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LeetCode, GeeksForGeeks Problem of the day solution

LeetCode, GeeksForGeeks Problem of the day solution

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Complete daily challenges from LeetCode, GeeksForGeeks and redeem their rewards Channel link : https://t.me/leetcode_gfg_potd

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GFG | Problem of the day :

class Solution { public: int getWinner(vector& arr, int k) { int first=0; int second=1; int count=0; while(first < arr.size() && second< arr.size()){ if(count==k) return arr[first]; if(arr[first] > arr[second]){ count++; second++; } else{ count=1; while(first!=second){ first++; } first++; int temp=second; second= first; first= temp; } } return arr[first]; } };

LeetCode | Daily challenge :

class Solution { public: vector<int> topK(vector<int>& nums, int k) { priority_queue <pair<int,int>> pq; unordered_map <int,int> map; vector<int> ans; for (auto i : nums) { map[i]++; } for (auto i : map) { pq.push({i.second,i.first}); } while (k--) { ans.push_back(pq.top().second); pq.pop(); } return ans; } };

GFG | Problem of the day :

class Solution { public: int getLastMoment(int n, vector& left, vector& right) { if(right.size()==NULL){ sort(left.begin(),left.end()); return left[left.size()-1]; } if(left.size()==NULL){ sort(right.begin(),right.end()); return n-right[0]; } sort(left.begin(),left.end()); sort(right.begin(),right.end()); int mini=right[0]; int maxi=left[left.size()-1]; if(maxi>=abs(mini-n))return maxi; else return abs(mini-n); } };

LeetCode | Daily challenge :

class Solution { public: int transitionPoint(int arr[], int n) { for(int i=0;i

GFG | Problem of the day :

class Solution { public: vector buildArray(vector& target, int n) { vectors; int x=1; vectorv; int j=0; for(int i=1;i<=n;i++){ v.push_back(i); s.push_back("Push"); if(i==target[j]){ j++; } else{ v.pop_back(); s.push_back("Pop"); } if(v==target) break; } return s; } };

LeetCode | Daily challenge :

class Solution{ public: // Function to check if the // Pythagorean triplet exists or not bool checkTriplet(int arr[], int n) { vectorv(1001,0); for(int i=0;i

GFG | Problem of the day :

class Solution { public: int result = 0; int traverse(TreeNode* node, int ¤tSum){ if(node == nullptr){ return 0; } int temp = currentSum; currentSum = currentSum + node->val; int left = 0, right = 0; if(node->left!=nullptr) left = 1 + traverse(node->left, currentSum); if(node->right!=nullptr) right = 1 + traverse(node->right, currentSum); int n = left + right; int avg = int(floor(((currentSum - temp) / ((n+1) * 1.0)))); if(avg == node->val){ result++; } return n; } int averageOfSubtree(TreeNode* root) { int sum = 0; traverse(root, sum); return result; } };

LeetCode | Daily challenge :

class Solution{ public: int minDist(int a[], int n, int x, int y) { int ans=INT_MAX; int x1=-1; int y1=-1; for(int i=0;i

GFG | Problem of the day :

class Solution { public: vectorans; int mx_freq=0; unordered_mapmp; void dfs(TreeNode* root){ if(root==NULL) return; int f= mp[root->val]++; if(f>mx_freq) {mx_freq=f; ans={root->val}; } else if(f==mx_freq) ans.push_back(root->val); dfs(root->left); dfs(root->right); } vector findMode(TreeNode* root) { dfs(root); return ans; } };

LeetCode | Daily challenge :

class Solution{ public: //Function to count the frequency of all elements from 1 to N in the array. void frequencyCount(vector& arr,int N, int P) { unordered_mapmp(P); for(int i=0;i