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Канал Programming Resources | Python | Javascript | Artificial Intelligence Updates | Computer Science Courses | AI Books (@programming_guide) языкового сегмента Английский является активным участником. Сейчас сообщество объединяет 56 111 подписчиков, занимая 2 368 место в категории Технологии и приложения и 6 556 место в регионе Индия.
📊 Показатели аудитории и динамика
С момента создания невідомо проект демонстрирует стремительный рост, собрав аудиторию из 56 111 подписчиков.
Согласно последним данным от 08 июня, 2026, канал показывает стабильную активность. За последние 30 дней изменение числа участников составило 104, а за последние 24 часа — -6, при этом общий охват остаётся высоким.
- Статус верификации: Не верифицирован
- Уровень вовлечённости (ER): Средний показатель вовлечённости аудитории составляет 2.58%. В первые 24 часа после публикации контент обычно набирает 0.84% реакций от общего числа подписчиков.
- Охват публикаций: В среднем каждый пост получает 1 450 просмотров. В течение первых суток публикация набирает 471 просмотров.
- Реакции и взаимодействия: Аудитория активно поддерживает контент: среднее количество реакций на один пост — 3.
- Тематические интересы: Контент сосредоточен на ключевых темах, таких как algorithm, structure, stack, javascript, programming.
📝 Описание и контентная политика
Автор описывает ресурс как площадку для выражения субъективного мнения:
“Everything about programming for beginners
* Python programming
* Java programming
* App development
* Machine Learning
* Data Science
Managed by: @love_data”
Благодаря высокой частоте обновлений (последние данные получены 09 июня, 2026) канал поддерживает актуальность и высокий уровень охвата публикаций. Аналитика показывает, что аудитория активно взаимодействует с контентом, что делает его важной точкой влияния в категории Технологии и приложения.
class Node:
def __init__(self, data):
self.data = data
self.next = None
Java
class Node {
int data;
Node next;
Node(int data) {
this.data = data;
this.next = null;
}
}
C++
struct Node {
int data;
Node* next;
Node(int data): data(data), next(nullptr) {}
};
3️⃣ Insert at Head (Singly)
Python
def insert_head(head, data):
new_node = Node(data)
new_node.next = head
return new_node
Java
Node insertHead(Node head, int data) {
Node newNode = new Node(data);
newNode.next = head;
return newNode;
}
C++
Node* insertHead(Node* head, int data) {
Node* newNode = new Node(data);
newNode->next = head;
return newNode;
}
4️⃣ Doubly Linked List – Bi-directional Pointers
Python
class DNode:
def __init__(self, data):
self.data = data
self.prev = None
self.next = None
Java
class DNode {
int data;
DNode prev, next;
DNode(int data) {
this.data = data;
}
}
C++
struct DNode {
int data;
DNode* prev;
DNode* next;
DNode(int data): data(data), prev(nullptr), next(nullptr) {}
};
5️⃣ Insert at Head (Doubly)
Python
def insert_head(head, data):
new_node = DNode(data)
new_node.next = head
if head:
head.prev = new_node
return new_node
Java
DNode insertHead(DNode head, int data) {
DNode newNode = new DNode(data);
newNode.next = head;
if (head != null) head.prev = newNode;
return newNode;
}
C++
DNode* insertHead(DNode* head, int data) {
DNode* newNode = new DNode(data);
newNode->next = head;
if (head) head->prev = newNode;
return newNode;
}
6️⃣ Reversing a Singly Linked List
Python
def reverse_list(head):
prev = None
current = head
while current:
next_node = current.next
current.next = prev
prev = current
current = next_node
return prev
Java
Node reverseList(Node head) {
Node prev = null, current = head;
while (current != null) {
Node next = current.next;
current.next = prev;
prev = current;
current = next;
}
return prev;
}
C++
Node* reverseList(Node* head) {
Node* prev = nullptr;
Node* current = head;
while (current) {
Node* next = current->next;
current->next = prev;
prev = current;
current = next;
}
return prev;
}
7️⃣ Why Use Linked Lists?
✅ Dynamic memory allocation
✅ Efficient insert/delete (O(1) at head/tail)
❌ Slower access (O(n) for random access)
✅ Great for implementing stacks, queues, hash maps, etc.
8️⃣ Practice Tasks
✅ Implement singly linked list with insert/delete
✅ Implement doubly linked list with insert at tail
✅ Reverse a singly linked lists = "hello"
print(s[1]) # Output: 'e'
C++ Example:string s = "hello";
cout << s[1]; // Output: 'e'
Java Example:String s = "hello";
System.out.println(s.charAt(1)); // Output: 'e'
2️⃣ Common String Operations:
• Concatenation
• Substring
• Comparison
• Reversal
• Search
• Replace
Python – Reversal:s = "hello"
print(s[::-1]) # Output: 'olleh'
C++ – Substring:string s = "hello";
cout << s.substr(1, 3); // Output: 'ell'
Java – Replace:String s = "hello";
System.out.println(s.replace("l", "x")); // Output: 'hexxo'
3️⃣ Pattern Matching – Naive vs Efficient
Naive Approach: Check every substring
Efficient: Use hashing or KMP (Knuth-Morris-Pratt)
Python – Naive Pattern Search:def search(text, pattern):
for i in range(len(text) - len(pattern) + 1):
if text[i:i+len(pattern)] == pattern:
print(f"Found at index {i}")
search("abracadabra", "abra") # Output: Found at index 0, 7
4️⃣ Hashing for Fast Lookup
Use hash maps to store character counts, frequencies, or indices.
Python – First Unique Character:from collections import Counter
def first_unique_char(s):
count = Counter(s)
for i, ch in enumerate(s):
if count[ch] == 1:
return i
return -1
print(first_unique_char("leetcode")) # Output: 0
5️⃣ Two Pointers Technique
Used for problems like palindromes, anagrams, or substring windows.
Python – Valid Palindrome:def is_palindrome(s):
s = ''.join(filter(str.isalnum, s)).lower()
left, right = 0, len(s) - 1
while left < right:
if s[left] != s[right]:
return False
left += 1
right -= 1
return True
print(is_palindrome("A man, a plan, a canal: Panama")) # Output: True
6️⃣ Practice Tasks:
✅ Implement pattern search (naive)
✅ Find first non-repeating character
✅ Check if a string is a palindrome
✅ Use two pointers to reverse vowels in a string
✅ Try Rabin-Karp or KMP for pattern matching
💬 Double Tap ❤️ for Part-5arr = [10, 20, 30, 40]
print(arr[2]) # Output: 30
C++ Example:
int arr[] = {10, 20, 30, 40};
cout << arr[2]; // Output: 30
Java Example:
int[] arr = {10, 20, 30, 40};
System.out.println(arr[2]); // Output: 30
2️⃣ Basic Array Operations:
• Insert
• Delete
• Traverse
• Search
• Update
Python – Traversal:
for i in arr:
print(i)
C++ – Search:
for (int i = 0; i < n; i++) {
if (arr[i] == key) {
// Found
}
}
Java – Update:
arr[1] = 99; // Updates second element
3️⃣ Sliding Window Technique 🪟
Used to reduce time complexity in problems involving subarrays or substrings.
▶️ Fixed-size window:
Find max sum of subarray of size k
▶️ Variable-size window:
Find longest substring with unique characters
4️⃣ Sliding Window – Max Sum Subarray (Size k)
Python:
def max_sum(arr, k):
window_sum = sum(arr[:k])
max_sum = window_sum
for i in range(k, len(arr)):
window_sum += arr[i] - arr[i - k]
max_sum = max(max_sum, window_sum)
return max_sum
print(max_sum([1, 4, 2, 10, 2, 3], 3)) # Output: 16
5️⃣ Practice Tasks:
✅ Find the second largest element in an array
✅ Implement sliding window to find max sum subarray
✅ Try variable-size window: longest substring without repeating characters
👇 Solution for Practice Tasks
✅ 1. Find the Second Largest Element in an Array
Python:
def second_largest(arr):
first = second = float('-inf')
for num in arr:
if num > first:
second = first
first = num
elif first > num > second:
second = num
return second if second != float('-inf') else None
print(second_largest([10, 20, 4, 45, 99])) # Output: 45
✅ 2. Max Sum Subarray (Fixed-size Sliding Window)
Python:
def max_sum(arr, k):
window_sum = sum(arr[:k])
max_sum = window_sum
for i in range(k, len(arr)):
window_sum += arr[i] - arr[i - k]
max_sum = max(max_sum, window_sum)
return max_sum
print(max_sum([1, 4, 2, 10, 2, 3, 1, 0, 20], 4)) # Output: 24
✅ 3. Longest Substring Without Repeating Characters (Variable-size Sliding Window)
Python:
def longest_unique_substring(s):
seen = {}
left = max_len = 0
for right in range(len(s)):
if s[right] in seen and seen[s[right]] >= left:
left = seen[s[right]] + 1
seen[s[right]] = right
max_len = max(max_len, right - left + 1)
return max_len
print(longest_unique_substring("abcabcbb")) # Output: 3 ("abc")
Double Tap ♥️ For Part-4def countdown(n):
if n == 0:
print("Done!")
return
print(n)
countdown(n - 1)
▶️ Counts down from n to 0
2️⃣ Key Parts of Recursion:
• Base case – Stops recursion
• Recursive case – Function calls itself
Java Example – Factorial:
int factorial(int n) {
if (n == 0) return 1;
return n * factorial(n - 1);
}
C++ Example – Sum of Array:
int sum(int arr[], int n) {
if (n == 0) return 0;
return arr[n - 1] + sum(arr, n - 1);
}
3️⃣ Why Use Recursion?
• Breaks complex problems into simpler ones
• Great for trees, graphs, backtracking, divide conquer
4️⃣ When Not to Use It?
• Large inputs can cause stack overflow
• Use loops if recursion is too deep or inefficient
5️⃣ Practice Task:
✅ Write a recursive function to calculate power (a^b)
✅ Write a function to reverse a string recursively
✅ Try basic Fibonacci using recursion
👇 Solution for Practice Task
✅ 1. Recursive Power Function (a^b)
Python:
def power(a, b):
if b == 0:
return 1
return a * power(a, b - 1)
print(power(2, 3)) # Output: 8
C++:
int power(int a, int b) {
if (b == 0) return 1;
return a * power(a, b - 1);
}
// Example: cout << power(2, 3); // Output: 8
Java:
int power(int a, int b) {
if (b == 0) return 1;
return a * power(a, b - 1);
}
// Example: System.out.println(power(2, 3)); // Output: 8
✅ 2. Reverse String Recursively
Python:
def reverse(s):
if len(s) == 0:
return ""
return reverse(s[1:]) + s[0]
print(reverse("hello")) # Output: "olleh"
C++:
string reverse(string s) {
if (s.length() == 0) return "";
return reverse(s.substr(1)) + s[0];
}
// Example: cout << reverse("hello"); // Output: "olleh"
Java:
String reverse(String s) {
if (s.isEmpty()) return "";
return reverse(s.substring(1)) + s.charAt(0);
}
// Example: System.out.println(reverse("hello")); // Output: "olleh"
✅ 3. Fibonacci Using Recursion
Python:
def fib(n):
if n <= 1:
return n
return fib(n - 1) + fib(n - 2)
print(fib(6)) # Output: 8
C++:
int fib(int n) {
if (n <= 1) return n;
return fib(n - 1) + fib(n - 2);
}
// Example: cout << fib(6); // Output: 8
Java:
int fib(int n) {
if (n <= 1) return n;
return fib(n - 1) + fib(n - 2);
}
// Example: System.out.println(fib(6)); // Output: 8
*Double Tap ♥️ For More*for i in range(n):
print(i)
Runs n times → O(n) time
Example (Java):for (int i = 0; i < n; i++) {
System.out.println(i);
}
Example (C++):for (int i = 0; i < n; i++) {
cout << i << endl;
}
2️⃣ Common Time Complexities (Best to Worst):
O(1) – Constant (e.g., array access)
O(log n) – Logarithmic (e.g., binary search)
O(n) – Linear (e.g., single loop)
O(n log n) – Efficient sorting (e.g., merge sort)
O(n²) – Quadratic (e.g., nested loops)
O(2ⁿ), O(n!) – Very slow (e.g., recursive brute force)
3️⃣ What is Space Complexity?
It tells us how much extra memory your code uses depending on input size.
Example:arr = [0] * n # O(n) space
If no extra structures are used → O(1) space
4️⃣ Why It Matters
• Handles large inputs without crashing
• Crucial in coding interviews
• Essential for scalable systems
5️⃣ Practice Task – Guess the Complexity
a) Nested loopfor (int i = 0; i < n; i++) {
for (int j = 0; j < n; j++) {
System.out.println(i + ", " + j);
}
}
// O(n²)
b) Binary searchwhile (low <= high) {
int mid = (low + high) / 2;
if (arr[mid] == target) break;
}
// O(log n)
c) Recursive Fibonaccidef fib(n):
if n <= 1:
return n
return fib(n-1) + fib(n-2)
// O(2^n)
Takeaway:
Always analyze two things before solving any problem:
– How many steps will this take? (Time)
– How much memory does it use? (Space)
💬 Tap ❤️ for more▶️ Creating and modifying arrays; ▶️ Mathematical operations; ▶️ Working with matrices and vectors; ▶️ Sorting and searching for values.Save it for yourself — it will come in handy when working with NumPy. tags: #NumPy #Python ➡ @DataScienceM
var, let, or const.
let name = "John";
const age = 30;
• Data Types: Includes:
– Primitive Types: Number, String, Boolean, Null, Undefined, Symbol (ES6).
– Reference Types: Objects, Arrays, Functions.
• Functions: Blocks of code designed to perform a particular task.
function greet() {
console.log("Hello, World!");
}
• Control Structures: Includes conditional statements (if, else, switch) and loops (for, while).
▎4. Working with the DOM
JavaScript can manipulate the Document Object Model (DOM), allowing developers to change the document structure, style, and content.
document.getElementById("myElement").innerHTML = "New Content";
▎5. JavaScript Frameworks and Libraries
• Frameworks: Provide a structure for building applications (e.g., Angular, Vue.js).
• Libraries: Simplify specific tasks (e.g., jQuery for DOM manipulation, D3.js for data visualization).
▎6. Asynchronous JavaScript
JavaScript supports asynchronous programming through:
• Callbacks: Functions passed as arguments to other functions.
• Promises: Objects representing the eventual completion (or failure) of an asynchronous operation.
• Async/Await: Syntactic sugar over promises that makes asynchronous code easier to read.
async function fetchData() {
const response = await fetch('https://api.example.com/data');
const data = await response.json();
console.log(data);
}
▎7. Error Handling
JavaScript uses try, catch, and finally blocks to handle errors gracefully.
try {
// Code that may throw an error
} catch (error) {
console.error("An error occurred:", error);
} finally {
// Code that runs regardless of success or failure
}
▎8. Modern JavaScript (ES6 and Beyond)
ES6 (ECMAScript 2015) introduced many new features:
• Arrow Functions:
const add = (a, b) => a + b;
• Template Literals:
const greeting = Hello, ${name}!;
• Destructuring:
const person = { name: "Alice", age: 25 };
const { name, age } = person;
▎9. Resources for Learning JavaScript
• Online Courses: Codecademy, freeCodeCamp, Udemy.
• Books: "You Don’t Know JS" series by Kyle Simpson, "Eloquent JavaScript" by Marijn Haverbeke.
• Documentation: MDN Web Docs (Mozilla Developer Network) is an excellent resource for JavaScript documentation.
▎10. Best Practices
• Write clean and readable code.
• Use meaningful variable and function names.
• Comment your code appropriately.
• Keep functions small and focused on a single task.
• Use version control (e.g., Git) for managing changes.
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