP BY    month_year ORDER BY    month_year ASC,    source ASC; ✅✅ share @coding_000

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