Leetcode with dani

ማስታወቂያ ነው ⬆️

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ማስታወቂያ

we got this through @a2svmemesbot

እንኳን ለ ትንሳኤ በዓል በሰላም አደረሳችሁ መልካም በዓል ይሁንላችሁ

When someone mentions on LinkedIn "I finally landed my dream job", they miss to tell you about Let's think about it step by step. Why Do You Need a Job? Before jumping into any career path, ask yourself: ➤ Why do I need a job? Is it for financial stability? Personal growth? A sense of purpose? Jobs can provide structure, income, and learning opportunities. But they are not the only way to achieve these goals. Clarity on your "why" will help you make smarter decisions. What if the market is not in your favor, which it is right now? The job market is unpredictable. Recessions, layoffs, and industry shifts happen. So, what's your backup plan? Here are some alternatives: Freelancing: Offer your skills to clients worldwide. Platforms like Upwork or Fiverr make this easier than ever. Starting a Side Hustle: Turn hobbies into income. Think tutoring, content creation, or selling digital products. Remote Work: Explore temporary or part-time remote jobs to stay flexible while earning. Your job shouldn't be your only source of income. Think of ways to diversify. How Can You Acquire More Skills to Turn the Tables? If the market isn't working for you, invest in yourself. ➤ Here's how: Take Online Courses: Platforms like Coursera or Udemy offer affordable courses in trending fields. Network: Attend webinars, join LinkedIn groups, and connect with industry leaders. Experiment: Take on small projects outside your comfort zone to build confidence and expertise. Every new skill adds value to your profile and opens new opportunities. Look for jobs that offer more than a paycheck A great job isn't just about money. ➤ It's about: Learning: Does the role teach you something new? Growth: Will it help you progress in your career? Stability: Does it offer financial and mental security? If a job doesn't check these boxes, it might be time to reassess. Hustle, but avoid toxicity ➤ Hard work is essential, but remember: Hustle is healthy; toxicity is not. Your mental health and well-being are non-negotiable. Walk away from environments that drain you. Success should feel empowering, not exhausting. So, Build multiple income streams. Keep growing and learning. Prioritize your happiness and health. So, what's your next step? Are you building skills, exploring alternatives, or rethinking your path? Tell me in the comments below!

Was talking to Emre and yeah A2SV is staying and the issues are resolving. There's still an issue of funding but he's very hopeful about it now. We won :) I'm super glad and I'm happy for all the present and future A2SVians. This's wonderful news. Thank you everyone that supported, shared and encouraged this. ❤️

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I HAVE INTERVIEWED ON A2SV ON THURSDAY AND THE QUESTION WAS /* Question Description Given a string s and an integer k, return the number of substrings in s of length k with no repeated characters. Example 1: Input: s = "havefunonleetcode", k = 5 Output: 6 Explanation: There are 6 substrings they are: 'havef','avefu','vefun','efuno','etcod','tcode'. Example 2: Input: s = "home", k = 5 Output: 0 Explanation: Notice k can be larger than the length of s. In this case, it is not possible to find any substring. Constraints: 1 <= s.length <= 104 s consists of lowercase English letters. 1 <= k <= 104 */ FINALLY I HAVE SOLVED THE QUESTION LIKE THIS IN C++ MAY BE IT IS USEFUL

#include <bits/stdc++.h>
using namespace std;
class Solution {
    public :
        int solve (string s,int k){
            vector <int> freq(26);
            
            int l=0;int r=0;
            int offset=(int)'a';
            int ans=0;
            while (r<s.size()){
                if (r-l<k-1){   
                   freq[s[r]-offset]++;
                    r++;             
                }else if (r-l==k-1){
                    freq[s[r]-offset]++;
                    r++;
                    bool t=true;
                    for (int x:freq){
                        if (x>1){
                          t=false;
                        }
                    }
                    t?ans+=1:ans=ans;
                    
                }else if (r-l>k-1){
                    freq[s[l]-offset]--;
                    l++;
                }
                
            }
            return ans;
        }
};

int main () {
    string s="abcdefhijklmnopqrstuvwxyz";
    int k=5;
    Solution* sol=new Solution();
    cout<<sol->solve(s,k);
}

Question Description You are given a 0-indexed string s consisting of only lowercase English letters. Return the number of substrings in s that begin and end with the same character. A substring is a contiguous non-empty sequence of characters within a string. Example 1: Input: s = "abcba" #"a", "b", "c", "b","a",abcba","bcb" a:2 b:2 c : 1 Output: 7 Explanation: The substrings of length 1 that start and end with the same letter are: "a", "b", "c", "b", and "a". The substring of length 3 that starts and ends with the same letter is: "bcb". The substring of length 5 that starts and ends with the same letter is: "abcba". Example 2: Input: s = "abacad" Output: 9 Explanation: The substrings of length 1 that start and end with the same letter are: "a", "b", "a", "c", "a", and "d". The substrings of length 3 that start and end with the same letter are: "aba" and "aca". The substring of length 5 that starts and ends with the same letter is: "abaca". Example 3: Input: s = "a" Output: 1 Explanation: The substring of length 1 that starts and ends with the same letter is: "a". Constraints: 1 <= s.length <= 105 s consists only of lowercase English letters

Educational Codeforces Round 177 (rated for Div. 2) starts on the 3rd of April at 14:35 UTC. Please, join by the link https://codeforces.com/contests/2086

If anyone has questions or is interviewed by A2SV today, please share the questions with me. I'll post them in this channel! @zprogramming_bot