Physics Spmnetic!™ 🔭

Открыть в Telegram

This channel belongs to @thespmneticofficial, and a platform for sharing notes and exercises 🤘🏻 For inquiries, directly ask in a discussion group ✨

Больше

Сеть:Sejarah spmnetic!™Малайзия1 351 Образование7 479...

📈 Аналитический обзор Telegram-канала Physics Spmnetic!™ 🔭

Канал Physics Spmnetic!™ 🔭 (@physicsspmnotes) языкового сегмента Малайский является активным участником. Сейчас сообщество объединяет 26 181 подписчиков, занимая 7 479 место в категории Образование и 1 351 место в регионе Малайзия.

📊 Показатели аудитории и динамика

С момента создания невідомо проект демонстрирует стремительный рост, собрав аудиторию из 26 181 подписчиков.

Согласно последним данным от 27 июня, 2026, канал показывает стабильную активность. За последние 30 дней изменение числа участников составило 360, а за последние 24 часа — 28, при этом общий охват остаётся высоким.

Статус верификации: Не верифицирован
Уровень вовлечённости (ER): Средний показатель вовлечённости аудитории составляет 8.54%. В первые 24 часа после публикации контент обычно набирает 5.38% реакций от общего числа подписчиков.
Охват публикаций: В среднем каждый пост получает 2 234 просмотров. В течение первых суток публикация набирает 1 408 просмотров.
Реакции и взаимодействия: Аудитория активно поддерживает контент: среднее количество реакций на один пост — 5.
Тематические интересы: Контент сосредоточен на ключевых темах, таких как chapter, halo, jawab, physics, soalan.

📝 Описание и контентная политика

Автор описывает ресурс как площадку для выражения субъективного мнения:
“This channel belongs to @thespmneticofficial, and a platform for sharing notes and exercises 🤘🏻 For inquiries, directly ask in a discussion group ✨”

Благодаря высокой частоте обновлений (последние данные получены 28 июня, 2026) канал поддерживает актуальность и высокий уровень охвата публикаций. Аналитика показывает, что аудитория активно взаимодействует с контентом, что делает его важной точкой влияния в категории Образование.

26 181

Подписчики

+2824 часа

+1717 дней

+36030 день

2 234

Просмотры поста

~ 1 40824 часа

~ 1 89448 часов

8.54%

Коэффициент вовлеченности

~ 4

Постов в день

Ads index

beta

Архив постов

26 176

the total resistance must be

Anonymous voting

26 176

the heating wire should have

Anonymous voting

26 176

u should know that the liquid would be responding to acceleration not speed and therefore there is no way to determine which is faster, only which is speeding up, slowing down or maintaining steady speed.

26 176

for those who don't know about history, few years back an admin of physics spmnetic banned a guy who corrected him, and its a shame to this group, and as an spmnetic admin, I apologize from our side...admin here including me can be incorrect, so pls correct us when we are wrong.

26 176

from zianhao, an unknown legend

26 176

Anonymous voting

26 176

Assuming uniform acceleration: Journey OA s = ut + 0.5at² 20 = 0 + 0.5a(1)² a = 40 m/s² v = u + at v = 0 + 40(1) = 40 m/s Journey AB s = ut + 0.5at² 20 = 40(1) + 0.5a(1)² a = -40m/s² v = u + at v = 40 + (-40)(1) = 0 Which means it's accelerating, decelerating and vice versa. If that's the case, then option B is also correct. Unless, we are assuming a non-uniform acceleration, where we don't care how the acceleration changes, but we assume this acceleration brings the velocity at point A to be 20 m/s, then it has constant velocity all the way down the journey, making option A the only answer.

26 176

I'll say there's not enough information

26 176

If you remember this question, I think there's something interesting to discuss. If you recalled, I said that when the car is at A, the velocity cannot be equal to 20 m/s, assuming a constant acceleration along OA. I stopped there and didn't continue with the discussion. However, if the car continues the journey (taking my case to be true), then you'll find out the OA, BC, DE will have acceleration, making B also a correct answer. So, what will be the real case? Turns out, you'll need to have a non-uniform acceleration along journey OA, then you can have the car travelling at 20m/s at A, and later having a constant velocity throughout the journey, making option A the only correct answer. But still, even it's possible to have the car travelling at 20m/s at A, the working did by Harraz in his Physics Spmnetic was still wrong. He didnt understand how to use v = d/t and a = (v-u)/t correctly

26 176

I see a big misconception here. Not only you, many are doing it as well If you want to use v = displacement/ time, you are assuming that the velocity is constant and there is no acceleration But then you find the acceleration for OA, taking v = 20 m/s. Do you guys see the contradiction here? We should apply suvat formulas Journey OA s = 20 u = 0 v = ? a = ? t = 1 s = ut + ½at² 20 = 0 + ½a a = 40 m/s² Assume that the acceleration is constant Then use v = u + at v = 0 + 40(1) = 40 m/s

26 176

Quiz time🔥

26 176

For truck A, if it decelerates from 200 km per hour to 180km, the water will go to the right side , so we cant really eliminate truck A, for other trucks many people gave reasoning on why it could be the fastest

26 176

And also give reasoning on why U can't use any formula here.

26 176

But at least describe how it moves properly

26 176

Ok U actually can't use. Any formula here

26 176

Repost from ꒰ 📚 ˗ˏˋ 𝐉𝐎𝐌 𝐒𝐓𝐔𝐃𝐘 ´ˎ˗ °◞♡ ꒱

PERCUMA ❗️PERCUMA ❗️PERCUMA AVICENNA TUITION X EXERCISE STUDENTS [ TUTOR MUDA DARI BATCH 08 ] 🚀 SPM 2026/27: LET'S START NOW ! 🚀 Cuti CNY nak healing ke nak study? Apa kata buat dua-dua! AVICENNA TUITION nak bantu korang skor Straight A’s dengan teknik paling simple & straight to the point. 🔥 KENAPA KENA JOIN ❓ ✅ 100% PERCUMA (Tak payah bayar sesen pun!) ✅ 16 Subjek Terlibat (Termasuk AddMath, GKT & Reka Cipta) ✅ TutorMuda Pakar (Abang & Kakak lepasan SPM 2025 yang dah lalui apa korang rasa) 📅 TARIKH: 12 Feb – 20 Feb 2026 ⏰ MASA: 8:30 AM – 11:00 PM Jangan biarkan "nanti-nanti" jadi "rugi". Peluang depan mata, jom penuhkan ilmu masa cuti ni! 🔗 Klik link Dibawah Untuk Dapatkan Jadual Kelas : https://drive.google.com/drive/folders/1oHBv9ZDFYixBqzFy0jCpsHzfDOEn1SaF?usp=sharing DAPATKAN LINK KELAS DI CHANNEL TELEGRAM : [ https://t.me/Tatabahasa_Melayu ] sebarkan pada rakan - rakan anda !

26 176