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https://t.me/Coding_solution_0 n = int(input()) a = list(map(int,input().split())) c = 0 for i in range(n-1): for j in range(i+1:n): s1 = sum(list(map(int,bin(i)[2:].split()))) s2 = sum(list(map(int,bin(j)[2:].split()))) if s1 == s2: c += 1 print(c) Python Bob and Numbers Code Telegram- https://t.me/Coding_solution_0

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class Solution: def calculateMinimumHP(self, dungeon: List[List[int]]) -> int: def oneIfNotPos(a): return a if a > 0 else 1 def f(i: int, j: int) -> int: cached = self.cache.get((i, j)) if cached: return cached answer = min(oneIfNotPos(f(i, j + 1) - dungeon[i][j]), \ oneIfNotPos(f(i + 1, j) - dungeon[i][j])) self.cache[(i, j)] = answer return answer m = len(dungeon) n = len(dungeon[0]) # init cache to remove ifs from f self.cache = {(m - 1, n - 1): oneIfNotPos(1 - dungeon[m - 1][n - 1])} for i in range(0, m): self.cache[(i, n)] = 1000 000000 # inf for j in range(0, n): self.cache[(m, j)] = 10000 00000 # inf return f(0, 0) Python Dungeon Hunters Telegram -https://t.me/Coding_solution_0

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