AI Coding & CSE Fundamentals
🚀 Explore AI, Coding & Computer Science Fundamentals. 💻 Programming • DSA • DBMS • OS • Networks 🤖 AI & Emerging Technologies 🛠️ Projects • Tutorials • Learning Resources 📚 Your freedom to gain knowledge for free.
Mostrar más📈 Análisis del canal de Telegram AI Coding & CSE Fundamentals
El canal AI Coding & CSE Fundamentals (@aicoding_csefundamentals) en el segmento lingüístico de Inglés es un actor destacado. Actualmente la comunidad reúne a 12 318 suscriptores, ocupando la posición 10 235 en la categoría Tecnologías y Aplicaciones y el puesto 31 257 en la región India.
📊 Métricas de audiencia y dinámica
Desde su creación el невідомо, el proyecto ha mostrado un crecimiento acelerado, reuniendo a 12 318 suscriptores.
Según los últimos datos del 13 noviembre, 2026, el canal mantiene una actividad estable. En los últimos 30 días la variación de miembros fue de -236, y en las últimas 24 horas de -9, conservando un alto alcance.
- Estado de verificación: No verificado
- Tasa de interacción (ER): El promedio de interacción de la audiencia es 10.85%. Durante las primeras 24 horas tras publicar, el contenido suele obtener N/A% de reacciones respecto al total de suscriptores.
- Alcance de las publicaciones: Cada publicación recibe en promedio 1 337 visualizaciones. En el primer día suele acumular 0 visualizaciones.
- Reacciones e interacción: La audiencia responde de forma activa: el promedio de reacciones por publicación es 11.
- Intereses temáticos: El contenido se centra en temas clave como input, string, scanf("%d, array, element.
📝 Descripción y política de contenido
El autor describe el recurso como un espacio para expresar opiniones subjetivas:
“🚀 Explore AI, Coding & Computer Science Fundamentals.
💻 Programming • DSA • DBMS • OS • Networks
🤖 AI & Emerging Technologies
🛠️ Projects • Tutorials • Learning Resources
📚 Your freedom to gain knowledge for free.”
Gracias a la alta frecuencia de actualizaciones (últimos datos recibidos el 14 noviembre, 2026), el canal mantiene la vigencia y un amplio alcance. La analítica demuestra que la audiencia interactúa activamente con el contenido, lo que lo convierte en un punto de referencia dentro de la categoría Tecnologías y Aplicaciones.
#include <stdio.h>
void printHello() {
printf("Hello, world!n");
}
int main() {
printHello(); // Calling or invoking the function
return 0;
}
- `void printHello()`: This declares a function named `printHello`.
- `void`: This means the function doesn't return any value. It just does something (in this case, printing).
- `printHello()`: This is the name of the function. Choose descriptive names!
- `{}`: The curly braces contain the code that the function executes.
- `printf("Hello, world!\n");`: This line prints "Hello, world!" to the console. `\n` adds a newline character (moves the cursor to the next line).
- `main()`: This is the main function, where the program execution begins.
- `printHello();`: This *calls* or *invokes* the `printHello` function. When the program reaches this line, it jumps to the `printHello` function, executes its code, and then returns to the next line in `main()`.
**2. Functions with Return Types (Giving Back Results)** ↩️
Sometimes, you want a function to calculate something and give you the result. This is where return types come in.
#include <stdio.h>
int add(int a, int b) {
int sum = a + b;
return sum;
}
int main() {
int result = add(5, 3);
printf("The sum is: %dn", result);
return 0;
}
- `int add(int a, int b)`:
- `int`: This is the *return type*. It means the function will return an integer value.
- `a` and `b`: These are *parameters*. They're like inputs to the function. `a` and `b` are integers.
- `return sum;`: This statement sends the value of `sum` back to the calling function (`main()`).
- `int result = add(5, 3);`: In `main()`, we call the `add` function with the values 5 and 3. The returned value (8) is then stored in the `result` variable.
**3. Parameters (Passing Information to Functions)** ➡️
Parameters are variables that you pass into a function. They allow you to give functions different inputs each time you call them.
#include <stdio.h>
void greet(char name[]) {
printf("Hello, %s!n", name);
}
int main() {
greet("Alice");
greet("Bob");
return 0;
}
- `char name[]`: This declares a parameter named `name` which is an array of characters (a string). The function takes a string as input.
- `greet("Alice")`: When we call `greet("Alice")`, the string "Alice" is passed as the value of the `name` parameter.
**4. Recursion (Functions Calling Themselves)** 🔄
Recursion is a powerful technique where a function calls *itself*. It's like looking in a mirror that reflects another mirror, and so on. 🤯 You need a "base case" to stop the recursion, or it will go on forever (or until your program crashes!).
#include <stdio.h>
int factorial(int n) {
// Base case:
if (n == 0) {
return 1;
}
// Recursive step:
else {
return n * factorial(n - 1);
}
}
int main() {
int result = factorial(5);
printf("Factorial of 5 is: %dn", result);
return 0;
}
- `factorial(int n)`: This function calculates the factorial of a number `n`.
- Base Case: `if (n == 0) { return 1; }`: The factorial of 0 is 1. This is the base case that stops the recursion. ⚠️ Without a base case, the function would call itself infinitely!
- Recursive Step#include <stdio.h>
int main() {
int i = 8;
int count = 0;
for (; i; i >>= 1) {
printf("%d ", i);
count++;
}
printf("\nLoop ran %d times.\n", count);
return 0;
}#include <stdio.h>
int main() {
for (int i = 1; i <= 10; i++) {
if (i == 5 || i == 7) {
continue;
}
printf("%d ", i);
}
printf("\n");
return 0;
}#include <stdio.h>
int main() {
int i = 0;
while (1) {
printf("%d ", i);
i++;
if (i > 9) {
break;
}
}
printf("\nLoop finished!\n");
return 0;
}#include <stdio.h>
int main() {
char ch;
for (ch = 'A'; ch <= 'Z'; ch++) {
printf("%c", ch);
if (ch < 'Z') {
printf("-");
}
}
printf("\n");
return 0;
}#include <stdio.h>
int main() {
int rows, num = 1;
scanf("%d", &rows);
for (int i = 1; i <= rows; i++) {
for (int j = 1; j <= i; j++) {
printf("%d ", num++);
}
printf("\n");
}
return 0;
}#include <stdio.h>
int main() {
int n;
scanf("%d", &n);
for (int i = 0; i < n; i++) {
for (int j = 0; j < n; j++) {
if (i == 0 || i == n - 1 || j == 0 || j == n - 1) {
printf("*");
} else {
printf(" ");
}
}
printf("\n");
}
return 0;
}#include <stdio.h>
int main() {
int rows = 5, cols = 5;
for (int i = 1; i <= rows; i++) {
for (int j = 1; j <= cols; j++) {
if (i == 3 && j == 2) {
continue;
}
if (i == 4 && j == 4) {
break;
}
printf("%d * %d = %d\t", i, j, i * j);
}
printf("\n");
}
return 0;
}#include <stdio.h>
int main() {
int num, prevNum = -1;
while (1) {
printf("Enter a number: ");
scanf("%d", &num);
if (num == prevNum) {
printf("Duplicate detected: %d\n", num);
break;
}
prevNum = num;
}
return 0;
}#include <stdio.h>
int main() {
int n;
scanf("%d", &n);
do {
printf("%d ", n);
n--;
} while (n >= 1);
printf("\n");
return 0;
}#include <stdio.h>
int main() {
char alphabet = 'A';
while (alphabet <= 'Z') {
printf("%c ", alphabet);
alphabet++;
}
printf("\n");
return 0;
}#include <stdio.h>
int main() {
int N, i = 1;
printf("Enter the value of N: ");
scanf("%d", &N);
printf("Even numbers: ");
while (i <= N) {
if (i % 2 == 0) {
printf("%d ", i);
}
i++;
}
printf("\n");
i = 1;
printf("Odd numbers: ");
while (i <= N) {
if (i % 2 != 0) {
printf("%d ", i);
}
i++;
}
printf("\n");
return 0;
}#include <stdio.h>
#include <stdlib.h>
#include <time.h>
int main() {
int number, guess, attempts = 0;
srand(time(0));
number = rand() % 100 + 1;
do {
printf("Guess a number between 1 and 100: ");
scanf("%d", &guess);
attempts++;
if (guess > number) {
printf("Too high!\n");
} else if (guess < number) {
printf("Too low!\n");
} else {
printf("Correct! You guessed in %d attempts.\n", attempts);
}
} while (guess != number);
return 0;
}#include <stdio.h>
int main() {
int rows, i, j, space;
rows = 5;
for (i = 1; i <= rows; i++) {
for (space = i; space < rows; space++)
printf(" ");
for (j = 1; j <= (2 * i - 1); j++)
printf("*");
printf("\n");
}
for (i = rows - 1; i >= 1; i--) {
for (space = i; space < rows; space++)
printf(" ");
for (j = 1; j <= (2 * i - 1); j++)
printf("*");
printf("\n");
}
return 0;
}#include <stdio.h>
int main() {
int rows, i, j, space;
rows = 5;
for (i = rows; i >= 1; --i) {
for (space = 0; space < rows - i; ++space)
printf(" ");
for (j = i; j <= 2 * i - 1; ++j)
printf("* ");
for (j = 0; j < i - 1; ++j)
printf("* ");
printf("\n");
}
return 0;
}#include <stdio.h>
int main() {
int rows, i, j;
scanf("%d", &rows);
for (i = 1; i <= rows; i++) {
for (j = 1; j <= i; j++) {
printf("*");
}
printf("\n");
}
return 0;
}#include <stdio.h>
int main() {
int rows, i, j, space, number = 1;
printf("Enter number of rows: ");
scanf("%d", &rows);
for (i = 0; i < rows; i++) {
for (space = 1; space <= rows - i; space++)
printf(" ");
for (j = 0; j <= i; j++) {
if (j == 0 || i == 0)
number = 1;
else
number = number * (i - j + 1) / j;
printf("%4d", number);
}
printf("\n");
}
return 0;
}#include <stdio.h>
int main() {
int rows, num = 1;
scanf("%d", &rows);
for (int i = 1; i <= rows; i++) {
for (int j = 1; j <= i; j++) {
printf("%d ", num);
num++;
}
printf("\n");
}
return 0;
}#include <stdio.h>
int main() {
int n, i;
printf("Enter a number: ");
scanf("%d", &n);
for (i = 1; i <= 10; i++) {
printf("%d * %d = %d\n", n, i, n * i);
}
return 0;
}