C Programming Codes
C Programming Codes || Quizzes || DSA Learn along with the community Any queries admin - @Pradeep_saii
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Channel C Programming Codes (@c_programming_codes) in the English language segment is an active participant. Currently, the community unites 13 431 subscribers, ranking 9 534 in the Technologies & Applications category and 32 075 in the India region.
π Audience metrics and dynamics
Since its creation on Π½Π΅Π²ΡΠ΄ΠΎΠΌΠΎ, the project has demonstrated rapid growth, gathering an audience of 13 431 subscribers.
According to the latest data from 11 June, 2026, the channel demonstrates stable activity. Although there has been a change in the number of participants by -239 over the last 30 days and by -9 over the last 24 hours, overall reach remains high.
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- Thematic interests: Content is focused on key topics such as input, string, scanf("%d, array, element.
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βC Programming Codes || Quizzes || DSA
Learn along with the community
Any queries
admin - @Pradeep_saiiβ
Thanks to the high frequency of updates (latest data received on 12 June, 2026), the channel maintains relevance and a high level of publication reach. Analytics show that the audience actively interacts with content, making it an important point of influence in the Technologies & Applications category.
#include <stdio.h>
int main() {
int n;
printf("Enter the number of elements: ");
scanf("%d", &n);
int arr[n];
printf("Enter the elements:n");
for (int i = 0; i < n; i++) {
scanf("%d", &arr[i]);
}
int uniqueArr[n];
int uniqueSize = 0;
for (int i = 0; i < n; i++) {
int isDuplicate = 0;
for (int j = 0; j < uniqueSize; j++) {
if (arr[i] == uniqueArr[j]) {
isDuplicate = 1;
break;
}
}
if (!isDuplicate) {
uniqueArr[uniqueSize] = arr[i];
uniqueSize++;
}
}
printf("Array with unique elements:n");
for (int i = 0; i < uniqueSize; i++) {
printf("%d ", uniqueArr[i]);
}
printf("n");
return 0;
}
π€ Output:
Input: 5 Input: 1 Input: 2 Input: 2 Input: 3 Input: 4 Output: Enter the number of elements: Enter the elements: Array with unique elements: 1 2 3 4 Input: 7 Input: 5 Input: 2 Input: 5 Input: 1 Input: 2 Input: 3 Input: 4 Output: Enter the number of elements: Enter the elements: Array with unique elements: 5 2 1 3 4
#include <stdio.h>
#include <stdbool.h>
int main() {
int n;
printf("Enter the size of the array: ");
scanf("%d", &n);
int arr[n];
printf("Enter the elements of the array: ");
for (int i = 0; i < n; i++) {
scanf("%d", &arr[i]);
}
bool isSorted = true;
for (int i = 0; i < n - 1; i++) {
if (arr[i] > arr[i + 1]) {
isSorted = false;
break;
}
}
if (isSorted) {
printf("Array is sorted.n");
} else {
printf("Array is not sorted.n");
}
return 0;
}
π€ Output:
Input: 5 Input: 1 2 3 4 5 Output: Array is sorted. Input: 5 Input: 5 4 3 2 1 Output: Array is not sorted. Input: 4 Input: 1 2 4 3 Output: Array is not sorted. Input: 3 Input: 1 1 1 Output: Array is sorted. Input: 1 Input: 10 Output: Array is sorted.
#include <stdio.h>
int main() {
int n, i, temp;
printf("Enter the number of elements in the array: ");
scanf("%d", &n);
int arr[n];
printf("Enter the elements of the array:n");
for (i = 0; i < n; i++) {
scanf("%d", &arr[i]);
}
// Reversing the array
for (i = 0; i < n / 2; i++) {
temp = arr[i];
arr[i] = arr[n - i - 1];
arr[n - i - 1] = temp;
}
printf("Reversed array: ");
for (i = 0; i < n; i++) {
printf("%d ", arr[i]);
}
printf("n");
return 0;
}
π€ Output:
Input: 5 Input: 1 Input: 2 Input: 3 Input: 4 Input: 5 Output: Enter the number of elements in the array: Enter the elements of the array: Reversed array: 5 4 3 2 1 Input: 6 Input: 10 Input: 20 Input: 30 Input: 40 Input: 50 Input: 60 Output: Enter the number of elements in the array: Enter the elements of the array: Reversed array: 60 50 40 30 20 10
#include <stdio.h>
int main() {
int n, i;
float sum = 0.0, average;
printf("Enter the number of elements: ");
scanf("%d", &n);
float arr[n];
printf("Enter the elements:n");
for (i = 0; i < n; i++) {
scanf("%f", &arr[i]);
sum += arr[i];
}
average = sum / n;
printf("Average = %.2fn", average);
return 0;
}
π€ Output:
Input: 3 Input: 1.0 Input: 2.0 Input: 3.0 Output: Enter the number of elements: Enter the elements: Average = 2.00
#include <stdio.h>
int main() {
int n, i, sum = 0;
printf("Enter the number of elements in the array: ");
scanf("%d", &n);
int arr[n];
printf("Enter the elements of the array:n");
for (i = 0; i < n; i++) {
scanf("%d", &arr[i]);
}
for (i = 0; i < n; i++) {
sum += arr[i];
}
printf("Sum of all elements in the array = %dn", sum);
return 0;
}
π€ Output:
Input: 5 Input: 1 Input: 2 Input: 3 Input: 4 Input: 5 Output: Enter the number of elements in the array: Enter the elements of the array: Sum of all elements in the array = 15
#include <stdio.h>
int main() {
int arr[5];
int smallest;
int i;
printf("Enter 5 integer elements:n");
for (i = 0; i < 5; i++) {
scanf("%d", &arr[i]);
}
smallest = arr[0];
for (i = 1; i < 5; i++) {
if (arr[i] < smallest) {
smallest = arr[i];
}
}
printf("Smallest element: %dn", smallest);
return 0;
}
π€ Output:
Input: 5 Input: 2 Input: 8 Input: 1 Input: 9 Output: Enter 5 integer elements: Output: Smallest element: 1
#include <stdio.h>
int main() {
int n;
printf("Enter the number of elements in the array: ");
scanf("%d", &n);
int arr[n];
printf("Enter the elements of the array:n");
for (int i = 0; i < n; i++) {
scanf("%d", &arr[i]);
}
int largest = arr[0];
for (int i = 1; i < n; i++) {
if (arr[i] > largest) {
largest = arr[i];
}
}
printf("The largest element in the array is: %dn", largest);
return 0;
}
π€ Output:
Input: 5 Input: 12 Input: 5 Input: 28 Input: 3 Input: 19 Output: Enter the number of elements in the array: Enter the elements of the array: The largest element in the array is: 28
#include <stdio.h>
int sum_natural(int n) {
if (n == 0) {
return 0;
} else {
return n + sum_natural(n - 1);
}
}
int main() {
int num;
printf("Enter a positive integer: ");
scanf("%d", &num);
if (num < 0) {
printf("Please enter a non-negative integer.n");
} else {
int sum = sum_natural(num);
printf("Sum of natural numbers up to %d = %dn", num, sum);
}
return 0;
}
π€ Output:
Input: 5 Output: Enter a positive integer: Sum of natural numbers up to 5 = 15 Input: 0 Output: Enter a positive integer: Sum of natural numbers up to 0 = 0 Input: -3 Output: Enter a positive integer: Please enter a non-negative integer.
#include <stdio.h>
void increment(int *n) {
*n = *n + 1;
}
int main() {
int num = 10;
printf("Before increment: %dn", num);
increment(&num);
printf("After increment: %dn", num);
return 0;
}
π€ Output:
Before increment: 10 After increment: 11
#include <stdio.h>
void modifyValue(int x) {
x = x + 10;
printf("Value inside function: %dn", x);
}
int main() {
int num;
printf("Enter an integer: ");
scanf("%d", &num);
printf("Value before function call: %dn", num);
modifyValue(num);
printf("Value after function call: %dn", num);
return 0;
}
π€ Output:
Input: 5 Output: Enter an integer: Value before function call: 5 Value inside function: 15 Value after function call: 5
#include <stdio.h>
int factorial(int n) {
int fact = 1;
for (int i = 1; i <= n; i++) {
fact *= i;
}
return fact;
}
int isStrong(int num) {
int originalNum = num;
int sum = 0;
while (num > 0) {
int digit = num % 10;
sum += factorial(digit);
num /= 10;
}
if (sum == originalNum) {
return 1;
} else {
return 0;
}
}
int main() {
int number;
printf("Enter a number: ");
scanf("%d", &number);
if (isStrong(number)) {
printf("%d is a strong number.n", number);
} else {
printf("%d is not a strong number.n", number);
}
return 0;
}
π€ Output:
Input: 145 Output: 145 is a strong number. Input: 123 Output: 123 is not a strong number. Input: 40585 Output: 40585 is a strong number.
#include <stdio.h>
int isPerfect(int num) {
int sum = 1;
for (int i = 2; i * i <= num; i++) {
if (num % i == 0) {
if (i * i != num)
sum = sum + i + num / i;
else
sum = sum + i;
}
}
if (sum == num && num != 1)
return 1; // True
else
return 0; // False
}
int main() {
int number;
printf("Enter a number: ");
scanf("%d", &number);
if (isPerfect(number)) {
printf("%d is a perfect numbern", number);
} else {
printf("%d is not a perfect numbern", number);
}
return 0;
}
π€ Output:
Input: 6 Output: 6 is a perfect number Input: 28 Output: 28 is a perfect number Input: 12 Output: 12 is not a perfect number Input: 496 Output: 496 is a perfect number Input: 8128 Output: 8128 is a perfect number Input: 1 Output: 1 is not a perfect number Input: 0 Output: 0 is not a perfect number Input: -1 Output: -1 is not a perfect number
#include <stdio.h>
#include <math.h>
int binaryToDecimal(long long n) {
int decimalNumber = 0, i = 0, remainder;
while (n!=0) {
remainder = n % 10;
n /= 10;
decimalNumber += remainder * pow(2, i);
++i;
}
return decimalNumber;
}
int main() {
long long n;
printf("Enter a binary number: ");
scanf("%lld", &n);
printf("Decimal equivalent: %d", binaryToDecimal(n));
return 0;
}
π€ Output:
Input: 101101 Output: Decimal equivalent: 45 Input: 1111 Output: Decimal equivalent: 15 Input: 0 Output: Decimal equivalent: 0 Input: 10000000 Output: Decimal equivalent: 128 Input: 1 Output: Decimal equivalent: 1
#include <stdio.h>
#include <stdlib.h>
void decimalToBinary(int n) {
if (n > 0) {
decimalToBinary(n / 2);
printf("%d", n % 2);
}
}
int main() {
int decimal;
printf("Enter a decimal number: ");
scanf("%d", &decimal);
printf("Binary equivalent: ");
if(decimal == 0){
printf("0");
} else {
decimalToBinary(decimal);
}
printf("n");
return 0;
}
π€ Output:
Input: 10 Output: Enter a decimal number: Binary equivalent: 1010 Input: 0 Output: Enter a decimal number: Binary equivalent: 0 Input: 25 Output: Enter a decimal number: Binary equivalent: 11001 Input: 128 Output: Enter a decimal number: Binary equivalent: 10000000 Input: 1 Output: Enter a decimal number: Binary equivalent: 1
#include <stdio.h>
int sumOfDigits(int num) {
int sum = 0;
while (num != 0) {
sum += num % 10;
num /= 10;
}
return sum;
}
int main() {
int number;
printf("Enter a positive integer: ");
scanf("%d", &number);
if (number < 0) {
printf("Please enter a positive integer.n");
return 1;
}
int sum = sumOfDigits(number);
printf("Sum of digits of %d is %dn", number, sum);
return 0;
}
π€ Output:
Input: 12345 Output: Enter a positive integer: Sum of digits of 12345 is 15 Input: 5 Output: Enter a positive integer: Sum of digits of 5 is 5 Input: 999 Output: Enter a positive integer: Sum of digits of 999 is 27 Input: -10 Output: Enter a positive integer: Please enter a positive integer.
#include <stdio.h>
int reverseNumber(int num) {
int reversed = 0;
while (num != 0) {
int remainder = num % 10;
reversed = reversed * 10 + remainder;
num /= 10;
}
return reversed;
}
int main() {
int number;
printf("Enter an integer: ");
scanf("%d", &number);
int reversedNumberResult = reverseNumber(number);
printf("Reversed Number: %dn", reversedNumberResult);
return 0;
}
π€ Output:
Input: 12345 Output: Reversed Number: 54321 Input: 100 Output: Reversed Number: 1 Input: -123 Output: Reversed Number: -321 Input: 0 Output: Reversed Number: 0
#include <stdio.h>
void printFibonacci(int n) {
int first = 0, second = 1, next;
printf("Fibonacci Series: ");
for (int i = 0; i < n; i++) {
printf("%d ", first);
next = first + second;
first = second;
second = next;
}
printf("n");
}
int main() {
int num;
printf("Enter the number of terms for Fibonacci Series: ");
scanf("%d", &num);
printFibonacci(num);
return 0;
}
π€ Output:
Input: 10 Output: Enter the number of terms for Fibonacci Series: Fibonacci Series: 0 1 1 2 3 5 8 13 21 34
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