uk
Feedback

Не попадись на ботовода! Telemetrio знаходить і позначає такі канали мітками 👉 Хочеш бачити мітку, оформляй підписку

allcoding1_official

allcoding1_official

Відкрити в Telegram

📈 Аналітичний огляд Telegram-каналу allcoding1_official

Канал allcoding1_official (@allcoding1_official) у мовному сегменті Англійська є активним учасником. На даний момент спільнота об'єднує 78 690 підписників, посідаючи 1 624 місце в категорії Технології та додатки та 3 768 місце у регіоні Індія.

📊 Показники аудиторії та динаміка

З моменту свого створення невідомо, проект продемонстрував стрімке зростання, зібравши аудиторію у 78 690 підписників.

За останніми даними від 31 жовтня, 2026, канал демонструє стабільну активність. Хоча за останні 30 днів спостерігається зміна кількості учасників на -1 635, а за останні 24 години на -91, загальне охоплення залишається високим.

  • Статус верифікації: Не верифікований
  • Рівень залученості (ER): Середній показник залученості аудиторії становить 1.60%. Протягом перших 24 годин після публікації контент зазвичай збирає 0.61% реакцій від загальної кількості підписників.
  • Охоплення публікацій: В середньому кожен допис отримує 1 263 переглядів. Протягом першої доби публікація в середньому набирає 481 переглядів.
  • Реакції та взаємодія: Аудиторія активно підтримує контент: середня кількість реакцій на один пост – 0.
  • Тематичні інтереси: Контент зосереджений навколо ключових тем, таких як dsa, stack, namaste, javascript, dev.

📝 Опис та контентна політика

Опис каналу не надано.

Завдяки високій частоті оновлень (останні дані отримано 01 листопада, 2026), канал підтримує актуальність та високий рівень охоплення публікацій. Аналітика показує, що аудиторія активно взаємодіє з контентом, що робить його важливою точкою впливу в категорії Технології та додатки.

78 690
Підписники
-9124 години
-3887 днів
-1 63530 днів
Архів дописів
Question
import java.util.*;

public class LiquidFlowSimulation {
    public static void main(String[] args) {
        Scanner scanner = new Scanner(System.in);
        
        int n = scanner.nextInt();
        int[][] grid = new int[n][n];
        
        for (int i = 0; i < n; i++) {
            for (int j = 0; j < n; j++) {
                grid[i][j] = scanner.nextInt();
            }
        }
        
        simulateLiquidFlow(grid, n);
    }
    
    public static void simulateLiquidFlow(int[][] grid, int n) {
        int waterLevel = grid[n/2][n/2];
        boolean[][] visited = new boolean[n][n];
        
        while (true) {
            if (flowWater(grid, n, waterLevel, n/2, n/2, visited)) {
                break;
            } else {
                waterLevel++;
            }
        }
        
        printOutput(grid, n);
    }
    
    public static boolean flowWater(int[][] grid, int n, int waterLevel, int row, int col, boolean[][] visited) {
        if (row < 0 || row >= n || col < 0 || col >= n || visited[row][col] || grid[row][col] > waterLevel) {
            return false;
        }
        
        visited[row][col] = true;
        grid[row][col] = waterLevel;
        
        if (row == 0 || row == n - 1 || col == 0 || col == n - 1) {
            return true;
        }
        
        return flowWater(grid, n, waterLevel, row-1, col, visited) ||
               flowWater(grid, n, waterLevel, row+1, col, visited) ||
               flowWater(grid, n, waterLevel, row, col-1, visited) ||
               flowWater(grid, n, waterLevel, row, col+1, visited);
    }
    
    public static void printOutput(int[][] grid, int n) {
        for (int i = 0; i < n; i++) {
            for (int j = 0; j < n; j++) {
                if (grid[i][j] >= n) {
                    System.out.print("W ");
                } else {
                    System.out.print(". ");
                }
            }
            System.out.println();
        }
 

It seems that you need help with implementing a simulation of liquid flow on a terrain grid in Java. Here's an example of how you can start solving this problem:
import java.util.*;

public class LiquidFlowSimulation {
    public static void main(String[] args) {
        Scanner scanner = new Scanner(System.in);
        
        int n = scanner.nextInt();
        int[][] grid = new int[n][n];
        
        for (int i = 0; i < n; i++) {
            for (int j = 0; j < n; j++) {
                grid[i][j] = scanner.nextInt();
            }
        }
        
        simulateLiquidFlow(grid, n);
    }
    
    public static void simulateLiquidFlow(int[][] grid, int n) {
        int waterLevel = grid[n/2][n/2];
        boolean[][] visited = new boolean[n][n];
        
        while (true) {
            if (flowWater(grid, n, waterLevel, n/2, n/2, visited)) {
                break;
            } else {
                waterLevel++;
            }
        }
        
        printOutput(grid, n);
    }
    
    public static boolean flowWater(int[][] grid, int n, int waterLevel, int row, int col, boolean[][] visited) {
        if (row < 0 || row >= n || col < 0 || col >= n || visited[row][col] || grid[row][col] > waterLevel) {
            return false;
        }
        
        visited[row][col] = true;
        grid[row][col] = waterLevel;
        
        if (row == 0 || row == n - 1 || col == 0 || col == n - 1) {
            return true;
        }
        
        return flowWater(grid, n, waterLevel, row-1, col, visited) ||
               flowWater(grid, n, waterLevel, row+1, col, visited) ||
               flowWater(grid, n, waterLevel, row, col-1, visited) ||
               flowWater(grid, n, waterLevel, row, col+1, visited);
    }
    
    public static void printOutput(int[][] grid, int n) {
        for (int i = 0; i < n; i++) {
            for (int j = 0; j < n; j++) {
                if (grid[i][j] >= n) {
                    System.out.print("W ");
                } else {
                    System.out.print(". ");
                }
            }
            System.out.println();
        }
    }
}
Telegram:- @allcoding1_official

import java.util.*; public class LiquidFlowSimulation { public static void main(String[] args) { Scanner scanner = new Scanner(System.in); int n = scanner.nextInt(); int[][] grid = new int[n][n]; for (int i = 0; i < n; i++) { for (int j = 0; j < n; j++) { grid[i][j] = scanner.nextInt(); } } simulateLiquidFlow(grid, n); } public static void simulateLiquidFlow(int[][] grid, int n) { int waterLevel = grid[n/2][n/2]; boolean[][] visited = new boolean[n][n]; while (true) { if (flowWater(grid, n, waterLevel, n/2, n/2, visited)) { break; } else { waterLevel++; } } printOutput(grid, n); } public static boolean flowWater(int[][] grid, int n, int waterLevel, int row, int col, boolean[][] visited) { if (row < 0 row >= n col < 0 col >= n visited[row][col] || grid[row][col] > waterLevel) { return false; } visited[row][col] = true; grid[row][col] = waterLevel; if (row == 0 row == n - 1 col == 0 || col == n - 1) { return true; } return flowWater(grid, n, waterLevel, row-1, col, visited) || flowWater(grid, n, waterLevel, row+1, col, visited) || flowWater(grid, n, waterLevel, row, col-1, visited) || flowWater(grid, n, waterLevel, row, col+1, visited); } public static void printOutput(int[][] grid, int n) { for (int i = 0; i < n; i++) { for (int j = 0; j < n; j++) { if (grid[i][j] >= n) { System.out.print("W "); } else { System.out.print(". "); } } System.out.println(); } } }

Given an elliptical ranch with dimensions 2*R units horizontally and 1 unit vertically, a goat is tied to the fence inside the ranch using a leash of length r units. The angle formed between the point of tying and the horizontal axis is θ. To determine the area of grass the goat can graze, the following inputs are provided as shown in the image below: R half of the horizontal dimension of the ranch, r the length of the leash, and θ the angle formed by the point of tying and the horizontal axis. Write a program that takes these three inputs as floating-point numbers on separate lines and prints the total area of grass the goat can graze, rounded to three decimal points. Example: Input: 0.75 0.25 310 Output: 0.091

Given an elliptical ranch with dimensions 2*R units horizontally and 1 unit vertically, a goat is tied to the fence inside the ranch using a leash of length r units. The angle formed between the point of tying and the horizontal axis is θ. To determine the area of grass the goat can graze, the following inputs are provided as shown in the image below: R half of the horizontal dimension of the ranch, r the length of the leash, and θ the angle formed by the point of tying and the horizontal axis. Write a program that takes these three inputs as floating-point numbers on separate lines and prints the total area of grass the goat can graze, rounded to three decimal points. Example: Input: 0.75 0.25 310 Output: 0.091

It seems that you need help with implementing a simulation of liquid flow on a terrain grid in Java. Here's an example of how you can start solving this problem:
import java.util.*;

public class LiquidFlowSimulation {
    public static void main(String[] args) {
        Scanner scanner = new Scanner(System.in);
        
        int n = scanner.nextInt();
        int[][] grid = new int[n][n];
        
        for (int i = 0; i < n; i++) {
            for (int j = 0; j < n; j++) {
                grid[i][j] = scanner.nextInt();
            }
        }
        
        simulateLiquidFlow(grid, n);
    }
    
    public static void simulateLiquidFlow(int[][] grid, int n) {
        int waterLevel = grid[n/2][n/2];
        boolean[][] visited = new boolean[n][n];
        
        while (true) {
            if (flowWater(grid, n, waterLevel, n/2, n/2, visited)) {
                break;
            } else {
                waterLevel++;
            }
        }
        
        printOutput(grid, n);
    }
    
    public static boolean flowWater(int[][] grid, int n, int waterLevel, int row, int col, boolean[][] visited) {
        if (row < 0 || row >= n || col < 0 || col >= n || visited[row][col] || grid[row][col] > waterLevel) {
            return false;
        }
        
        visited[row][col] = true;
        grid[row][col] = waterLevel;
        
        if (row == 0 || row == n - 1 || col == 0 || col == n - 1) {
            return true;
        }
        
        return flowWater(grid, n, waterLevel, row-1, col, visited) ||
               flowWater(grid, n, waterLevel, row+1, col, visited) ||
               flowWater(grid, n, waterLevel, row, col-1, visited) ||
               flowWater(grid, n, waterLevel, row, col+1, visited);
    }
    
    public static void printOutput(int[][] grid, int n) {
        for (int i = 0; i < n; i++) {
            for (int j = 0; j < n; j++) {
                if (grid[i][j] >= n) {
                    System.out.print("W ");
                } else {
                    System.out.print(". ");
                }
            }
            System.out.println();
        }
    }
}
This code takes the input of the terrain grid, simulates the flow of liquid according to the given rules, and then prints the output in the specified format. Please note that this is just a starting point, and you may need to further refine the code to handle various edge cases and optimize the solution. Let me know if you need further assistance!

public class Main { public static void main(String[] args) { int[] arr = {3, 3, 4, 7, 8}; int d = 5; System.out.println(getTr
+2
public class Main { public static void main(String[] args) { int[] arr = {3, 3, 4, 7, 8}; int d = 5; System.out.println(getTripletCount(arr, d)); } public static int getTripletCount(int[] arr, int d) { int count = 0; for (int i = 0; i < arr.length - 2; i++) { for (int j = i + 1; j < arr.length - 1; j++) { for (int k = j + 1; k < arr.length; k++) { if ((arr[i] + arr[j] + arr[k]) % d == 0) { count++; } } } } return count; } }

Questions....❓

import java.util.Scanner;

public class SubstringMinimization {
    public static void main(String[] args) {
        Scanner scanner = new Scanner(System.in);
        
        int N = Integer.parseInt(scanner.nextLine());
        String s = scanner.nextLine();
        int q = Integer.parseInt(scanner.nextLine());

        int[][] queries = new int[q][2];
        char[] characters = new char[q];

        for (int i = 0; i &lt; q; i++) {
            String[] queryStr = scanner.nextLine().split(" ");
            queries[i][0] = Integer.parseInt(queryStr[0]);
            queries[i][1] = Integer.parseInt(queryStr[1]);
        }

        String[] charStr = scanner.nextLine().split(" ");
        for (int i = 0; i &lt; q; i++) {
            characters[i] = charStr[i].charAt(0);
        }
        
        int[] result = solve(N, s, q, queries, characters);

        for (int res : result) {
            System.out.print(res + " ");
        }
    }

    public static int[] solve(int N, String s, int q, int[][] queries, char[] characters) {
        int[] ans = new int[q];

        for (int i = 0; i &lt; q; i++) {
            int left = queries[i][0] - 1;
            int right = queries[i][1] - 1;
            char x = characters[i];
            ans[i] = getMinLength(s, left, right, x);
        }

        return ans;
    }

    private static int getMinLength(String s, int left, int right, char x) {
        StringBuilder sb = new StringBuilder(s.substring(left, right + 1));
        boolean changed = true;

        while (changed) {
            changed = false;
            for (int i = 0; i &lt; sb.length() - 1; i++) {
                if (sb.charAt(i) == x &amp;&amp; sb.charAt(i + 1) == x) {
                    sb.delete(i, i + 2);
                    changed = true;
                    break;
                }
            }
        }

        return sb.length();
    }
}
Telegram:- @allcoding1_official

photo content
+6

Waiting

Send Questions

👍
👍

import java.util.ArrayList;
import java.util.Arrays;
import java.util.HashSet;
import java.util.List;
import java.util.Set;

public class RequestParser {
    
    public static List<string> getResponses(String[] validAuthTokens, String[][] requests) {
        List<string> responses = new ArrayList&lt;&gt;();

        Set<string> validTokensSet = new HashSet&lt;&gt;(Arrays.asList(validAuthTokens));
        
        for (String[] request : requests) {
            String requestType = request[0];
            String url = request[1];
            
            // Extract the token and other parameters from the URL
            String[] urlParts = url.split("\\?");
            String[] params = urlParts[1].split("&amp;");
            
            String token = null;
            String csrf = null;
            StringBuilder otherParams = new StringBuilder();
            
            for (String param : params) {
                String[] keyValue = param.split("=");
                if (keyValue[0].equals("token")) {
                    token = keyValue[1];
                } else if (keyValue[0].equals("csrf")) {
                    csrf = keyValue[1];
                } else {
                    otherParams.append(",").append(keyValue[0]).append(",").append(keyValue[1]);
                }
            }
            
            // Validate the authentication token
            if (!validTokensSet.contains(token)) {
                responses.add("INVALID");
                continue;
            }
            
            // Validate the request type and CSRF token for POST requests
            if (requestType.equals("POST")) {
                if (csrf == null || !csrf.matches("[a-z0-9]{8,}")) {
                    responses.add("INVALID");
                    continue;
                }
            }
            
            // If all validations pass, construct the response string
            if (otherParams.length() &gt; 0) {
                responses.add("VALID" + otherParams);
            } else {
                responses.add("VALID");
            }
        }
        
        return responses;
    }

    public static void main(String[] args) {
        String[] validAuthTokens = {"ah37j2ha483u", "safh34ywb0p5", "ba34wyi8t902"};
        String[][] requests = {
            {"GET", "https://example.com/?token=347sd6yk8iu2&amp;name=alex"},
            {"GET", "https://example.com/?token=safh34ywb0p5&amp;name=sam"},
            {"POST", "https://example.com/?token=safh34ywb0p5&amp;name=alex"},
            {"POST", "https://example.com/?token=safh34ywb0p5&amp;csrf=ak2sh32dy&amp;name=chri$"}
        };

        List<string> responses = getResponses(validAuthTokens, requests);
        System.out.println(responses);  // Output: [INVALID, VALID,name,sam, INVALID, VALID,name,chri$]
    }
}
Telegram:- @allcoding1_official Java

photo content
+3

Saks subarray product✅ long long solve(vector& nums, int k) {     if (k <= 1) return 0;     int n = nums.size();     long long p = 1;     int i = 0, j = 0;     long long ans = 0;     while (j < n) {         p *= nums[j];         while (i <= j && p > k) {             p /= nums[i];             i++;         }         ans += j - i + 1;         j++;     }     return ans; }

#include<bits/stdc++.h> using namespace std; vector<int> solve(int N, vector<int> a, int q, vector<vector<int>> queries) {     vector<int> res;     for(int i=0; i<q; i++) {         int T = queries[i][0];         int l = queries[i][1];         int r = queries[i][2];         int x = queries[i][3];         if(T == 1) {             int ans = a[l-1];             for(int j=l; j<r; j++) {                 ans |= a[j];             }             res.push_back(ans);         } else {             for(int j=l-1; j<r; j++) {                 a[j] ^= x;             }         }     }     return res; } int main() {     ios_base::sync_with_stdio(false);     cin.tie(NULL);     int N;     cin>>N;     vector<int> a(N);     for(int i=0; i<N; i++) {         cin>>a[i];     }     int q;     cin>>q;     vector<vector<int>> queries(q, vector<int>(4));     for(int i=0; i<q; i++) {         for(int j=0; j<4; j++) {             cin>>queries[i][j];         }     }     vector<int> res = solve(N, a, q, queries);     for(int i=0; i<res.size(); i++) {         cout<<res[i]<<" ";     }     cout<<endl;     return 0; } Array bitwise operations✅

#include using namespace std; class hm { &nbsp;&nbsp;&nbsp; unordered_map m; &nbsp;&nbsp;&nbsp; int k = 0, v = 0; public: &nb
#include<bits/stdc++.h> using namespace std; class hm {     unordered_map<int, int> m;     int k = 0, v = 0; public:     void i(int x, int y) {         x -= k;         y -= v;         m[x] = y;     }     int g(int x) {         x -= k;         if (m.find(x) == m.end()) {             return -1;         }         return m[x] + v;     }     void ak(int x) {         k += x;     }     void av(int y) {         v += y;     } }; int solve(vector<string>& qt, vector<vector<int>>& q) {     hm h;     int s = 0;     for (int i = 0; i < qt.size(); ++i) {         if (qt[i] == "insert") {             h.i(q[i][0], q[i][1]);         } else if (qt[i] == "addToKey") {             h.ak(q[i][0]);         } else if (qt[i] == "addToValue") {             h.av(q[i][0]);         } else if (qt[i] == "get") {             int v = h.g(q[i][0]);             if (v != -1) {                 s += v;             }         }     }     return s; } Telegram:-

#include <iostream> #include <vector> #include <unordered_map> class Main { public:     static long getZeroBitSubarrays(const std::vector<int>& arr) {         int n = arr.size();         long totalSubarrayCount = static_cast<long>(n) * (n + 1) / 2;         long nonzeroSubarrayCount = 0;         std::unordered_map<int, int> windowBitCounts;         int leftIdx = 0;         for (int rightIdx = 0; rightIdx < n; rightIdx++) {             int rightElement = arr[rightIdx];             if (rightElement == 0) {                 windowBitCounts.clear();                 leftIdx = rightIdx + 1;                 continue;             }             std::vector<int> setBitIndices = getSetBitIndices(rightElement);             for (int index : setBitIndices) {                 windowBitCounts[index]++;             }             while (leftIdx < rightIdx && isBitwiseAndZero(rightIdx - leftIdx + 1, windowBitCounts)) {                 for (int index : getSetBitIndices(arr[leftIdx])) {                     windowBitCounts[index]--;                     if (windowBitCounts[index] == 0) {                         windowBitCounts.erase(index);                     }                 }                 leftIdx++;             }             nonzeroSubarrayCount += (rightIdx - leftIdx + 1);         }         return totalSubarrayCount - nonzeroSubarrayCount;     } private:     static std::vector<int> getSetBitIndices(int x) {         std::vector<int> setBits;         int pow2 = 1;         int exponent = 0;         while (pow2 <= x) {             if ((pow2 & x) != 0) {                 setBits.push_back(exponent);             }             exponent++;             pow2 *= 2;         }         return setBits;     }     static bool isBitwiseAndZero(int windowLength, const std::unordered_map<int, int>& bitCounts) {         for (const auto& entry : bitCounts) {             if (entry.second >= windowLength) {                 return false;             }         }         return true;     } }; DE Shaw ✅ C++

🎯TCS National Qualifier Test (TCS NQT) 2024 Location: Across India Qualification: B.E / B.Tech / M.E / M.Tech / M.Sc / MCA / Any Graduate / Under Graduate / Diploma Batch: 2018/2019/2020/2021/2022/2023/2024 Apply Now:- www.allcoding1.com Telegram:- @allcoding1_official