LeetCode, GeeksForGeeks Problem of the day solution
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class Solution {
public:
vector findArray(vector& pref) {
vector arr;
arr.push_back(pref[0]);
for(int i = 1; i
class Solution{
public:
void pushZerosToEnd(int arr[], int n) {
vectorv;
int count=0;
for(int i=0;i
class Solution {
public:
static int compare(int a, int b){
int v1 = __builtin_popcount(a);
int v2 = __builtin_popcount(b);
if(v1 != v2)
return v1 sortByBits(vector& arr) {
sort(arr.begin(), arr.end(), compare);
return arr;
}
};
class Solution{
public:
// Returns sum of bitwise OR
// of all pairs
long long int sumXOR(int arr[], int n)
{
vectorv(31,0);
long long int ans=0;
for(int i=0;i
class Solution {
public:
int poorPigs(int buckets, int minutesToDie, int minutesToTest) {
int periods = minutesToTest/minutesToDie;
return ceil(log2(buckets) / log2(periods+1));
}
};
class Solution
{
public:
// Function to check if Kth bit is set or not.
bool checkKthBit(int n, int k)
{
return (n&(1<
class Solution {
private:
int mod = 1000000007;
unordered_map > mp;
public:
int vowelPermutations(int n, int i, char prev, vector >& dp){
if(i>n){
return 0;
}
if(i==n){
switch(prev){
case 'a':
return 1;
break;
case 'e':
return 2;
break;
case 'i':
return 4;
break;
case 'o':
return 2;
break;
case 'u':
return 1;
break;
default:
return 5;
}
}
int index = prev - 'a';
if(dp[i][index] != -1){
return dp[i][index];
}
long long result = 0;
for(auto next:mp[prev]){
result += vowelPermutations(n, i+1, next, dp);
}
dp[i][index] = result%mod;
return dp[i][index];
}
int countVowelPermutation(int n) {
mp['b'] = {'a', 'e','i','o', 'u'};
mp['a'] = {'e'};
mp['e'] = {'a','i'};
mp['i'] = {'a', 'e', 'o', 'u'};
mp['o'] = {'i','u'};
mp['u'] = {'a'};
vector > dp(n+2, vector(27, -1));
int len = 1;
char prev = 'b';
return vowelPermutations(n, len, prev, dp);
}
};
class Solution
{
public:
int is_bleak(int n)
{
for(int i=0;i<32 and i<=n;i++)
{
if(__builtin_popcount(n-i)==i)
return 0;
}
return 1;
}
};
class Solution {
public:
string expand(int s, int e, string& str){
while(s>=0 && elg.size()){
lg = odd;
}
}
return lg;
}
};
class Solution{
public:
int minimumNumberOfDeletions(string s) {
int n = s.size();
vector> dp(n + 1,vector(n + 1,-1));
string s2 = s;
reverse(s2.begin(),s2.end());
int lps = solve(s2,s,dp,n,n);
return s.size() - lps;
}
int solve(string &s2,string &s1,vector> &dp,int n1,int n2){
if(n1==0 or n2==0){
return 0;
}
if(dp[n1][n2]!=-1){
return dp[n1][n2];
}
if(s1[n1 - 1]==s2[n2 - 1]){
return dp[n1][n2] = 1 + solve(s2,s1,dp,n1 - 1,n2 - 1);
}
return dp[n1][n2] = max(solve(s2,s1,dp,n1 - 1,n2),solve(s2,s1,dp,n1,n2 - 1));
}
};
