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No descriptive
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#Day_3_Target_SBI_PO_mains_Gk_imp_sub_pdfs_Nihar
A, B and C entered into a business and initial
investment made by A is Rs. X, initial investment
made by C is Rs. 720 more than 45% of the
initial investment made by A and initial
investment made by B is Rs. 675 less than 1.75
times the initial investment made by A. After 7
months, A withdrew Rs. 270, B added Rs. 1350
more and C added Rs. 378 more. Profit share of
C at the end of the year, out of total profit share
of Rs. 34200 is Rs. 9000. B invested 80% of the
profit earned by him in two schemes P and Q in
the ratio of R: S respectively. Scheme P offers
simple interest of 30% p.a. while scheme Q
offers a compound interest of 20% p.a.
compounded annually. Total interest received
from scheme P at the end of 3 years is Rs. 1614
more than the interest received from scheme Q
at the end of 2 years. From the interest earned
by B from scheme Q, he bought an article and
sold it at a loss of 40% to D. D marked it 80%
above the price which he paid to B and sold it
after two successive discounts of Z% and (Z - 5)
% making a profit of Rs. 443.52
sиαρσnє🌱
1. Find the profit share of ‘A’ out of total profit?
A. Rs. 16200
B. Rs. 7500
C. Rs. 9000
D. Rs. 11200
E. None of these
2. Find the total interest earned by B from
scheme Q?
A. Rs. 6750
B. Rs. 4914
C. Rs. 3300
D. Rs. 5460
E. None
3. Find the value of Z?
A. 15
B. 10
C. 7.5
D. 17.5
E. 20
4. Find the ratio of R: S?
A. 90:121
B. 89:121
C. 91:125
D. 88:125
E. None
5. Find the interest earned by B if he invested
his whole profit in SI at Z% per annum for 3
years?
A. Rs.9210
B. Rs.9720
C. Rs.9840
D. Rs.9360
E. None
2 918
Detailed Solution:
P travels 20*20/100=4 hours by bus and 4/2 = 2
hours by train.
Let speed of the train is x.
So, 4*25+2*x=208
So, x= (208 – 100)/2 =54 km/hr.
So, the speed of the train is 54 km/hr.
Q, R, S and T travels 20*15/100=3,2,5 and 6
hours on the bus respectively.
Q travels distance = 3*30+1.5*54= 171 km
R travels = 30*2+54*1=114 km
S travels 40*5+54*2.5=335 km
T travels 25*6 +54*3=312 km
sиαρσnє🌱
1)
Speed of boat is 25*80/100=20
So, 64/(20–x) = 4
Or, 4x=80 – 64=16
Or, x= 4km/hr.
Speed of the stream is 4 km/hr. (C)
2)
Let length of the train is L
(140+L)/ (54*5/18) =20
Or, L=160
Let speed of another train is C
350/(15 – C)=70
Or, C=10 m/sec = 10*18/5=36 km/hr.
Required distance = 36*2.5=90 km. (D)
3)
Required sum = [5*25*120/100] + [2*40*90/100]
=222 km (B)
4)
Distance travel by Q and R = 171 – 114 = 57 km
Distance travel by S and T = 335 – 312 = 23 km
Required difference = 57 – 23= 34 km (D)
5)
Required difference = [312 +171] – [335+114] =
34km (A)
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2 918
2) If the Train cross a 140 long platform in 20 sec
and cross a 190 m long another train called A in
70 sec when they move in the same direction.
Find the distance covered by train A in the time
equivalent to the timein which S travels in the
train?
A. 35km
B. 75 km
C. 85 km
D. 90 km
E. 88 km
3) Find the sum of distance travel by Bus A in 5
hours at 20% more than its original speed and
distance travelled by bus C in 2 hours at 10%
less than its original speed?
A. 225 km
B. 222 km
C. 210 km
D. 230 km
E. None of these
sиαρσnє🌱
4) Find the difference between the difference of
distance travelled by Q and R and difference of
distance travelled by S and T?
A. 32 km
B. 31 km
C. 33 km
D. 34 km
E. None of these
5) Find the difference between total distance
travelled by Q and T together and R and S
together?
A. 34 km
B. 45 km
C. 52 km
D. 56 km
E. None of these
2 918
![#Day_2_Target_SBI_PO_mains_Gk_imp_sub_pdfs_Nihar There are five people [P, Q, R, S and T]. Each person travels at a different](https://cdn.tlmtr.io/_next/static/media/empty-channel.35ed232f.svg)
#Day_2_Target_SBI_PO_mains_Gk_imp_sub_pdfs_Nihar
There are five people [P, Q, R, S and T]. Each person travels at a different time in bus and train. The time
they travel by train is half of the time they travel in their respective Buses. P and T travel in bus A, R and
Q travel in bus B and S travel in Bus C. Speed of bus A, B and C is 25 km/hr, 30 km/hr and 40 km/hr.
They all travel in the same speed in train. Pie charts given below show the percentage distribution of total
time travel by each one in their respective bus. Sum of pie charts is 20 hours. Total distance covered by
P by both bus and train together is 208 km.
sиαρσnє🌱
1) Speed of a boat is 20% less than the speed of
bus A. Boat covers 64 km upstream in the same
time that P travels in Bus. Find the speed of the
stream?
A. 7km/hr
B. 5 km/hr
C. 4 km/hr
D. 2 km/hr
E. 3 km/hr
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Detailed Solution:
Let number of men and women visit park A is 4x
and 3x.
If Number of men visit park B is 9y, so number of
women visit park B is 9y*(100-11.11)/100=8y.
If Number of men visit park E is 15z, Number of
women visit park E is 15z*(100+6.66)/100=16z.
4x+9y=219, 3x+16z=170, 8y+16z=168
170-3x=168-8y
Or, 3x-8y=2
By solving above equation, we get x=30, y=11
and z=5.
Number of children visits park A =
120*10/100=12
Number of children visits park C = 12+6=18
Number of children visits park B = [12+18]/2=15
Number of children visits Park E =
15*120/100=18
sиαρσnє🌱
1) Answer: C
Required average age =
[12*8+15*7+18*5]/45=291/45=6.46
2) Answer: D
Required difference = [120+99+100]-[90+85+80]
=64
3) Answer: B
Let us check value of B,
40*120/100+30*90/100+20*15/100=78
4) Answer: A
Total revenue earned by the park =
100*25+90*20+18*10=Rs.4480
5) Answer: A
Required ratio = [120+90+12]:[100+90+18]
=222:208 =111:104
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#Day_1_Target_SBI_PO_mains_Gk_imp_sub_pdfs_Nihar
There are five parks [A, B, C, D and E]. Different numbers of men, women and children visit the park. Ratio of the number of men and women visits park A is 4:3. Number of men comes to the park C is one more than the number of men comes to the park B. Number of women comes to the park A and C is same. Total number of women that comes to park B and E together is 168. Number of women that comes to park E is
6.66% more than the number of men that comes to the same park. Number of children comes to park C is 6 more than the number of children comes to park A. Number of children comes to park B is average of number of children comes to
park A and C together. Number of women comes to park B is 11.11% less than the number of men comes to park B. Number of children comes to park E is 20% more than number of children comes to park B. Number of men comes to park
D is 5 less than the number men to park E and number of women comes to park D is 5 more
than the number of women to park E. Number of children comes to park A and D is same. Total number of men that comes to park A and B
together is 219 and the total number of women that comes to park A and E together is 170.
Number of children visiting in A is 10% of the number of men visits in park A.
sиαρσnє🌱
1) Average age of children visiting park A is 8
years old,park B is 7 years old and park C is 5 years old. Find the average age of all the children together who visit these three parks?
A. 9.46
B. 5.46
C. 6.46
D. 7.46
E. 8.46
2) Find the difference between the total number of men visits park A, B and C together and the number of women visits park C, D and E together?
A. 82
B. 85
C. 67
D. 64
E. 72
3) Sum of _% men visits A, % women visits C and _%children visits B is 78. Find which combination of values is satisfied?
A. 45,20,30
B. 40, 30, 20
C. 60,40,10
D. 40,40,40
E. None of these
4) Entry fee of men in the park C is Rs.25, for women is Rs.20 and for children is Rs.10. Find the total revenue earned by the park C?
A. Rs.4480
B. Rs.4250
C. Rs.4630
D. Rs.4760
E. None of these
5) Find the ratio between the total number of people [men+ women+children] visiting A and
the total number of people visiting C?
A. 111:104
B. 111:103
C. 101:106
D. 131:107
E. None of these
2 918
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Tentative Calendar 2023-24 OUT ( IBPS )
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🚦SBI CLERK MAINS 2022-23 2nd SHIFT ATTEMPTS 🚥
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🌻 SBI CLERK MAINS 2022-23 1st SHIFT ATTEMPTS 🌻
Join➺ @Banking_encyclopedia_by_Nihar
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Recruitment of Assistant Administrative Officers (Generalist)
🎯VACANCIES :300
🎯Date of Pre :-17 Feb,20 Feb
🎯Dates of Main:-18.03.2023
🎯Age Minimum:21 years
Maximum:- 30 years
(as on 01.01.2023)
*English Language test will be of qualifying nature and the marks in English Language will not be counted for ranking.
2 918
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📚Important Days and Themes
🍃 JANUARY 2022
🌀 FEBRUARY 2022
🌻 MARCH 2022
💱 APRIL 2022
🌝 MAY 2022
🕰 JUNE 2022
🍕 JULY 2022
🍭 AUGUST 2022
✨ SEPTEMBER 2022
🌸 OCTOBER 2022
🌱 NOVEMBER 2022
❄ DECEMBER 2022
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#Daystheme
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This data is from the Henley Passport Index, which used data from the International Air Transport Association (IATA) to launch the list of the most powerful passports for 2023.
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#henleypassportindex2023
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♥️ 80th Golden Globe Awards
CATEGORY WINNERS
🎬 Best Actor in a Motion Picture, Drama : Austin Butler (For “Elvis”)
🎬 Best Actress in a TV Series Drama : Zendaya
🎬 Best Motion Picture, Drama: The Fabelmans
🎬 Best Motion Picture, Musical or Comedy : “The Banshees of Inisherin”
🎬 Best TV Series, Drama : “House of the Dragon”
🎬 Best Director, Motion Picture : Steven Spielberg (For The Fabelmans)
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🎬 Best Motion Picture, Animated : “Guillermo del Toro’s Pinocchio
🇮🇳 ♥️✌ Best Original Song, Motion Picture " : “Naatu Naatu,” “RRR”
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#goldenglobeawards2023
2 918
Number of Reebok shoes in store A is 220.
Number of Reebok shoes in store B = 370 – 220
= 150.
Number of Adidas shoes in A = 180.
Number of Nike shoes in store A = X = 520 –
180 – 220 = 120
Total number of Nike shoes in store B = 350 –
120 – 130 = 100
Total number of Nike shoes in store D = 100 * 2
= 200
Let number of Nike and Adidas shoes in store E
is 7j and 10j.
17j = 520 – 180 = 340
Or, j = 20
Total number of Nike and Adidas shoes in store
E = 7 * 20 = 140 and 10 * 20 = 200.
sиαρσnє🌱
6.
So, Y - X = 220 – 120 = 100 (C)
7.
Required value = M + Z – N = 225 + 160 – 180 =
205 (D)
8.
Required difference = [180 + 220 + 140 + 225 +
200] - [220 + 150 + 160 + 250 + 180] = 5 (B)
9.
Required ratio = [100 + 220 + 150]: [140 + 200 +
180] = 470:520 = 47:52 (A)
10.
Required percentage = [(220 + 180)/ (100 +
130)] * 100 = 173.91% (A)
2 918
Detailed Solution:
Total number of Reebok shoes in store C = 960
– 370 – 250 - 180 = 160 = Z.
Let, the number of Nike and Adidas shoes in
store C is 13i and 14i.
So, 27i = 430 – 160 = 270
So, Number of Nike and Adidas shoes in store C
is 130 and 140 respectively.
According to the question, Y + M = 445
Y + Y + 5 = 445
Or, Y = 220
So, M = 225
2 918
Detailed Solution:
Average temperature in the month of March in
Chennai = 38 – 1 = 37
Average temperature in the month of March in
Bangalore = 70 – 37 = 33
Average temperature in the month of March in
Mumbai = 33.5 * 2 – 35 = 32
Average temperature in the month of March in
Delhi = 32 + 2 = 34 = Average temperature of
Bangalore in the month of April.
Average temperature in the month of April in
Delhi = 35 + 1 = 36
Average temperature in the month of April in
Kolkata = 34 + 2 = 36
sиαρσnє🌱
1.
Required difference = [35 + 36]/2 – [36 + 34]/2 =
0.5 (C)
2.
Average temperature in the month of March in
Hyderabad = 36
Average temperature in the month of April in
Hyderabad = 36 * 8/9 = 32
Required sum = 32 + 36 = 68 (D)
3.
Required difference = [35 + 36] – [35 + 32] = 4 (B)
4.
Average temperature in the month of May in
Bangalore = [15 * 34.5 + 16 * 35]/31 = 34.75
So, required average = [33 + 34 + 34.75]/3 =
33.91 (A)
5.
Average temperature of all cities in the month of
March = [32 + 34 + 37 + 33 + 35]/5 = 34.2
Average temperature of all cities in the month of
April = [35 + 36 + 38 + 34 + 36]/5 = 35.8
Required percentage = [(35.8 – 34.2)/35.8] x
100 = 4.5 (approx.) (A)
2 918
#Day_25_Target_SBI_PO_Clerk_mains_Gk_imp_sub_pdfs_Nihar
In five stores [A, B, C, D and E] three company
shoes are there [ Nike, Adidas and Reebok].
Number of Nike shoes in store A is X. Total
number of shoes in store A is 520. Number of
Adidas shoes in store B is Y, which is equal to
the number of Reebok shoes in store A. Total
number of Reebok shoes in all five stores is 960.
Sum of Reebok shoes in stores A and B is 370.
Ratio between the number of Nike and Adidas
shoes in store C is 13:14. Number of Reebok
shoes in store C is Z. Number of Adidas shoes in
store D is M, which is 5 more than the number of
adidas shoes in store B. Total number of shoes
in store E is 520. Total number of Reebok shoes
in stores D and E is 250 and 180 respectively.
Total number of shoes in store C is 430. Total
number of Adidas shoes in stores B and D
together is 445. Total number of Reebok shoes
in store E is N, which is equal to the number of
Adidas shoes in store A. Total number of Nike
shoes in stores A, B and C together is 350.
Number of Nike shoes in store D is double of
number of Nike shoes in store B. Ratio between
the number of Nike and Adidas shoes in store E
is 7:10.
sиαρσnє🌱
6) Find the value of Y – X =.
a) 110
b) 130
c) 100
d) 120
e) 160
7) Find the value of M + Z - N.
a) 230
b) 215
c) 220
d) 205
e) 225
8) Find the difference between the total number
of Adidas shoes in all the stores together and the
total number of Reebok shoes in all the stores
together.
a) 35
b) 5
c) 25
d) 15
e) None of these
9) Find the ratio between the total number of
shoes in store B of all companies together and
total number of shoes in store E of all companies
together.
a) 47:52
b) 47:53
c) 41:50
d) 5:9
e) None of these
10) Total number of Reebok shoes in stores A
and E together is approximately what percent of
total number of Nike shoes in stores B and C
together?
a) 173.91%
b) 213.32%
c) 202.32%
d) 172.32%
e) None of these
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a) Average temperature of Bangalore in the month of April is equal to the average temperature of Delhi in
the month of March.
b) Average temperature of Delhi and Kolkata in the month of April is equal.
c) Average of average temperature of Mumbai in two months is 33.5.
d) Average temperature of Delhi in the months of March and April is 2 and 1 degree more than the
average temperature of Mumbai in the months of March and April respectively.
d) Average temperature in Chennai in the month of March is 1 degree less than in the month of April.
e) Average temperature of Chennai and Bangalore together in the month of March is 70.
a) Average temperature of Kolkata in the month March is equal to the Average temperature of Mumbai in
the month April.
b) Average temperature of Kolkata in the month of April is 2 degrees more than the average temperature
of Bangalore in the month of April.
sиαρσnє🌱
1) Find the difference between the average of
average temperature in the months of April and
March together in Delhi and the average of
average temperature in the months of March and
April together in Kolkata.
a) 0.9
b) 0.6
c) 0.5
d) 1.2
e) 2
2) Ratio of average temperature in the months of
April and March in the city of Hyderabad is 8:9.
Average temperature in the month of March in
the city Hyderabad is equal to the average
temperature in the month of April in Kolkata. Find
the total average temperature of Hyderabad in
both the months together.
a) 64
b) 60
c) 69
d) 68
e) 67
3) Find the difference between the average
temperature of Kolkata in the months of March
and April together and average temperature of
Mumbai in the months of March and April
together?
a) 1
b) 4
c) 3
d) 2
e) None of these
4) The average temperature in Bangalore during
the first 15 days of May is 34.5 and in the next 16
days it is 35. Then find the average of average
temperature of Bangalore in the months of
March, April and May together.
a) 33.91
b) 34.23
c) 35.33
d) 33.01
e) None of these
5) Average of average temperature of all cities
in the month of March together is approximately
what percent more or less than that of average of
average temperature of all cities in the month of
April together?
a) 4.5
b) 4.7
c) 4.9
d) 5.1
e) None of these
