QUANTessential👑

✌ What approximate value will come in place of the question mark(?)in the following question? (You are not expected to calculate the exact value) 1) ? ÷ 2.997 + 799.98 × 8.9 = 9199.978 A. 6000 B. 5000 C. 4000 D. 4800 E. 6400 2) 49.99% of 6400.002 ÷ 999.99 = ? A. 3.6 B. 5 C. 4.8 D. 2.4 E. 3.2 3) 468.02 + 79.91 ÷ 5.01 = ?^2 A. 12 B. 11 C. 18 D. 22 E. 24 4) (1110.02 + 89.81) ÷ ? – √15 = 15.98 A. 60 B. 120 C. 80 D. 75 E. 40 5) ? × 350.01 ÷ 3.992 = 983 ÷ 14.001 A. 1.2 B. 1.8 C. 2.8 D. 3.2 E. 4 Join: @Quant_Genius

ATQ, (100-25)% of Boys = Total number of girls ⇒ 75% of B= G ⇒ Boys : Girls = 4 : 3 Let number of Boys & girls respectively 4x , 3x ⇒ 60% of 3x – 25% of 4x = 40 ⇒ X= 50 So number of boys & girls= (3x + 4x) = 7× 50 = 350

ATQ, (100-25)% of Boys = Total number of girls 75% of B= G ⇒ Boys : Girls = 4 : 3 Let number of Boys & girls respectively 4x , 3x % = (60% of 3x - 25% of 4x)/ 25% of 4x 80 ans

🏦 IBPS PO || SBI PO 🏦 🌀) 25% of the boys and 60% of the girls from a college participated in an event. Total number of girls in the college is equal to the number of boys, who do not participate in the event. 1) The number of girls, who participated in the event is what percent more than the number of boys, who participated in the event? ANSWER 2) If the difference the number of boys and girls, who participated in the event is 40, then the total number of boys and girls in the college is ? ANSWER 🌀 I. X^ 3= 125 II.Y^ 3= 8 A. X > Y B. X < Y C. X ≥ Y D. X ≤ Y E. X = Y or no relation can be established I. X^2 = 92 II. (Y – 8)^2 = 9 A. X > Y B. X < Y C. X ≥ Y D. X ≤ Y E. X = Y or no relation can be established Join : @Quant_Genius

322 – 160 = 162 162 – 80 = 82 82 – 40 = 42 42 – 20 = 22 22 – 10 = 12 B📌

322 – 160 = 162 162 – 80 = 82 82 – 40 = 42 42 – 20 = 22 22 – 10 = 12 B📌

D 2 × 5 + 5 = 15 15 × 4 + 4 = 64 64 × 3 + 3 = 195 195 × 2 + 2 = 392 392 × 1 + 1 = 393

162 – 37 = 125 125 – 31 = 94 94 – 29 = 65 65 – 23 = 42 42 - 19 = 23 B

33 + (2^2– 1) = 36 36 + (3^2– 1) = 44 44 + (4^2– 1) = 59 59 + (5^2 – 1) = 83 83 + (6^2- 1) = 118 B📌

Missing number series? 33, 36, 44, 59, ?, 118 A. 77 B. 83 C. 94 D. 88 E. 103

Let total =100 on rent = 10% Given to mother = 25% Remaining salary amount = 100 – (10+25) = 65% Salary amount to friend = 1/5 of 65 = 13% Reaming salary amount = 65 – 13 = 52% ATQ, 52% - 25%= 11340 27%= 11340 100% = ? Total= 42000 Now ans = 42000×52/100= 21840

lt=160 m It crossed the platform of length 120 m in 20 seconds. So Speed = (160+120)/20 =14 m/s Since speed of both the trains are equal hence speed of the second train is also 14 km/h so, now its speed = lt/10 Lt/10 =14 Lt = 140 m So, the first and second train will cross each other in time = (160+140)/28 = 75/7 seconds.

Pi×b^2- Pi×a^2=374 b^2- a^2= 119 (b-a)(b+a)= 119 Also b-a= 7........1 So b+a=17......2 From 1 and 2 b= 12 larger a= 5 smaller

Sd = 23/2 Sd/Su= 3/2 3--23/2 1---23/6 Su= 23/3 Tu= 46×3/23=6hr

QUESTION (🙄 WORD PROBLEM) 1) A toy is in the form of a cone surmounted on a hemisphere. The radius of the hemisphere and the cone is 3 cm each, the height of the conical part of the toy is 4 cm. What is the total surface area of the toy? A. 102.25cm2 B. 103.71cm2 C. 106 cm2 D. 110 cm2 2) A train, 160 m long, crossed 120 m platform in 20 seconds and another train travelling at the speed same speed crossed an electric pole in 10 seconds. In how many seconds will they cross each other when they are travelling in the opposite direction. A. 15 seconds B. 12 seconds C. 25/2 seconds D. 75/7 seconds 3) Two circles touch each other internally. The area bounded between them is 374 cm2. If the distance between their centers is 7cm, find the radius of the smaller circle. (π = 22/7) A. 4 cm B. 5 cm C. 6 cm D. 7cm 4) A boat travel 23 km downstream in 2 hours. If ratio of downstream speed to upstream speed is 3 : 2 find the time taken by boat to travel 46 km upstream. A. 5 hours B. 6 hours C. 4.5 hours D. 5.5 hours E. 7 hours 5) A person spent 10% of his salary in rent. He also gives 25% of his salary to his mother for household expenses. After giving money to his mother one-fifth of his remaining salary to his friend and deposited the remaining salary in a bank. If the difference between the amount of money deposited in the bank and the amount given to his mother is Rs. 11340, find the amount deposited in the bank. A. Rs. 24320 B. Rs. 18510 C. Rs. 17990 D. Rs. 23480 E. Rs. 21840 JOin : @Quant_Genius

Ssa+su= 200 Ssa=75 Ssu=125 Ssa/vsa= 5/6 5---75 1---15 Vsa= 6×15=90 Ksa+ vsa= 144 Ksa+ 90=144 Ksa=54 Ssa+ ksu= Ssu 75+ ksu= 125 Ksu= 50 Vsa - Vsu= 22 90-22=Vsu 68=Vsu Final result Suturday (su) Sunday(su) S=75 S=125 K=54 K=50 V=90 V=68