en
Feedback
IBM Oa Help | Oa Exam Helper

IBM Oa Help | Oa Exam Helper

Open in Telegram

We are here to clear All types of Exams Admin : @Codercpp001 (aka) KMK βœ… INTERVIEW HELP AVAILABLE 1-Coding Round 2-Aptitude and Reasoning Round 3-Communication round 4-Resume building πŸŽ‰Job updates will be posted here.

Show more
1 163
Subscribers
-224 hours
-57 days
+530 days
Posts Archive
Today test Accenture slot Walmart slot Cognizant slot available βœ…βœ…βœ…

Dm me for today help βœ…βœ…βœ…

Cognizant exam help available today βœ…βœ…βœ…

Join these group for discussion

Accenture slot available book your slot for tomorrow βœ…βœ…

Just respond

If more student will respond then we will be starting it soon

We are starting a cp mentorship for free if you genuinely want guidance then we will start

Amazon 6 m sde both code executed βœ…βœ…βœ…
Amazon 6 m sde both code executed βœ…βœ…βœ…

Accenture 7 pm slot available βœ…βœ…βœ…book your slot

One great opportunity for you if you are adding 5 of your friend to these group we have a giveaway for you guys πŸ₯‚πŸ₯³πŸ₯³just share the group link and send screenshot

If anyone want experience certificate or want to switch to different company then we provide you a experience certificate dm ...if you want genuinely

βœ…βœ…

Accenture help availble book your slot very low price

message for rubrik

Uber all code done dm @klarqk

Wants me to post linkedin codes?
Anonymous voting

long calculateTotalRegion(vector<int> heights) { int n = heights.size(); vector<int> left(n, 1), right(n, 1); stack<int> st; for (int i = 0; i < n; ++i) { while (!st.empty() && heights[st.top()] <= heights[i]) { st.pop(); } if (!st.empty()) { left[i] = i - st.top(); } else { left[i] = i + 1; } st.push(i); } while (!st.empty()) { st.pop(); } for (int i = n - 1; i >= 0; --i) { while (!st.empty() && heights[st.top()] <= heights[i]) { st.pop(); } if (!st.empty()) { right[i] = st.top() - i; } else { right[i] = n - i; } st.push(i); } long totalRegion = 0; for (int i = 0; i < n; ++i) { totalRegion += left[i] + right[i] - 1; } return totalRegion; }