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Tcs NQT Solution Group

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TCS IRA PYTHON 1, A 2, 2003 3, machine learning 4, 2018 5, AI 6, C 8, A 9, B 10, D 11, D 12, B 13, B 14, A 15, C @codingsolution_group @codingsolution_group @codingsolution_group

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TCS IRA Java IRA 26 - all 27 - id 28 - ol 29 - a and b 30 - before it loads 31- error 32 - false true 33- 35 @codingsolution_group @codingsolution_group @codingsolution_group

Tree code l=list(map(int,input().split(','))) m=[] for i in range(5): k=[] for j in range(5): k.append('O') m.append(k) for i in l: a1=(i-1)//5 a2=(i-1)%5 m[a1][a2]='X' num=0 for i in m: x=0 o=0 for j in i: if j=='X': x=x+1 else: o=o+1 if x==5: num=1 if o==5: num=2 for i in range(5): x=0 o=0 for j in range(5): if m[j][i]=='X': x=x=1 else: o=o+1 if x==5: num=1 if o==5: num=2 o1=0 x1=0 o=0 x=0 for i in range(5): for j in range(5): if i==j: if m[i][j]=='X': x1=x1+1 else: o1=o1+1 if i==5-j-1: if m[i][j]=='X': x=x+1 else: o=o+1 if o1==5 or o==5: num=2 if x1==5 or x==5: num=1 print(num) for i in range(5): for j in range(5): print(m[i][j],end='') if j!=4: print(',',end='') print() @codingsolution_group @codingsolution_group @codingsolution_group

Minimum strings code int minStringMoves(char* a, char* b) { int length, pos, i, j, moves=0; char *ptr; length = strlen(a); for(i=0;i<length;i++) { // Find the first occurrence of b[i] in a ptr = strchr(a,b[i]); pos = ptr - a; // If its the last element, swap with the first if(i==0 && pos == length-1) { swap(&a[0], &a[length-1]); moves++; } // Else swap from current index till pos else { for(j=pos;j>i;j--) { swap(&a[j],&a[j-1]); moves++; } } // If equal, break if(strcmp(a,b) == 0) break; } return moves; } @codingsolution_group @codingsolution_group @codingsolution_group

Longest palindrome int longestPalindrome(vector<string> a,int n) { string pair1[n]; string pair2[n]; int r = 0; for (int i = 0; i < n; i++) { string s = a[i]; reverse(s.begin(), s.end()); for (int j = i + 1; j < n; j++) { if (a[i] != "" && a[j] != "") { if (s == a[j]) { pair1[r] = a[i]; pair2[r++] = a[j]; a[i] = ""; a[j] = ""; break; } } } } string s1 = ""; for (int i = 0; i < n; i++) { string s = a[i]; reverse(a[i].begin(), a[i].end()); if (a[i] != "") { if (a[i] == s) { s1 = a[i]; break; } } } string ans = ""; // Update the answer with // all strings of pair1 for (int i = 0; i < r; i++) { ans = ans + pair1[i]; } // Update the answer with // palindromic string s1 if (s1 != "") { ans = ans + s1; } // Update the answer with // all strings of pair2 for (int j = r - 1; j >= 0; j--) { ans = ans + pair2[j]; } return ans.size(); } @codingsolution_group @codingsolution_group @codingsolution_group

✅Alice code : def smallest(n): arr = list() x = 0 for i in range(n): x = int(input()) arr.append(x) arr = sorted(arr) count = 1 temp = list() for j in range(1, n): if arr[j] == arr[j-1] + 1: count += 1 else: temp.append(count) count = 1 temp.append(count) return min(temp) n = int(input()) res = smallest(n) print(res) def isP(n): if n<=3: return True if ((n%2==0)|(n%3==0)): return False for d in range(5,int(n*5)+1,6): if ((n%d==0)|(n%(d+2)==0)): return False return True def getP(m): P=[1,2] for n in range(3,m+1,2): if isP(n): P.append(n) return P P=getP(int(105+1000)) g = int(input().strip()) for a0 in range(g): n = int(input().strip()) for i in range(len(P)): if P[i]>n: c=i-1 break if c%2==1: print("Alice") else: print("Bob") @codingsolution_group @codingsolution_group @codingsolution_group

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Set 2 C
Set 2 C