Data Analytics Projects - SQL, Excel, Tableau, Python & Power BI Interview Resources
Covering all technical and popular stuff about anything related to Data Science: AI, Big Data, Machine Learning, Statistics, general Math and the applications of former. Ads/ Promo: @love_data
Show more📈 Analytical overview of Telegram channel Data Analytics Projects - SQL, Excel, Tableau, Python & Power BI Interview Resources
Channel Data Analytics Projects - SQL, Excel, Tableau, Python & Power BI Interview Resources (@sqlproject) in the English language segment is an active participant. Currently, the community unites 39 679 subscribers, ranking 4 606 in the Education category and 9 819 in the India region.
📊 Audience metrics and dynamics
Since its creation on невідомо, the project has demonstrated rapid growth, gathering an audience of 39 679 subscribers.
According to the latest data from 26 August, 2026, the channel demonstrates stable activity. Although there has been a change in the number of participants by 56 over the last 30 days and by 3 over the last 24 hours, overall reach remains high.
- Verification status: Not verified
- Engagement rate (ER): The average audience engagement rate is 1.80%. Within the first 24 hours after publication, content typically collects 0.73% reactions from the total number of subscribers.
- Post reach: On average, each post receives 715 views. Within the first day, a publication typically gains 291 views.
- Reactions and interaction: The audience actively supports content: the average number of reactions per post is 2.
- Thematic interests: Content is focused on key topics such as analytic, dataset, visualization, sql, learning.
📝 Description and content policy
The author describes the resource as a platform for expressing subjective opinions:
“Covering all technical and popular stuff about anything related to Data Science: AI, Big Data, Machine Learning, Statistics, general Math and the applications of former.
Ads/ Promo: @love_data”
Thanks to the high frequency of updates (latest data received on 27 August, 2026), the channel maintains relevance and a high level of publication reach. Analytics show that the audience actively interacts with content, making it an important point of influence in the Education category.
COALESCE or IS NULL checks
3️⃣ Wrong JOIN Type
• INNER instead of LEFT
• Data silently disappears
• Always ask: Do you need unmatched rows?
4️⃣ Missing JOIN Conditions
• Creates cartesian product
• Rows explode
• Always join on keys
5️⃣ Filtering After JOIN Instead of Before
• Processes more rows than needed
• Slower performance
• Filter early using WHERE or subqueries
6️⃣ Using WHERE Instead of HAVING
• WHERE filters rows
• HAVING filters groups
• Aggregates fail without HAVING
7️⃣ Not Using Indexes
• Full table scans
• Slow dashboards
• Index columns used in JOIN, WHERE, ORDER BY
8️⃣ Relying on ORDER BY in Subqueries
• Order not guaranteed
• Results change
• Use ORDER BY only in final query
9️⃣ Mixing Data Types
• Implicit conversions
• Index not used
• Match column data types
🔟 No Query Validation
• Results look right but are wrong
• Always cross-check counts and totals
🧠 Practice Task
• Rewrite one query
• Remove SELECT *
• Add proper JOIN
• Handle NULLs
• Compare result count
SQL Resources: https://whatsapp.com/channel/0029VanC5rODzgT6TiTGoa1v
❤️ Double Tap For MoreSELECT MAX(salary)
FROM employees
WHERE salary < (SELECT MAX(salary) FROM employees);
2️⃣ List employees who earn more than the average salary.
SELECT name, salary
FROM employees
WHERE salary > (SELECT AVG(salary) FROM employees);
3️⃣ Show department-wise highest paid employee.
SELECT department, name, salary
FROM (
SELECT *,
RANK() OVER (PARTITION BY department ORDER BY salary DESC) AS rnk
FROM employees
) AS ranked
WHERE rnk = 1;
4️⃣ Display total sales made by each employee in 2023.
SELECT emp_id, SUM(amount) AS total_sales
FROM sales
WHERE YEAR(sale_date) = 2023
GROUP BY emp_id;
5️⃣ Retrieve products with price above average in their category.
SELECT p.name, p.category, p.price
FROM products p
WHERE price > (
SELECT AVG(price)
FROM products
WHERE category = p.category
);
6️⃣ Identify duplicate emails in the users table.
SELECT email, COUNT(*)
FROM users
GROUP BY email
HAVING COUNT(*) > 1;
7️⃣ Rank customers based on total purchase amount.
SELECT customer_id,
SUM(amount) AS total_spent,
RANK() OVER (ORDER BY SUM(amount) DESC) AS rank
FROM orders
GROUP BY customer_id;
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