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ACCENTURE EXAM SOLUTIONS

ACCENTURE EXAM SOLUTIONS

رفتن به کانال در Telegram

🔥Guys plz Stop fearing for daily exams 📝 👨‍💻 @srksvk is here to help you all at lowest cost possible.💪 🌀 ” Our Only Aim Is To Let Get Placed To You In A Reputed Company 🔥Effort from our side = 💯 📱Main Channel: @coding_are 📱Tel I'd : @srksvk

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📈 تحلیل کانال تلگرام ACCENTURE EXAM SOLUTIONS

کانال ACCENTURE EXAM SOLUTIONS (@coding_are) در بخش زبانی انگلیسی بازیگری فعال است. در حال حاضر جامعه شامل 14 139 مشترک است و جایگاه 14 044 را در دسته آموزش و رتبه 28 010 را در منطقه الهند دارد.

📊 شاخص‌های مخاطب و پویایی

از زمان ایجاد در невідомо، پروژه رشد سریعی داشته و 14 139 مشترک جذب کرده است.

بر اساس آخرین داده‌ها در تاریخ 21 سپتامبر, 2026، کانال فعالیت پایداری دارد. در ۳۰ روز گذشته تغییر اعضا برابر -136 و در ۲۴ ساعت گذشته برابر 1 بوده و همچنان دسترسی گسترده‌ای حفظ شده است.

  • وضعیت تأیید: تأیید نشده
  • نرخ تعامل (ER): میانگین تعامل مخاطب 4.15% است و در ۲۴ ساعت نخست پس از انتشار، محتوا معمولاً 1.53% واکنش نسبت به کل مشترکان کسب می‌کند.
  • دسترسی پست‌ها: هر پست به طور میانگین 586 بازدید دریافت می‌کند. در اولین روز معمولاً 216 بازدید جمع‌آوری می‌شود.
  • واکنش‌ها و تعامل: مخاطبان به‌طور فعال حمایت می‌کنند؛ میانگین واکنش به هر پست 1 است.
  • علایق موضوعی: محتوا بر موضوعات کلیدی مانند placement, gaurntee, suree, capgemini, infosy تمرکز دارد.

📝 توضیح و سیاست محتوایی

نویسنده این فضا را محل بیان دیدگاه‌های شخصی توصیف می‌کند:
🔥Guys plz Stop fearing for daily exams 📝 👨‍💻 @srksvk is here to help you all at lowest cost possible.💪 🌀 ” Our Only Aim Is To Let Get Placed To You In A Reputed Company 🔥Effort from our side = 💯 📱Main Channel: @coding_are 📱Tel I'd : @srks...

به لطف به‌روزرسانی‌های پرتکرار (آخرین داده در تاریخ 22 سپتامبر, 2026)، کانال همواره به‌روز و دارای دسترسی بالاست. تحلیل‌ها نشان می‌دهد مخاطبان به‌طور فعال با محتوا تعامل دارند و آن را به نقطه اثرگذاری مهم در دسته آموزش تبدیل کرده‌اند.

14 139
مشترکین
+124 ساعت
-367 روز
-13630 روز
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import sys def solve(N, K, A): n = N limit = 1 << n valid = [False] * limit for mask in range(limit): s = 0 for i in range(n): if (mask >> i) & 1: s += A[i] if s <= K: valid[mask] = True dp = [n+1] * limit dp[0] = 0 full = limit - 1 for mask in range(1, limit): sub = mask while sub: if valid[sub]: other = mask ^ sub if dp[other] + 1 < dp[mask]: dp[mask] = dp[other] + 1 sub = (sub - 1) & mask return dp[full] * K def main(): data = sys.stdin.read().split() it = iter(data) N = int(next(it)); K = int(next(it)) A = [int(next(it)) for _ in range(N)] print(solve(N, K, A)) if name == "main": main()