Data Analyst Interview Resources
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Channel Data Analyst Interview Resources (@dataanalystinterview) in the English language segment is an active participant. Currently, the community unites 52 280 subscribers, ranking 3 330 in the Education category and 7 186 in the India region.
📊 Audience metrics and dynamics
Since its creation on невідомо, the project has demonstrated rapid growth, gathering an audience of 52 280 subscribers.
According to the latest data from 11 June, 2026, the channel demonstrates stable activity. Although there has been a change in the number of participants by 247 over the last 30 days and by 13 over the last 24 hours, overall reach remains high.
- Verification status: Not verified
- Engagement rate (ER): The average audience engagement rate is 2.55%. Within the first 24 hours after publication, content typically collects 0.92% reactions from the total number of subscribers.
- Post reach: On average, each post receives 1 332 views. Within the first day, a publication typically gains 479 views.
- Reactions and interaction: The audience actively supports content: the average number of reactions per post is 3.
- Thematic interests: Content is focused on key topics such as sql, row, |--, dataset, visualization.
📝 Description and content policy
The author describes the resource as a platform for expressing subjective opinions:
“Join our telegram channel to learn how data analysis can reveal fascinating patterns, trends, and stories hidden within the numbers! 📊
For ads & suggestions: @love_data”
Thanks to the high frequency of updates (latest data received on 12 June, 2026), the channel maintains relevance and a high level of publication reach. Analytics show that the audience actively interacts with content, making it an important point of influence in the Education category.
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⦁ Tuple: immutable, defined with ()
lst = [1, 2, 3]
tpl = (1, 2, 3)
2️⃣ How to reverse a string in Python?
s = "Hello"
rev = s[::-1] # 'olleH'
3️⃣ Write a function to find factorial using recursion.
def factorial(n):
return 1 if n == 0 else n * factorial(n-1)
4️⃣ How do you handle exceptions?
⦁ Use try and except blocks.
try:
x = 1 / 0
except ZeroDivisionError:
print("Cannot divide by zero")
5️⃣ Difference between == and is?
⦁ == compares values
⦁ is compares identities (memory locations)
6️⃣ How to check if a number is prime?
def is_prime(n):
if n < 2:
return False
for i in range(2,int(n**0.5)+1):
if n % i == 0:
return False
return True
7️⃣ What are list comprehensions? Give example.
⦁ Compact way to create lists
squares = [x*x for x in range(5)]
8️⃣ How to merge two dictionaries?
⦁ Python 3.9+
d1 = {'a':1}
d2 = {'b':2}
merged = d1 | d2
9️⃣ Explain *args and **kwargs.
⦁ *args: variable number of positional arguments
⦁ **kwargs: variable number of keyword arguments
10️⃣ How do you read a file in Python?
with open('file.txt', 'r') as f:
data = f.read()
Python Interview Resources: https://whatsapp.com/channel/0029VaiM08SDuMRaGKd9Wv0L
Tap ❤️ for moreSELECT department, AVG(salary)
FROM employees
WHERE salary > 3000
GROUP BY department
HAVING AVG(salary) > 5000;
2. Write a query to find the second-highest salary.
Solution:
SELECT MAX(salary) AS second_highest_salary
FROM employees
WHERE salary < (SELECT MAX(salary) FROM employees);
3. How do you fetch the first 5 rows of a table?
Solution:
SELECT * FROM employees
LIMIT 5; -- (MySQL/PostgreSQL)
For SQL Server:
SELECT TOP 5 * FROM employees;
4. Write a query to find duplicate records in a table.
Solution:
SELECT column1, column2, COUNT(*)
FROM table_name
GROUP BY column1, column2
HAVING COUNT(*) > 1;
5. How do you find employees who don’t belong to any department?
Solution:
SELECT *
FROM employees
WHERE department_id IS NULL;
6. What is a JOIN, and write a query to fetch data using INNER JOIN.
Solution:
A JOIN combines rows from two or more tables based on a related column.
SELECT e.name, d.department_name
FROM employees e
INNER JOIN departments d ON e.department_id = d.id;
7. Write a query to find the total number of employees in each department.
Solution:
SELECT department_id, COUNT(*) AS total_employees
FROM employees
GROUP BY department_id;
8. How do you fetch the current date in SQL?
Solution:
SELECT CURRENT_DATE; -- MySQL/PostgreSQL
SELECT GETDATE(); -- SQL Server
9. Write a query to delete duplicate rows but keep one.
Solution:
WITH CTE AS (
SELECT *, ROW_NUMBER() OVER (PARTITION BY column1, column2 ORDER BY id) AS rn
FROM table_name
)
DELETE FROM CTE WHERE rn > 1;
10. What is a Common Table Expression (CTE), and how do you use it?
Solution:
A CTE is a temporary result set defined within a query.
WITH EmployeeCTE AS (
SELECT department_id, COUNT(*) AS total_employees
FROM employees
GROUP BY department_id
)
SELECT * FROM EmployeeCTE WHERE total_employees > 10;
Hope it helps :)
#sql #dataanalysts
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