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ACCENTURE EXAM SOLUTIONS

ACCENTURE EXAM SOLUTIONS

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🔥Guys plz Stop fearing for daily exams 📝 👨‍💻 @srksvk is here to help you all at lowest cost possible.💪 🌀 ” Our Only Aim Is To Let Get Placed To You In A Reputed Company 🔥Effort from our side = 💯 📱Main Channel: @coding_are 📱Tel I'd : @srksvk

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📈 Аналитический обзор Telegram-канала ACCENTURE EXAM SOLUTIONS

Канал ACCENTURE EXAM SOLUTIONS (@coding_are) языкового сегмента Английский является активным участником. Сейчас сообщество объединяет 14 141 подписчиков, занимая 14 044 место в категории Образование и 28 010 место в регионе Индия.

📊 Показатели аудитории и динамика

С момента создания невідомо проект демонстрирует стремительный рост, собрав аудиторию из 14 141 подписчиков.

Согласно последним данным от 20 сентября, 2026, канал показывает стабильную активность. За последние 30 дней изменение числа участников составило -145, а за последние 24 часа — -3, при этом общий охват остаётся высоким.

  • Статус верификации: Не верифицирован
  • Уровень вовлечённости (ER): Средний показатель вовлечённости аудитории составляет 4.14%. В первые 24 часа после публикации контент обычно набирает 1.54% реакций от общего числа подписчиков.
  • Охват публикаций: В среднем каждый пост получает 585 просмотров. В течение первых суток публикация набирает 217 просмотров.
  • Реакции и взаимодействия: Аудитория активно поддерживает контент: среднее количество реакций на один пост — 1.
  • Тематические интересы: Контент сосредоточен на ключевых темах, таких как placement, gaurntee, suree, capgemini, infosy.

📝 Описание и контентная политика

Автор описывает ресурс как площадку для выражения субъективного мнения:
🔥Guys plz Stop fearing for daily exams 📝 👨‍💻 @srksvk is here to help you all at lowest cost possible.💪 🌀 ” Our Only Aim Is To Let Get Placed To You In A Reputed Company 🔥Effort from our side = 💯 📱Main Channel: @coding_are 📱Tel I'd : @srks...

Благодаря высокой частоте обновлений (последние данные получены 22 сентября, 2026) канал поддерживает актуальность и высокий уровень охвата публикаций. Аналитика показывает, что аудитория активно взаимодействует с контентом, что делает его важной точкой влияния в категории Образование.

14 137
Подписчики
-324 часа
-347 дней
-14530 дней
Архив постов
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2nd linkdin code✅

public static List getMinSum(List arr, List query, int k) { List result = new ArrayList<>(); int n = arr.size(); for (int z : query) { int minSum = Integer.MAX_VALUE; for (int i = 0; i < n; i++) { for (int j = 0; j < n; j++) { int x = arr.get(i); int y = arr.get(j); if (x == 0 && y == 0) continue; if (x != 0 && z % x == 0) { int a = z / x, b = 0; if (a >= 0) minSum = Math.min(minSum, a + b); } if (y != 0 && z % y == 0) { int a = 0, b = z / y; if (b >= 0) minSum = Math.min(minSum, a + b); } if (x != 0) { for (int a = 0; a <= k; a++) { int rem = z - a * x; if (rem < 0) break; if (y != 0 && rem % y == 0) { int b = rem / y; if (b >= 0 && a + b <= k) { minSum = Math.min(minSum, a + b); } } } } } } result.add(minSum <= k ? minSum : -1); } return result; }

Linkdin first' code✅

import java.util.*; class Result { public static int findMinOperations(List<Integer> arr) { int n = arr.size(); int operations = 0; int rootCount = 0; for (int x : arr) { if (x == -1) rootCount++; } if (rootCount == 0) { arr.set(0, -1); operations++; } else if (rootCount > 1) { boolean found = false; for (int i = 0; i < n; i++) { if (arr.get(i) == -1) { if (!found) { found = true; } else { arr.set(i, 1); operations++; } } } } for (int i = 0; i < n; i++) { int parent = arr.get(i); if (parent != -1 && (parent < 1 || parent > n)) { arr.set(i, 1); operations++; } } boolean[] visited = new boolean[n]; boolean[] inStack = new boolean[n]; for (int i = 0; i < n; i++) { if (!visited[i]) { operations += dfsFixCycle(arr, visited, inStack, i); } } return operations; } private static int dfsFixCycle(List<Integer> arr, boolean[] visited, boolean[] inStack, int node) { int operations = 0; while (node != -1 && !visited[node]) { visited[node] = true; inStack[node] = true; int parent = arr.get(node) == -1 ? -1 : arr.get(node) - 1; if (parent != -1) { if (!visited[parent]) { node = parent; } else if (inStack[parent]) { arr.set(node, -1); operations++; break; } else { break; } } else { break; } } Arrays.fill(inStack, false); return operations; } } public class Solution { public static void main(String[] args) { Scanner sc = new Scanner(System.in); int n = sc.nextInt(); List<Integer> arr = new ArrayList<>(); for (int i = 0; i < n; i++) { arr.add(sc.nextInt()); } System.out.println(Result.findMinOperations(arr)); } }

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