ACCENTURE | COGNIZANT | IBM | CAPGEMINI

IBM CIC 6:30PM✅✅ Contact : @MLCODER2

IBM CIC 6:30PM SLOTS AVAILABLE✅✅ Contact : @MLCODER2

SLK SOFTWARE CODING✅✅ Contact :@MLCODER2

IBM CIC✅✅

IBM CIC SLOTS DONE & DUSTED✅✅ Contact : @MLCODER2

IBM CIC DONE & DUSTED✅✅ Contact : @MLCODER2

IBM 6PM CIC✅✅

CTS JAVA-CLUSTER✅✅ Contact : @MLCODER2

CTS PYTHON-CLUSTER✅✅ CONTACT : @mlcoder2

CTS JAVA CLUSTER✅✅ Contact : @MLCODER2

CTS PYTHON CLUSTER✅✅ Contact : @MLCODER2

IBM ON-CAMPUS EXAM✅✅ Contact : @MLCODER2

IBM CIC 6:30pm slots available ✅ Contact : @mlcoder2

EPAM EXAM✅✅ Contact : @MLCODER2

EPAM EXAM✅✅✅ Contact : @MLCODER2

ACCENTURE EXAM✅✅✅ contact : @MLCODER2

COMCAST DONE&DUSTED✅✅✅ Contact : @MLCODER2

def nCr(n,k): if k<0 or k>n: return 0 k=min(k,n-k) res=1 for i in range(1,k+1): res=res*(n-k+i)//i return res T=int(input().strip()) for i in range(T): parts=input().split() k=int(parts[0]) s=parts[1].strip() d=len(set(s)) print(nCr(d,k)) SPRINKLER✅✅

MICRON EXAM DONE & DUSTED✅✅ Contact : @MLCODER2