Data Engineers
Free Data Engineering Ebooks & Courses
Больше📈 Аналитический обзор Telegram-канала Data Engineers
Канал Data Engineers (@sql_engineer) языкового сегмента Английский является активным участником. Сейчас сообщество объединяет 10 379 подписчиков, занимая 19 346 место в категории Образование и 40 072 место в регионе Индия.
📊 Показатели аудитории и динамика
С момента создания невідомо проект демонстрирует стремительный рост, собрав аудиторию из 10 379 подписчиков.
Согласно последним данным от 09 июня, 2026, канал показывает стабильную активность. За последние 30 дней изменение числа участников составило 243, а за последние 24 часа — 11, при этом общий охват остаётся высоким.
- Статус верификации: Не верифицирован
- Уровень вовлечённости (ER): Средний показатель вовлечённости аудитории составляет 10.19%. В первые 24 часа после публикации контент обычно набирает N/A% реакций от общего числа подписчиков.
- Охват публикаций: В среднем каждый пост получает 1 057 просмотров. В течение первых суток публикация набирает 0 просмотров.
- Реакции и взаимодействия: Аудитория активно поддерживает контент: среднее количество реакций на один пост — 7.
- Тематические интересы: Контент сосредоточен на ключевых темах, таких как sql, learning, analytic, engineer, link:-.
📝 Описание и контентная политика
Автор описывает ресурс как площадку для выражения субъективного мнения:
“Free Data Engineering Ebooks & Courses”
Благодаря высокой частоте обновлений (последние данные получены 10 июня, 2026) канал поддерживает актуальность и высокий уровень охвата публикаций. Аналитика показывает, что аудитория активно взаимодействует с контентом, что делает его важной точкой влияния в категории Образование.
MongoDB is a flexible, document-orientated, NoSQL database program that can scale to any enterprise volume without compromising search performance.This Post includes a MongoDB cheat sheet to make it easy for our followers to work with MongoDB. Working with databases Working with rows Working with Documents Querying data from documents Modifying data in documents Searching
I am seeking to become an expert professional in [Making ChatGPT prompts perfectly]. I would like ChatGPT to provide me with a complete course on this subject, following the principles of Pareto principle and simulating the complexity, structure, duration, and quality of the information found in a college degree program at a prestigious university. The course should cover the following aspects: Course Duration: The course should be structured as a comprehensive program, spanning a duration equivalent to a full-time college degree program, typically four years. Curriculum Structure: The curriculum should be well-organized and divided into semesters or modules, progressing from beginner to advanced levels of proficiency. Each semester/module should have a logical flow and build upon the previous knowledge. Relevant and Accurate Information: The course should provide all the necessary and up-to-date information required to master the skill or knowledge area. It should cover both theoretical concepts and practical applications. Projects and Assignments: The course should include a series of hands-on projects and assignments that allow me to apply the knowledge gained. These projects should range in complexity, starting from basic exercises and gradually advancing to more challenging real-world applications. Learning Resources: ChatGPT should share a variety of learning resources, including textbooks, research papers, online tutorials, video lectures, practice exams, and any other relevant materials that can enhance the learning experience. Expert Guidance: ChatGPT should provide expert guidance throughout the course, answering questions, providing clarifications, and offering additional insights to deepen understanding. I understand that ChatGPT's responses will be generated based on the information it has been trained on and the knowledge it has up until September 2021. However, I expect the course to be as complete and accurate as possible within these limitations. Please provide the course syllabus, including a breakdown of topics to be covered in each semester/module, recommended learning resources, and any other relevant information
(Tap on above text to copy)SELECT name, email FROM users;
This fetches only the name and email columns from the users table.
✔️ Used when you don’t want all columns from a table.
2️⃣ Filter Records with WHERE
SELECT * FROM users WHERE age > 30;
The WHERE clause filters rows where age is greater than 30.
✔️ Used for applying conditions on data.
3️⃣ ORDER BY Clause
SELECT * FROM users ORDER BY registered_at DESC;
Sorts all users based on registered_at in descending order.
✔️ Helpful to get latest data first.
4️⃣ Aggregate Functions (COUNT, AVG)
SELECT COUNT(*) AS total_users, AVG(age) AS avg_age FROM users;
Explanation:
- COUNT(*) counts total rows (users).
- AVG(age) calculates the average age.
✔️ Used for quick stats from tables.
5️⃣ GROUP BY Usage
SELECT city, COUNT(*) AS user_count FROM users GROUP BY city;
Groups data by city and counts users in each group.
✔️ Use when you want grouped summaries.
6️⃣ JOIN Tables
SELECT users.name, orders.amount
FROM users
JOIN orders ON users.id = orders.user_id;
Fetches user names along with order amounts by joining users and orders on matching IDs.
✔️ Essential when combining data from multiple tables.
7️⃣ Use of HAVING
SELECT city, COUNT(*) AS total
FROM users
GROUP BY city
HAVING COUNT(*) > 5;
Like WHERE, but used with aggregates. This filters cities with more than 5 users.
✔️ **Use HAVING after GROUP BY.**
8️⃣ Subqueries
SELECT * FROM users
WHERE salary > (SELECT AVG(salary) FROM users);
Finds users whose salary is above the average. The subquery calculates the average salary first.
✔️ Nested queries for dynamic filtering9️⃣ CASE Statementnt**
SELECT name,
CASE
WHEN age < 18 THEN 'Teen'
WHEN age <= 40 THEN 'Adult'
ELSE 'Senior'
END AS age_group
FROM users;
Adds a new column that classifies users into categories based on age.
✔️ Powerful for conditional logic.
🔟 Window Functions (Advanced)
SELECT name, city, score,
RANK() OVER (PARTITION BY city ORDER BY score DESC) AS rank
FROM users;
Ranks users by score *within each city*.
SQL Learning Series: https://whatsapp.com/channel/0029VanC5rODzgT6TiTGoa1v/1075
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