C Programming Language || Hands On Coding
Hands-on C programming language challenges for beginners. Learn building logic by solving programs. Owner: @Pradeep_saii
Show moreπ Analytical overview of Telegram channel C Programming Language || Hands On Coding
Channel C Programming Language || Hands On Coding (@c_programming_language_coding) in the English language segment is an active participant. Currently, the community unites 12 822 subscribers, ranking 9 562 in the Technologies & Applications category and 31 207 in the India region.
π Audience metrics and dynamics
Since its creation on Π½Π΅Π²ΡΠ΄ΠΎΠΌΠΎ, the project has demonstrated rapid growth, gathering an audience of 12 822 subscribers.
According to the latest data from 26 August, 2026, the channel demonstrates stable activity. Although there has been a change in the number of participants by -210 over the last 30 days and by -2 over the last 24 hours, overall reach remains high.
- Verification status: Not verified
- Engagement rate (ER): The average audience engagement rate is 12.56%. Within the first 24 hours after publication, content typically collects 2.42% reactions from the total number of subscribers.
- Post reach: On average, each post receives 1 612 views. Within the first day, a publication typically gains 310 views.
- Reactions and interaction: The audience actively supports content: the average number of reactions per post is 4.
- Thematic interests: Content is focused on key topics such as input, string, scanf("%d, array, element.
π Description and content policy
The author describes the resource as a platform for expressing subjective opinions:
βHands-on C programming language challenges for beginners. Learn building logic by solving programs.
Owner: @Pradeep_saiiβ
Thanks to the high frequency of updates (latest data received on 27 August, 2026), the channel maintains relevance and a high level of publication reach. Analytics show that the audience actively interacts with content, making it an important point of influence in the Technologies & Applications category.
#include <stdio.h>
int main() {
int arr[100];
int n, i, positiveCount = 0, negativeCount = 0;
printf("Enter the number of elements in the array: ");
scanf("%d", &n);
printf("Enter the elements of the array:n");
for (i = 0; i < n; i++) {
scanf("%d", &arr[i]);
}
for (i = 0; i < n; i++) {
if (arr[i] > 0) {
positiveCount++;
} else if (arr[i] < 0) {
negativeCount++;
}
}
printf("Positive numbers: %dn", positiveCount);
printf("Negative numbers: %dn", negativeCount);
return 0;
}
π€ Output:
Input: 5 Input: 1 Input: -2 Input: 3 Input: -4 Input: 0 Output: Enter the number of elements in the array: Enter the elements of the array: Positive numbers: 2 Negative numbers: 2
#include <stdio.h>
int main() {
int arr[100];
int n, i, evenCount = 0, oddCount = 0;
printf("Enter the number of elements in the array: ");
scanf("%d", &n);
printf("Enter the elements of the array:n");
for (i = 0; i < n; i++) {
scanf("%d", &arr[i]);
}
for (i = 0; i < n; i++) {
if (arr[i] % 2 == 0) {
evenCount++;
} else {
oddCount++;
}
}
printf("Even numbers: %dn", evenCount);
printf("Odd numbers: %dn", oddCount);
return 0;
}
π€ Output:
Input: 5 Input: 1 Input: 2 Input: 3 Input: 4 Input: 5 Output: Even numbers: 2 Output: Odd numbers: 3
#include <stdio.h>
#include <limits.h>
int main() {
int n, i;
printf("Enter the number of elements in the array: ");
scanf("%d", &n);
int arr[n];
printf("Enter the elements of the array:n");
for (i = 0; i < n; i++) {
scanf("%d", &arr[i]);
}
int smallest = INT_MAX;
int secondSmallest = INT_MAX;
for (i = 0; i < n; i++) {
if (arr[i] < smallest) {
secondSmallest = smallest;
smallest = arr[i];
} else if (arr[i] < secondSmallest && arr[i] != smallest) {
secondSmallest = arr[i];
}
}
if (secondSmallest == INT_MAX) {
printf("There is no second smallest element.n");
} else {
printf("The second smallest element is: %dn", secondSmallest);
}
return 0;
}
π€ Output:
Input: 5 Input: 5 Input: 2 Input: 8 Input: 1 Input: 9 Output: The second smallest element is: 2 Input: 4 Input: 1 Input: 1 Input: 1 Input: 1 Output: There is no second smallest element. Input: 3 Input: 10 Input: 5 Input: 10 Output: The second smallest element is: 10 Input: 2 Input: 7 Input: 3 Output: The second smallest element is: 7
#include <stdio.h>
int main() {
int n, i, largest, secondLargest;
printf("Enter the number of elements in the array: ");
scanf("%d", &n);
int arr[n];
printf("Enter the elements of the array:n");
for (i = 0; i < n; i++) {
scanf("%d", &arr[i]);
}
if (n < 2) {
printf("Array should have at least two elements.n");
return 0;
}
largest = arr[0];
secondLargest = arr[1];
if (secondLargest > largest) {
int temp = largest;
largest = secondLargest;
secondLargest = temp;
}
for (i = 2; i < n; i++) {
if (arr[i] > largest) {
secondLargest = largest;
largest = arr[i];
} else if (arr[i] > secondLargest && arr[i] != largest) {
secondLargest = arr[i];
}
}
if (largest == secondLargest) {
printf("There is no second largest element as all elements are the same.n");
} else {
printf("The second largest element in the array is: %dn", secondLargest);
}
return 0;
}
π€ Output:
Input: 5 Input: 10 Input: 5 Input: 8 Input: 2 Input: 7 Output: The second largest element in the array is: 8 Input: 3 Input: 5 Input: 5 Input: 5 Output: There is no second largest element as all elements are the same. Input: 1 Output: Enter the number of elements in the array: Array should have at least two elements. Input: 2 Input: 1 Input: 2 Output: The second largest element in the array is: 1
#include <stdio.h>
int main() {
int n;
printf("Enter the number of elements: ");
scanf("%d", &n);
int arr[n];
printf("Enter the elements:n");
for (int i = 0; i < n; i++) {
scanf("%d", &arr[i]);
}
int uniqueArr[n];
int uniqueSize = 0;
for (int i = 0; i < n; i++) {
int isDuplicate = 0;
for (int j = 0; j < uniqueSize; j++) {
if (arr[i] == uniqueArr[j]) {
isDuplicate = 1;
break;
}
}
if (!isDuplicate) {
uniqueArr[uniqueSize] = arr[i];
uniqueSize++;
}
}
printf("Array with unique elements:n");
for (int i = 0; i < uniqueSize; i++) {
printf("%d ", uniqueArr[i]);
}
printf("n");
return 0;
}
π€ Output:
Input: 5 Input: 1 Input: 2 Input: 2 Input: 3 Input: 4 Output: Enter the number of elements: Enter the elements: Array with unique elements: 1 2 3 4 Input: 7 Input: 5 Input: 2 Input: 5 Input: 1 Input: 2 Input: 3 Input: 4 Output: Enter the number of elements: Enter the elements: Array with unique elements: 5 2 1 3 4
#include <stdio.h>
#include <stdbool.h>
int main() {
int n;
printf("Enter the size of the array: ");
scanf("%d", &n);
int arr[n];
printf("Enter the elements of the array: ");
for (int i = 0; i < n; i++) {
scanf("%d", &arr[i]);
}
bool isSorted = true;
for (int i = 0; i < n - 1; i++) {
if (arr[i] > arr[i + 1]) {
isSorted = false;
break;
}
}
if (isSorted) {
printf("Array is sorted.n");
} else {
printf("Array is not sorted.n");
}
return 0;
}
π€ Output:
Input: 5 Input: 1 2 3 4 5 Output: Array is sorted. Input: 5 Input: 5 4 3 2 1 Output: Array is not sorted. Input: 4 Input: 1 2 4 3 Output: Array is not sorted. Input: 3 Input: 1 1 1 Output: Array is sorted. Input: 1 Input: 10 Output: Array is sorted.
#include <stdio.h>
int main() {
int n, i, temp;
printf("Enter the number of elements in the array: ");
scanf("%d", &n);
int arr[n];
printf("Enter the elements of the array:n");
for (i = 0; i < n; i++) {
scanf("%d", &arr[i]);
}
// Reversing the array
for (i = 0; i < n / 2; i++) {
temp = arr[i];
arr[i] = arr[n - i - 1];
arr[n - i - 1] = temp;
}
printf("Reversed array: ");
for (i = 0; i < n; i++) {
printf("%d ", arr[i]);
}
printf("n");
return 0;
}
π€ Output:
Input: 5 Input: 1 Input: 2 Input: 3 Input: 4 Input: 5 Output: Enter the number of elements in the array: Enter the elements of the array: Reversed array: 5 4 3 2 1 Input: 6 Input: 10 Input: 20 Input: 30 Input: 40 Input: 50 Input: 60 Output: Enter the number of elements in the array: Enter the elements of the array: Reversed array: 60 50 40 30 20 10
#include <stdio.h>
int main() {
int n, i;
float sum = 0.0, average;
printf("Enter the number of elements: ");
scanf("%d", &n);
float arr[n];
printf("Enter the elements:n");
for (i = 0; i < n; i++) {
scanf("%f", &arr[i]);
sum += arr[i];
}
average = sum / n;
printf("Average = %.2fn", average);
return 0;
}
π€ Output:
Input: 3 Input: 1.0 Input: 2.0 Input: 3.0 Output: Enter the number of elements: Enter the elements: Average = 2.00
#include <stdio.h>
int main() {
int n, i, sum = 0;
printf("Enter the number of elements in the array: ");
scanf("%d", &n);
int arr[n];
printf("Enter the elements of the array:n");
for (i = 0; i < n; i++) {
scanf("%d", &arr[i]);
}
for (i = 0; i < n; i++) {
sum += arr[i];
}
printf("Sum of all elements in the array = %dn", sum);
return 0;
}
π€ Output:
Input: 5 Input: 1 Input: 2 Input: 3 Input: 4 Input: 5 Output: Enter the number of elements in the array: Enter the elements of the array: Sum of all elements in the array = 15
#include <stdio.h>
int main() {
int arr[5];
int smallest;
int i;
printf("Enter 5 integer elements:n");
for (i = 0; i < 5; i++) {
scanf("%d", &arr[i]);
}
smallest = arr[0];
for (i = 1; i < 5; i++) {
if (arr[i] < smallest) {
smallest = arr[i];
}
}
printf("Smallest element: %dn", smallest);
return 0;
}
π€ Output:
Input: 5 Input: 2 Input: 8 Input: 1 Input: 9 Output: Enter 5 integer elements: Output: Smallest element: 1
#include <stdio.h>
int main() {
int n;
printf("Enter the number of elements in the array: ");
scanf("%d", &n);
int arr[n];
printf("Enter the elements of the array:n");
for (int i = 0; i < n; i++) {
scanf("%d", &arr[i]);
}
int largest = arr[0];
for (int i = 1; i < n; i++) {
if (arr[i] > largest) {
largest = arr[i];
}
}
printf("The largest element in the array is: %dn", largest);
return 0;
}
π€ Output:
Input: 5 Input: 12 Input: 5 Input: 28 Input: 3 Input: 19 Output: Enter the number of elements in the array: Enter the elements of the array: The largest element in the array is: 28
#include <stdio.h>
int sum_natural(int n) {
if (n == 0) {
return 0;
} else {
return n + sum_natural(n - 1);
}
}
int main() {
int num;
printf("Enter a positive integer: ");
scanf("%d", &num);
if (num < 0) {
printf("Please enter a non-negative integer.n");
} else {
int sum = sum_natural(num);
printf("Sum of natural numbers up to %d = %dn", num, sum);
}
return 0;
}
π€ Output:
Input: 5 Output: Enter a positive integer: Sum of natural numbers up to 5 = 15 Input: 0 Output: Enter a positive integer: Sum of natural numbers up to 0 = 0 Input: -3 Output: Enter a positive integer: Please enter a non-negative integer.
#include <stdio.h>
void increment(int *n) {
*n = *n + 1;
}
int main() {
int num = 10;
printf("Before increment: %dn", num);
increment(&num);
printf("After increment: %dn", num);
return 0;
}
π€ Output:
Before increment: 10 After increment: 11
#include <stdio.h>
void modifyValue(int x) {
x = x + 10;
printf("Value inside function: %dn", x);
}
int main() {
int num;
printf("Enter an integer: ");
scanf("%d", &num);
printf("Value before function call: %dn", num);
modifyValue(num);
printf("Value after function call: %dn", num);
return 0;
}
π€ Output:
Input: 5 Output: Enter an integer: Value before function call: 5 Value inside function: 15 Value after function call: 5
#include <stdio.h>
int factorial(int n) {
int fact = 1;
for (int i = 1; i <= n; i++) {
fact *= i;
}
return fact;
}
int isStrong(int num) {
int originalNum = num;
int sum = 0;
while (num > 0) {
int digit = num % 10;
sum += factorial(digit);
num /= 10;
}
if (sum == originalNum) {
return 1;
} else {
return 0;
}
}
int main() {
int number;
printf("Enter a number: ");
scanf("%d", &number);
if (isStrong(number)) {
printf("%d is a strong number.n", number);
} else {
printf("%d is not a strong number.n", number);
}
return 0;
}
π€ Output:
Input: 145 Output: 145 is a strong number. Input: 123 Output: 123 is not a strong number. Input: 40585 Output: 40585 is a strong number.
#include <stdio.h>
int isPerfect(int num) {
int sum = 1;
for (int i = 2; i * i <= num; i++) {
if (num % i == 0) {
if (i * i != num)
sum = sum + i + num / i;
else
sum = sum + i;
}
}
if (sum == num && num != 1)
return 1; // True
else
return 0; // False
}
int main() {
int number;
printf("Enter a number: ");
scanf("%d", &number);
if (isPerfect(number)) {
printf("%d is a perfect numbern", number);
} else {
printf("%d is not a perfect numbern", number);
}
return 0;
}
π€ Output:
Input: 6 Output: 6 is a perfect number Input: 28 Output: 28 is a perfect number Input: 12 Output: 12 is not a perfect number Input: 496 Output: 496 is a perfect number Input: 8128 Output: 8128 is a perfect number Input: 1 Output: 1 is not a perfect number Input: 0 Output: 0 is not a perfect number Input: -1 Output: -1 is not a perfect number
#include <stdio.h>
#include <math.h>
int binaryToDecimal(long long n) {
int decimalNumber = 0, i = 0, remainder;
while (n!=0) {
remainder = n % 10;
n /= 10;
decimalNumber += remainder * pow(2, i);
++i;
}
return decimalNumber;
}
int main() {
long long n;
printf("Enter a binary number: ");
scanf("%lld", &n);
printf("Decimal equivalent: %d", binaryToDecimal(n));
return 0;
}
π€ Output:
Input: 101101 Output: Decimal equivalent: 45 Input: 1111 Output: Decimal equivalent: 15 Input: 0 Output: Decimal equivalent: 0 Input: 10000000 Output: Decimal equivalent: 128 Input: 1 Output: Decimal equivalent: 1
#include <stdio.h>
#include <stdlib.h>
void decimalToBinary(int n) {
if (n > 0) {
decimalToBinary(n / 2);
printf("%d", n % 2);
}
}
int main() {
int decimal;
printf("Enter a decimal number: ");
scanf("%d", &decimal);
printf("Binary equivalent: ");
if(decimal == 0){
printf("0");
} else {
decimalToBinary(decimal);
}
printf("n");
return 0;
}
π€ Output:
Input: 10 Output: Enter a decimal number: Binary equivalent: 1010 Input: 0 Output: Enter a decimal number: Binary equivalent: 0 Input: 25 Output: Enter a decimal number: Binary equivalent: 11001 Input: 128 Output: Enter a decimal number: Binary equivalent: 10000000 Input: 1 Output: Enter a decimal number: Binary equivalent: 1
#include <stdio.h>
int sumOfDigits(int num) {
int sum = 0;
while (num != 0) {
sum += num % 10;
num /= 10;
}
return sum;
}
int main() {
int number;
printf("Enter a positive integer: ");
scanf("%d", &number);
if (number < 0) {
printf("Please enter a positive integer.n");
return 1;
}
int sum = sumOfDigits(number);
printf("Sum of digits of %d is %dn", number, sum);
return 0;
}
π€ Output:
Input: 12345 Output: Enter a positive integer: Sum of digits of 12345 is 15 Input: 5 Output: Enter a positive integer: Sum of digits of 5 is 5 Input: 999 Output: Enter a positive integer: Sum of digits of 999 is 27 Input: -10 Output: Enter a positive integer: Please enter a positive integer.
