Advanced Problems
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Here we would share few Jee Advanced Level Or Olympiad Level Problems every Day and we would also upload it's Solution.
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Solution of the Above Problem
Idea: Apply beggar coin method
First ghost in the form of 2k+3
Second ghost in form of 2m+2
Third ghost in form of 2in
Fourth ghost in form of 2p+5
So,
2k+3+2m+2+2n+2p+5=24
2k+2m+2n+2p=14
(k+m+n+p)=7
Using beggar coin
C(10,3)=120 ways
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Funny Problem By Nrip Dave. if u want to send out your problems checkout the Pinned Comment
