C Programming Language || Hands On Coding
Hands-on C programming language challenges for beginners. Learn building logic by solving programs. Owner: @Pradeep_saii
Больше📈 Аналитический обзор Telegram-канала C Programming Language || Hands On Coding
Канал C Programming Language || Hands On Coding (@c_programming_language_coding) языкового сегмента Английский является активным участником. Сейчас сообщество объединяет 12 818 подписчиков, занимая 9 567 место в категории Технологии и приложения и 30 989 место в регионе Индия.
📊 Показатели аудитории и динамика
С момента создания невідомо проект демонстрирует стремительный рост, собрав аудиторию из 12 818 подписчиков.
Согласно последним данным от 28 августа, 2026, канал показывает стабильную активность. За последние 30 дней изменение числа участников составило -213, а за последние 24 часа — -1, при этом общий охват остаётся высоким.
- Статус верификации: Не верифицирован
- Уровень вовлечённости (ER): Средний показатель вовлечённости аудитории составляет 6.87%. В первые 24 часа после публикации контент обычно набирает 2.42% реакций от общего числа подписчиков.
- Охват публикаций: В среднем каждый пост получает 881 просмотров. В течение первых суток публикация набирает 310 просмотров.
- Реакции и взаимодействия: Аудитория активно поддерживает контент: среднее количество реакций на один пост — 2.
- Тематические интересы: Контент сосредоточен на ключевых темах, таких как input, string, scanf("%d, array, element.
📝 Описание и контентная политика
Автор описывает ресурс как площадку для выражения субъективного мнения:
“Hands-on C programming language challenges for beginners. Learn building logic by solving programs.
Owner: @Pradeep_saii”
Благодаря высокой частоте обновлений (последние данные получены 29 августа, 2026) канал поддерживает актуальность и высокий уровень охвата публикаций. Аналитика показывает, что аудитория активно взаимодействует с контентом, что делает его важной точкой влияния в категории Технологии и приложения.
#include <stdio.h>
int main() {
int n, i = 1;
printf("Enter a number: ");
scanf("%d", &n);
do {
printf("%d ", i);
i++;
} while (i <= n);
printf("\n");
return 0;
}#include <stdio.h>
int main() {
int n, i = 1;
printf("Enter a number: ");
scanf("%d", &n);
while (i <= n) {
printf("%d ", i);
i++;
}
printf("\n");
return 0;
}#include <stdio.h>
int main() {
int n, i;
printf("Enter a number: ");
scanf("%d", &n);
for (i = 1; i <= n; i++) {
printf("%d ", i);
}
printf("\n");
return 0;
}
#include <stdio.h>
int main() {
int size = 5;
for (int i = 0; i < size; i++) {
for (int j = 0; j < size; j++) {
printf("* ");
}
printf("n");
}
return 0;
}
2. **Inverted Right-Angled Triangle:**
#include <stdio.h>
int main() {
int rows = 5;
for (int i = rows; i >= 1; i--) {
for (int j = 1; j <= i; j++) {
printf("* ");
}
printf("n");
}
return 0;
}
Practice Tips:
- Start with simple patterns and gradually increase the complexity.
- Break down the pattern into rows and columns.
- Identify the relationship between the row and column numbers and the characters to be printed.
- Draw the pattern on paper first to visualize the output.
Practice Problems:
- Print a hollow square pattern.
- Print a diamond pattern.
- Print a pyramid pattern.
- Print patterns with numbers or characters instead of ''.
🎉 Congratulations! You've taken the first steps into the world of loops and patterns in C. Keep practicing, and you'll be amazed at what you can create! Remember practice makes perfect. 👨💻
for (initialization; condition; increment/decrement) {
// Code to be executed repeatedly
}
Explanation:
1. `initialization`: This is executed only once at the beginning of the loop. Usually, it's used to declare and initialize a counter variable (e.g., `int i = 0;`).
2. `condition`: This is checked before each iteration of the loop. If the condition is true, the code inside the loop is executed. If it's false, the loop terminates. (e.g., `i < 10;`).
3. `increment/decrement`: This is executed after each iteration of the loop. It's usually used to update the counter variable (e.g., `i++`).
Example:
#include <stdio.h>
int main() {
for (int i = 0; i < 5; i++) {
printf("Iteration: %dn", i);
}
return 0;
}
Output:
```
Iteration: 0
Iteration: 1
Iteration: 2
Iteration: 3
Iteration: 4
```
✅ Good Practice: Use `for` loops when you know the number of iterations beforehand.
♾️ **2. `while` Loop**
The `while` loop executes a block of code as long as a condition is true. It's useful when you don't know the exact number of iterations.
Syntax:
while (condition) {
// Code to be executed repeatedly
}
Explanation:
The `condition` is checked before each iteration. If it's true, the code inside the loop is executed. If it's false, the loop terminates. ⚠️ Make sure the condition eventually becomes false, or you'll end up with an infinite loop!
Example:
#include <stdio.h>
int main() {
int i = 0;
while (i < 5) {
printf("Iteration: %dn", i);
i++; // Increment i to avoid an infinite loop
}
return 0;
}
Output:
```
Iteration: 0
Iteration: 1
Iteration: 2
Iteration: 3
Iteration: 4
```
✅ Good Practice: Use `while` loops when you need to repeat something until a certain condition is met.
💫 **3. `do-while` Loop**
The `do-while` loop is similar to the `while` loop, but it guarantees that the code inside the loop is executed at least once.
Syntax:
do {
// Code to be executed repeatedly
} while (condition);
Explanation:
The code inside the loop is executed first, and then the `condition` is checked. If the condition is true, the loop continues. If it's false, the loop terminates. Notice the semicolon (`;`) at the end of the `while` condition.
Example:
#include <stdio.h>
int main() {
int i = 0;
do {
printf("Iteration: %dn", i);
i++;
} while (i < 5);
return 0;
}
Output:
```
Iteration: 0
Iteration: 1
Iteration: 2
Iteration: 3
Iteration: 4
```
✅ Good Practice: Use `do-while` loops when you need to execute a block of code at least once, regardless of the initial condition.
🎨 **Patterns with Loops**
Now, let's combine loops to create patterns! This involves using nested loops (loops inside loops) to control the output.
Example: Printing a right-angled triangle
#include <stdio.h>
int main() {
int rows = 5;
for (int i = 1; i <= rows; i++) {
for (int j = 1; j <= i; j++) {
printf("* ");
}
printf("n");
}
return 0;
}
Output:
```
*
* *
* * *
* * * *
* * * * *
```
Explanation:
- The outer `for` loop controls the number of rows.
- The inner `for` loop controls the number of characters (in this case, ' ' )// Use switch for basic arithmetic operations
// Code will be generated in the interactive explainer
🔍 Get AI Explanation#include <stdio.h>
int main() {
int month;
printf("Enter month number (1-12): ");
scanf("%d", &month);
switch (month) {
case 1: case 3: case 5: case 7: case 8: case 10: case 12:
printf("31 days\n");
break;
case 4: case 6: case 9: case 11:
printf("30 days\n");
break;
case 2:
printf("28 or 29 days\n");
break;
default:
printf("Invalid month\n");
}
return 0;
}#include <stdio.h>
#include <string.h>
int main() {
char username[50];
char password[50];
printf("Username: ");
scanf("%s", username);
printf("Password: ");
scanf("%s", password);
if (strcmp(username, "admin") == 0) {
if (strcmp(password, "secret123") == 0) {
printf("Login successful!
");
} else {
printf("Incorrect password.
");
}
} else {
printf("Incorrect username.
");
}
return 0;
}#include <stdio.h>
int main() {
char ch;
printf("Enter a character: ");
scanf(" %c", &ch);
switch (ch) {
case 'a':
case 'e':
case 'i':
case 'o':
case 'u':
case 'A':
case 'E':
case 'I':
case 'O':
case 'U':
printf("%c is a vowel.\n", ch);
break;
default:
printf("%c is a consonant.\n", ch);
}
return 0;
}#include <stdio.h>
int main() {
char grade;
printf("Enter your grade (A/B/C/D/F): ");
scanf(" %c", &grade);
switch (grade) {
case 'A':
printf("Excellent! 🎉");
break;
case 'B':
printf("Good job! 👍");
break;
case 'C':
printf("Keep it up! 👏");
break;
case 'D':
printf("Needs improvement. 🤔");
break;
case 'F':
printf("Failed. 😔");
break;
default:
printf("Invalid grade. 😕");
}
printf("\n");
return 0;
}#include <stdio.h>
int main() {
int day = 4;
switch (day) {
case 1:
printf("Monday");
break;
case 2:
printf("Tuesday");
break;
case 3:
printf("Wednesday");
break;
case 4:
printf("Thursday");
break;
case 5:
printf("Friday");
break;
case 6:
printf("Saturday");
break;
case 7:
printf("Sunday");
break;
default:
printf("Invalid day");
}
return 0;
}#include <stdio.h>
int main() {
int choice, a, b, result;
printf("1. Add\n2. Subtract\n3. Multiply\n4. Divide\nEnter your choice: ");
scanf("%d", &choice);
printf("Enter two numbers: ");
scanf("%d %d", &a, &b);
switch (choice) {
case 1:
result = a + b;
printf("Result: %d\n", result);
break;
case 2:
result = a - b;
printf("Result: %d\n", result);
break;
case 3:
result = a * b;
printf("Result: %d\n", result);
break;
case 4:
if (b != 0) {
result = a / b;
printf("Result: %d\n", result);
} else {
printf("Cannot divide by zero!\n");
}
break;
default:
printf("Invalid choice!\n");
}
return 0;
}