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Job is important for everyone 🙂🙂 please try to help genuinely 🙂🙂🙂🙂 @Coding_000 Also share with your friends 🤝 @Coding_000 If more people join the channel will provide any coding solution for free here in the channel 💥💥💥@Coding_000 ✅Share✅Share✅Share ✅share✅

#include using namespace std; int main() {     int n,k;     vector v;     cin&gt
#include <bits/stdc++.h> using namespace std; int main() {     int n,k;     vector<int> v;     cin>>n;     for(int i=0;i<n;i++)     {         int t;         cin>>t;         v.push_back(t);     }     cin>>k;     sort(v.begin(),v.end());     cout<<v[k-1];         return 0; } c++ @Coding_000

Job is important for everyone 🙂🙂 please try to help genuinely 🙂🙂🙂🙂 @Coding_000 Also share with your friends 🤝 @Coding_000 If more people join the channel will provide any coding solution for free here in the channel 💥💥💥@Coding_000 ✅Share✅Share✅Share ✅share✅

int fun(int input1,int input2) { &nbsp;&nbsp;&nbsp; int l = input1; &nbsp;&nbsp;&nbsp; int r = input2; &nbsp;&nbsp;&nbsp; int
int fun(int input1,int input2) {     int l = input1;     int r = input2;     int ans = 0;     vector c(r+1,true);     c[0]=false;     c[1]=false;     for(int i = 2;i<= sqrt(r);i++)         for(int j = i*i;j<=r;j+=i)             c[j]=false;     for(int i = l;i<=r;i++)         if(c[i])             ans++;     return ans; }

def ncr(n,r): &nbsp;&nbsp;&nbsp; num=1 &nbsp;&nbsp;&nbsp; den=1 &nbsp;&nbsp;&nbsp; if r&gt;n or n&lt;0 or r&lt;0: &nbsp;&nbsp
def ncr(n,r):     num=1     den=1     if r>n or n<0 or r<0:         return 0     else:         for i in range(n,n-r,-1):             num=num*i         for j in range(1,r+1):             den=den*j     return num/den n=int(input()) r=int(input())

Job is important for everyone 🙂🙂 please try to help genuinely 🙂🙂🙂🙂 @Coding_000 Also share with your friends 🤝 @Coding_000 If more people join the channel will provide any coding solution for free here in the channel 💥💥💥@Coding_000 ✅Share✅Share✅Share ✅share✅

n=int(input()) l=list(map(int,input().split())) x=max(l) for i in range(n):     if(l[i] in l[:i]):         l[i]=x+1         x+=1 print(sum(l)) mr.mayer and the exam code -python

#include&nbsp; int main()&nbsp; {&nbsp; int x;&nbsp; scanf("%d",&amp;x);&nbsp; while(x--)&nbsp; {&nbsp; &nbsp; int n,op=0;&nb
#include<stdio.h>  int main()  {  int x;  scanf("%d",&x);  while(x--)  {    int n,op=0;    scanf("%d",&n);    int arr[n];    for(int i=0;i<n;i++)    {     scanf("%d",&arr[i]);    }    for(int i=0;i<n;i++)    {     if((arr[i]%2 ==0 && arr[i+1]%2 == 0) || (arr[i]%2 ==1 && arr[i+1]%2 ==1))     {      op++;     }    }    if(op==0)    {     printf("YES");    }    else    {     printf("NO");    }  }  } special array in c @Coding_000