Untold Coding
|| जय श्री राम || #100dayschallenge Sharing HTML, CSS and JS magic ✨ Join our Creative Journey!🎉
Show more📈 Analytical overview of Telegram channel Untold Coding
Channel Untold Coding (@untoldcoding) in the English language segment is an active participant. Currently, the community unites 31 445 subscribers, ranking 3 405 in the Technologies & Applications category and 15 035 in the India region.
📊 Audience metrics and dynamics
Since its creation on невідомо, the project has demonstrated rapid growth, gathering an audience of 31 445 subscribers.
According to the latest data from 10 August, 2025, the channel demonstrates stable activity. Although there has been a change in the number of participants by -416 over the last 30 days and by 0 over the last 24 hours, overall reach remains high.
- Verification status: Not verified
- Engagement rate (ER): The average audience engagement rate is 0%. Within the first 24 hours after publication, content typically collects N/A% reactions from the total number of subscribers.
- Post reach: On average, each post receives 0 views. Within the first day, a publication typically gains 0 views.
- Reactions and interaction: The audience actively supports content: the average number of reactions per post is 0.
📝 Description and content policy
The author describes the resource as a platform for expressing subjective opinions:
“|| जय श्री राम ||
#100dayschallenge
Sharing HTML, CSS and JS magic ✨
Join our Creative Journey!🎉”
Thanks to the high frequency of updates (latest data received on 11 August, 2025), the channel maintains relevance and a high level of publication reach. Analytics show that the audience actively interacts with content, making it an important point of influence in the Technologies & Applications category.
Question of the day#include <stdio.h> void count(int n) { static int d = 1; // Initialize static variable printf("%d ", n); printf("%d ", d); d++; if (n > 1) { count(n - 1); } printf("%d ", d); } void main() { count(3); }
Question of the day#include<stdio.h #define square(x) x*x int main() { int a, b=3; a = square (b+2); printf("%d",a); return 0; }
