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ACCENTURE EXAM SOLUTIONS

ACCENTURE EXAM SOLUTIONS

الذهاب إلى القناة على Telegram

🔥Guys plz Stop fearing for daily exams 📝 👨‍💻 @srksvk is here to help you all at lowest cost possible.💪 🌀 ” Our Only Aim Is To Let Get Placed To You In A Reputed Company 🔥Effort from our side = 💯 📱Main Channel: @coding_are 📱Tel I'd : @srksvk

إظهار المزيد

📈 نظرة تحليلية على قناة تيليجرام ACCENTURE EXAM SOLUTIONS

تُعد قناة ACCENTURE EXAM SOLUTIONS (@coding_are) في القطاع اللغوي الإنكليزية لاعباً نشطاً. يضم المجتمع حالياً 14 141 مشتركاً، محتلاً المرتبة 14 044 في فئة التعليم والمرتبة 28 010 في منطقة الهند.

📊 مؤشرات الجمهور والحراك

منذ تأسيسه في невідомо، حقق المشروع نمواً سريعاً وجمع 14 141 مشتركاً.

بحسب آخر البيانات بتاريخ 21 سبتمبر, 2026، تحافظ القناة على نشاط مستقر. خلال آخر 30 يوماً تغيّر عدد الأعضاء بمقدار -136، وفي آخر 24 ساعة بمقدار 1، مع بقاء الوصول العام مرتفعاً.

  • حالة التحقق: غير موثّقة
  • معدل التفاعل (ER): يبلغ متوسط تفاعل الجمهور 4.15‎%. وخلال أول 24 ساعة من النشر يحصد المحتوى عادةً 1.53‎% من ردود الفعل نسبةً إلى إجمالي المشتركين.
  • وصول المنشورات: يحصل كل منشور على متوسط 586 مشاهدة. وخلال اليوم الأول يجمع عادةً 216 مشاهدة.
  • التفاعلات والاستجابة: يتفاعل الجمهور بانتظام؛ متوسط التفاعلات لكل منشور يبلغ 1.
  • الاهتمامات الموضوعية: يركز المحتوى على مواضيع رئيسية مثل placement, gaurntee, suree, capgemini, infosy.

📝 الوصف وسياسة المحتوى

يصف المؤلف القناة بأنها مساحة للتعبير عن الآراء الذاتية:
🔥Guys plz Stop fearing for daily exams 📝 👨‍💻 @srksvk is here to help you all at lowest cost possible.💪 🌀 ” Our Only Aim Is To Let Get Placed To You In A Reputed Company 🔥Effort from our side = 💯 📱Main Channel: @coding_are 📱Tel I'd : @srks...

بفضل وتيرة التحديث المرتفعة (أحدث البيانات بتاريخ 22 سبتمبر, 2026) تحافظ القناة على حداثتها ومستوى وصول مرتفع. وتُظهر التحليلات تفاعلاً نشطاً من الجمهور، ما يجعلها نقطة تأثير مهمة ضمن فئة التعليم.

14 141
المشتركون
+124 ساعات
-367 أيام
-13630 أيام
أرشيف المشاركات
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2nd linkdin code✅

public static List getMinSum(List arr, List query, int k) { List result = new ArrayList<>(); int n = arr.size(); for (int z : query) { int minSum = Integer.MAX_VALUE; for (int i = 0; i < n; i++) { for (int j = 0; j < n; j++) { int x = arr.get(i); int y = arr.get(j); if (x == 0 && y == 0) continue; if (x != 0 && z % x == 0) { int a = z / x, b = 0; if (a >= 0) minSum = Math.min(minSum, a + b); } if (y != 0 && z % y == 0) { int a = 0, b = z / y; if (b >= 0) minSum = Math.min(minSum, a + b); } if (x != 0) { for (int a = 0; a <= k; a++) { int rem = z - a * x; if (rem < 0) break; if (y != 0 && rem % y == 0) { int b = rem / y; if (b >= 0 && a + b <= k) { minSum = Math.min(minSum, a + b); } } } } } } result.add(minSum <= k ? minSum : -1); } return result; }

Linkdin first' code✅

import java.util.*; class Result { public static int findMinOperations(List<Integer> arr) { int n = arr.size(); int operations = 0; int rootCount = 0; for (int x : arr) { if (x == -1) rootCount++; } if (rootCount == 0) { arr.set(0, -1); operations++; } else if (rootCount > 1) { boolean found = false; for (int i = 0; i < n; i++) { if (arr.get(i) == -1) { if (!found) { found = true; } else { arr.set(i, 1); operations++; } } } } for (int i = 0; i < n; i++) { int parent = arr.get(i); if (parent != -1 && (parent < 1 || parent > n)) { arr.set(i, 1); operations++; } } boolean[] visited = new boolean[n]; boolean[] inStack = new boolean[n]; for (int i = 0; i < n; i++) { if (!visited[i]) { operations += dfsFixCycle(arr, visited, inStack, i); } } return operations; } private static int dfsFixCycle(List<Integer> arr, boolean[] visited, boolean[] inStack, int node) { int operations = 0; while (node != -1 && !visited[node]) { visited[node] = true; inStack[node] = true; int parent = arr.get(node) == -1 ? -1 : arr.get(node) - 1; if (parent != -1) { if (!visited[parent]) { node = parent; } else if (inStack[parent]) { arr.set(node, -1); operations++; break; } else { break; } } else { break; } } Arrays.fill(inStack, false); return operations; } } public class Solution { public static void main(String[] args) { Scanner sc = new Scanner(System.in); int n = sc.nextInt(); List<Integer> arr = new ArrayList<>(); for (int i = 0; i < n; i++) { arr.add(sc.nextInt()); } System.out.println(Result.findMinOperations(arr)); } }

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