Data Analytics Projects - SQL, Excel, Tableau, Python & Power BI Interview Resources
Covering all technical and popular stuff about anything related to Data Science: AI, Big Data, Machine Learning, Statistics, general Math and the applications of former. Ads/ Promo: @love_data
Show more๐ Analytical overview of Telegram channel Data Analytics Projects - SQL, Excel, Tableau, Python & Power BI Interview Resources
Channel Data Analytics Projects - SQL, Excel, Tableau, Python & Power BI Interview Resources (@sqlproject) in the English language segment is an active participant. Currently, the community unites 39 490 subscribers, ranking 4 752 in the Education category and 10 399 in the India region.
๐ Audience metrics and dynamics
Since its creation on ะฝะตะฒัะดะพะผะพ, the project has demonstrated rapid growth, gathering an audience of 39 490 subscribers.
According to the latest data from 09 June, 2026, the channel demonstrates stable activity. Although there has been a change in the number of participants by 197 over the last 30 days and by 10 over the last 24 hours, overall reach remains high.
- Verification status: Not verified
- Engagement rate (ER): The average audience engagement rate is 2.73%. Within the first 24 hours after publication, content typically collects 1.01% reactions from the total number of subscribers.
- Post reach: On average, each post receives 1 079 views. Within the first day, a publication typically gains 400 views.
- Reactions and interaction: The audience actively supports content: the average number of reactions per post is 3.
- Thematic interests: Content is focused on key topics such as analytic, dataset, visualization, sql, learning.
๐ Description and content policy
The author describes the resource as a platform for expressing subjective opinions:
โCovering all technical and popular stuff about anything related to Data Science: AI, Big Data, Machine Learning, Statistics, general Math and the applications of former.
Ads/ Promo: @love_dataโ
Thanks to the high frequency of updates (latest data received on 10 June, 2026), the channel maintains relevance and a high level of publication reach. Analytics show that the audience actively interacts with content, making it an important point of influence in the Education category.
COALESCE or IS NULL checks
3๏ธโฃ Wrong JOIN Type
โข INNER instead of LEFT
โข Data silently disappears
โข Always ask: Do you need unmatched rows?
4๏ธโฃ Missing JOIN Conditions
โข Creates cartesian product
โข Rows explode
โข Always join on keys
5๏ธโฃ Filtering After JOIN Instead of Before
โข Processes more rows than needed
โข Slower performance
โข Filter early using WHERE or subqueries
6๏ธโฃ Using WHERE Instead of HAVING
โข WHERE filters rows
โข HAVING filters groups
โข Aggregates fail without HAVING
7๏ธโฃ Not Using Indexes
โข Full table scans
โข Slow dashboards
โข Index columns used in JOIN, WHERE, ORDER BY
8๏ธโฃ Relying on ORDER BY in Subqueries
โข Order not guaranteed
โข Results change
โข Use ORDER BY only in final query
9๏ธโฃ Mixing Data Types
โข Implicit conversions
โข Index not used
โข Match column data types
๐ No Query Validation
โข Results look right but are wrong
โข Always cross-check counts and totals
๐ง Practice Task
โข Rewrite one query
โข Remove SELECT *
โข Add proper JOIN
โข Handle NULLs
โข Compare result count
SQL Resources: https://whatsapp.com/channel/0029VanC5rODzgT6TiTGoa1v
โค๏ธ Double Tap For MoreSELECT MAX(salary)
FROM employees
WHERE salary < (SELECT MAX(salary) FROM employees);
2๏ธโฃ List employees who earn more than the average salary.
SELECT name, salary
FROM employees
WHERE salary > (SELECT AVG(salary) FROM employees);
3๏ธโฃ Show department-wise highest paid employee.
SELECT department, name, salary
FROM (
SELECT *,
RANK() OVER (PARTITION BY department ORDER BY salary DESC) AS rnk
FROM employees
) AS ranked
WHERE rnk = 1;
4๏ธโฃ Display total sales made by each employee in 2023.
SELECT emp_id, SUM(amount) AS total_sales
FROM sales
WHERE YEAR(sale_date) = 2023
GROUP BY emp_id;
5๏ธโฃ Retrieve products with price above average in their category.
SELECT p.name, p.category, p.price
FROM products p
WHERE price > (
SELECT AVG(price)
FROM products
WHERE category = p.category
);
6๏ธโฃ Identify duplicate emails in the users table.
SELECT email, COUNT(*)
FROM users
GROUP BY email
HAVING COUNT(*) > 1;
7๏ธโฃ Rank customers based on total purchase amount.
SELECT customer_id,
SUM(amount) AS total_spent,
RANK() OVER (ORDER BY SUM(amount) DESC) AS rank
FROM orders
GROUP BY customer_id;
๐ฌ Double Tap โค๏ธ For More!
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