Complete Coding by Prashant Sir

what will be the output of the following Pseudo Code. #include int main() { float i; i = 1; printf("%d",i); return 0; }

Function MyDisplay(string MyStr) //statement 1 { print “Hello !” print MyStr return 1 // statement 2 } function main() //statement 3 { string str= “Mickey” MyDisplay(str) // statement 4 } Which statement will generate an error .

Consider the following code: function modify(a,b) { Integer c,d=2 c= a*d+ b return c } function calculate() { integer a = 5, b = 20, c integer d= 10 c = modify(a, b); c = c+ d print c }

A 10-bit unsigned integer has the following range:

Given: integer x = 40, y = 35, z = 20, w = 10 Comment about the output of the following two statements: print x * y / z - w print x * y / (z - w)

What will be the output of the following code statements? integer a = 50, b = 25, c = 0 print ( a > 45 OR b > 50 AND c > 10 )

Is the value of a at the end of the program same as the beginning? #include int main(void) { int a = 100; char* b = (char*)&a; b[0] += 132; b[1] += 3; b[0] = (232 - 32) / 2; b[1] *= 0; printf("%d\n", a); }

What gets printed at the end of this program? #include int main(void) { int a = 20, b = 10; int *x = &a, *y = &b; int c = y[0], d = x[0]; x[0] = c; y[0] = d; printf("%d %d", *x, *y); }

Is the output of this code True or False? #include int main(void) { int b = 20; int* y = &b; char n = 'A'; char* z = &n; y[0] = z[0]; printf((*y == *z) ? "True" : "False"); }

What will be the output of the following pseudo-code statements: integer a = 456, b, c, d =10 b = a/d c = a - b print c

There is a new data-type which can take as values natural numbers between (and including) 0 and 25. How many minimum bits are required to store this datatype