Data Analyst Interview Resources
Join our telegram channel to learn how data analysis can reveal fascinating patterns, trends, and stories hidden within the numbers! 📊 For ads & suggestions: @love_data
Show more📈 Analytical overview of Telegram channel Data Analyst Interview Resources
Channel Data Analyst Interview Resources (@dataanalystinterview) in the English language segment is an active participant. Currently, the community unites 52 643 subscribers, ranking 3 266 in the Education category and 6 692 in the India region.
📊 Audience metrics and dynamics
Since its creation on невідомо, the project has demonstrated rapid growth, gathering an audience of 52 643 subscribers.
According to the latest data from 02 September, 2026, the channel demonstrates stable activity. Although there has been a change in the number of participants by 7 over the last 30 days and by -7 over the last 24 hours, overall reach remains high.
- Verification status: Not verified
- Engagement rate (ER): The average audience engagement rate is 1.84%. Within the first 24 hours after publication, content typically collects 0.82% reactions from the total number of subscribers.
- Post reach: On average, each post receives 970 views. Within the first day, a publication typically gains 430 views.
- Reactions and interaction: The audience actively supports content: the average number of reactions per post is 2.
- Thematic interests: Content is focused on key topics such as sql, row, |--, dataset, visualization.
📝 Description and content policy
The author describes the resource as a platform for expressing subjective opinions:
“Join our telegram channel to learn how data analysis can reveal fascinating patterns, trends, and stories hidden within the numbers! 📊
For ads & suggestions: @love_data”
Thanks to the high frequency of updates (latest data received on 03 September, 2026), the channel maintains relevance and a high level of publication reach. Analytics show that the audience actively interacts with content, making it an important point of influence in the Education category.
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SELECT c.CustomerID, c. Name, AVG(o.Amount) AS AveragePurchase FROM Customers c JOIN Orders o ON c.CustomerID = o.CustomerID GROUP BY c.CustomerID, c. Name;📍2. Write a query to find the employee with the minimum salary in each department from a table Employees with columns EmployeeID, Name, DepartmentID, and Salary.
SELECT e1.DepartmentID, e1.EmployeeID, e1 .Name, e1.Salary FROM Employees e1 WHERE Salary = (SELECT MIN(Salary) FROM Employees e2 WHERE e2.DepartmentID = e1.DepartmentID);📍3. Write a SQL query to find all products that have never been sold. Assume you have a table Products (ProductID, ProductName) and a table Sales (SaleID, ProductID, Quantity).
SELECT p.ProductID, p.ProductName FROM Products p LEFT JOIN Sales s ON p.ProductID = s.ProductID WHERE s.ProductID IS NULL;📍4. Given a table Orders with columns OrderID, CustomerID, OrderDate, and a table OrderItems with columns OrderID, ItemID, Quantity, write a query to find the customer with the highest total order quantity.
SELECT o.CustomerID, SUM(oi.Quantity) AS TotalQuantity FROM Orders o JOIN OrderItems oi ON o.OrderID = oi.OrderID GROUP BY o.CustomerID ORDER BY TotalQuantity DESC LIMIT 1;📍5. Write a SQL query to find the earliest order date for each customer from a table Orders (OrderID, CustomerID, OrderDate).
SELECT CustomerID, MIN(OrderDate) AS EarliestOrderDate FROM Orders GROUP BY CustomerID;
