ACCENTURE EXAM SOLUTIONS
前往频道在 Telegram
🔥Guys plz Stop fearing for daily exams 📝 👨💻 @srksvk is here to help you all at lowest cost possible.💪 🌀 ” Our Only Aim Is To Let Get Placed To You In A Reputed Company 🔥Effort from our side = 💯 📱Main Channel: @coding_are 📱Tel I'd : @srksvk
显示更多📈 Telegram 频道 ACCENTURE EXAM SOLUTIONS 的分析概览
频道 ACCENTURE EXAM SOLUTIONS (@coding_are) 英语 语言赛道中的 是活跃参与者。目前社区聚集了 14 136 名订阅者，在 教育 类别中位列第 14 103，并在 印度 地区排名第 28 083 位。
📊 受众指标与增长动态
自 невідомо 创建以来，项目保持高速增长，吸引了 14 136 名订阅者。
根据 21 九月, 2026 的最新数据，频道保持稳定运转。过去 30 天订阅人数变化为 -136，过去 24 小时变化为 1，整体触达仍然可观。
- 认证状态： 未认证
- 互动率 (ER)： 平均受众互动率为 4.15%。内容发布后 24 小时内通常能获得 1.53% 的反应，占订阅者总量。
- 帖子覆盖： 每篇帖子平均可获得 586 次浏览，首日通常累积 216 次浏览。
- 互动与反馈： 受众积极参与，单帖平均反应数为 1。
- 主题关注点： 内容集中在 placement, gaurntee, suree, capgemini, infosy 等核心主题上。
📝 描述与内容策略
作者将该频道定位为表达主观观点的平台：
“🔥Guys plz Stop fearing for daily exams 📝
👨💻 @srksvk is here to help you all at lowest cost possible.💪
🌀 ” Our Only Aim Is To Let Get Placed To You In A Reputed Company
🔥Effort from our side = 💯
📱Main Channel: @coding_are
📱Tel I'd : @srks...”
凭借高频更新（最新数据采集于 23 九月, 2026），频道始终保持新鲜度与高覆盖。分析显示受众积极互动，使其成为 教育 类别中的关键影响点。
14 139
订阅者
+124 小时
-367 天
-13630 天
帖子存档
14 136
+1
Josh technology exam cleared 🔥🔥🔥🔥🔥🔥🔥🔥🔥🔥🔥🔥
Got next round mail 🥳🥳🥳🎉
Helped proof 👇👇👇👇
Contact for placement exam @srksvk
14 136
+2
Linkdin exam successfully completed by remote access 👍👍👍👍👍
3/3 code done with all tests cases passed✅✅✅
Contact for placement exam @srksvk
14 136
Juspay
Epam
De shaw
Josh technology,
Ion group,
Amazon's,
Morning Star,
Wipro,
Any off campus or on campus exam by help available
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14 136
+1
Ibm exam successfully completed by remote access 👍👍👍👍
2/2 code done with all tests cases passed ✅✅
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14 136
+5
Reltio exam help successfully completed via pic ✅✅✅✅
18mcq+ 2/2 code done with all tests cases passed ✅
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14 136
Epam
De shaw
Josh technology,
Ion group,
Amazon's,
Morning Star,
Wipro,
Any off campus or on campus exam by help available
Contact fast and book your slots
Contact @srksvk
200% suree clearance grauntee
🔥
Remote access available
All company interview help available with sure clearance gaurntee
14 136
Epam , de shaw on campus exam help available
Contact fast and book your slots
Contact @srksvk
200% suree clearance gaurntee
14 136
+1
Ion group exam successfully completed by remote access 👍👍👍👍👍
2/2 code done with all tests cases passed
Contact for placement exam @srksvk
14 136
+5
PROLIM company interview help successfully completed ✅✅✅
All code done with all tests caes passed in python ✅
All answers provided on time with 💯% correct answer ✅ 🔥
Contact for placement exam @srksvk
200% suree clearance gaurntee 👍
14 136
+5
PROLIM company interview help successfully completed ✅✅✅
All code done with all tests caes passed in python ✅
All answers provided on time with 💯% correct answer ✅ 🔥
Contact for placement exam @srksvk
200% suree clearance gaurntee 👍
14 136
Josh technology,
Ion group,
Amazon's,
Morning Star,
Wipro,
Any off campus or on campus exam by help available
Contact fast and book your slots
Contact @srksvk
200% suree clearance grauntee
🔥
Remote access available
All company interview help available with sure clearance gaurntee
14 136
+3
Josh technology on campus exam successfully completed by remote access 👍👍👍👍👍
4/4 codes done with all tests cases passed ✅✅✅
Contact for placement exam @srksvk
14 136
+1
Infosys internal exam successfully completed by remote access ♿♿♿
2/2 code +all MCQ done with all tests caes passed ✅✅✅
Contact for placement exam @srksvk
14 136
+2
3pm Infosys exam successfully completed by remote access 👍👍👍👍♿
3/3 code done with all tests caes passed ✅✅
Contact for placement exam @srksvk
14 136
+2
3pm Infosys exam successfully completed by remote access 👍👍👍👍♿
3/3 code done with all tests caes passed ✅✅
Contact for placement exam @srksvk
14 136
+2
12pm Wipro exam successfully completed by remote access 👍👍👍👍♿
55 MCQ + 2/2 code done with all tests caes passed ✅✅
Contact for placement exam @srksvk
14 136
import sys
def solve(N, K, A):
n = N
limit = 1 << n
valid = [False] * limit
for mask in range(limit):
s = 0
for i in range(n):
if (mask >> i) & 1:
s += A[i]
if s <= K:
valid[mask] = True
dp = [n+1] * limit
dp[0] = 0
full = limit - 1
for mask in range(1, limit):
sub = mask
while sub:
if valid[sub]:
other = mask ^ sub
if dp[other] + 1 < dp[mask]:
dp[mask] = dp[other] + 1
sub = (sub - 1) & mask
return dp[full] * K
def main():
data = sys.stdin.read().split()
it = iter(data)
N = int(next(it)); K = int(next(it))
A = [int(next(it)) for _ in range(N)]
print(solve(N, K, A))
if name == "main":
main()
